Computer Systems: A Programmer's Perspective Plus Mastering Engineering With Pearson Etext -- Access Card Package (3rd Edition)
Computer Systems: A Programmer's Perspective Plus Mastering Engineering With Pearson Etext -- Access Card Package (3rd Edition)
3rd Edition
ISBN: 9780134123837
Author: Randal E. Bryant, David R. O'Hallaron
Publisher: PEARSON
Expert Solution & Answer
Book Icon
Chapter 3.7, Problem 3.35PP

A.

Explanation of Solution

Given assembly code:

x in %rdi

rfun:

pushq %rbx

movq %rdi, %rbx

movl $0, %eax

testq %rdi, %rdi

je .L2

shrq $2, %rdi

call rfun

addq %rbx, %rax

.L2:

popq %rbx

ret

Data movement instructions:

  • The different instructions are been grouped as “instruction classes”.
  • The instructions in a class performs same operation but with different sizes of operand.
  • The “Mov” class denotes data movement instructions that copy data from a source location to a destination.
  • The class has 4 instructions that includes:
    • movb:
      • It copies data from a source location to a destination.
      • It denotes an instruction that operates on 1 byte data size.
    • movw:
      • It copies data from a source location to a destination.
      • It denotes an instruction that operates on 2 bytes data size.
    • movl:
      • It copies data from a source location to a destination.
      • It denotes an instruction that operates on 4 bytes data size.
    • movq:
      • It copies data from a source location to a destination.
      • It denotes an instruction that operates on 8 bytes data size.

Unary and Binary Operations:

  • The details of unary operations includes:
    • The single operand functions as both source as well as destination.
    • It can either be a memory location or a register.
    • The instruction “incq” causes 8 byte element on stack top to be incremented...

B.

Explanation of Solution

Corresponding C code:

// Define method rfun

long rfun(unsigned long x)

{

//If x equals 0

if(x==0)

//Return 0

return 0;

//Assign value after right shit

unsigned long nx = x>>2;

//Call method

long rv = rfun(nx);

//Return value

return x+rv;

}

Explanation:

  • The register “%rdi” stores value of “x”.
  • The instruction “pushq” stores the data.
  • The instruction “movq %rdi, %rbx” saves value of register “%rdi” on “%rbx”.
  • The instruction “movl $0, %eax” saves 0 in variable “%eax”.
  • The instruction “testq %rdi, %rdi” checks whether value in register “%rdi” is zero.
    • The statement “if(x==0)” is corresponding to C statement...

Blurred answer
Students have asked these similar questions
make corrections of this program based on the errors shown. this is CIS 227 .
Create 6 users: Don, Liz, Shamir, Jose, Kate, and Sal. Create 2 groups: marketing and research. Add Shamir, Jose, and Kate to the marketing group. Add Don, Liz, and Sal to the research group. Create a shared directory for each group. Create two files to put into each directory: spreadsheetJanuary.txt meetingNotes.txt Assign access permissions to the directories:  Groups should have Read+Write access Leave owner permissions as they are  “Everyone else” should not have any access   Submit for grade: Screenshot of  /etc/passwd contents showing your new users Screenshot of /etc/group contents showing new groups with their members Screenshot of shared directories you created with files and permissions
⚫ your circuit diagrams for your basic bricks, such as AND, OR, XOR gates and 1 bit multiplexers, ⚫ your circuit diagrams for your extended full adder, designed in Section 1 and ⚫ your circuit diagrams for your 8-bit arithmetical-logical unit, designed in Section 2. 1 An Extended Full Adder In this Section, we are going to design an extended full adder circuit (EFA). That EFA takes 6 one bit inputs: aj, bj, Cin, Tin, t₁ and to. Depending on the four possible combinations of values on t₁ and to, the EFA produces 3 one bit outputs: sj, Cout and rout. The EFA can be specified in principle by a truth table with 26 = 64 entries and 3 outputs. However, as the EFA ignores certain inputs in certain cases, it is easier to work with the following overview specification, depending only on t₁ and to in the first place: t₁ to Description 00 Output Relationship Ignored Inputs Addition Mode 2 Coutsjaj + bj + Cin, Tout= 0 Tin 0 1 Shift Left Mode Sj = Cin, Cout=bj, rout = 0 rin, aj 10 1 1 Shift Right…

Chapter 3 Solutions

Computer Systems: A Programmer's Perspective Plus Mastering Engineering With Pearson Etext -- Access Card Package (3rd Edition)

Ch. 3.5 - Prob. 3.11PPCh. 3.5 - Prob. 3.12PPCh. 3.6 - Prob. 3.13PPCh. 3.6 - Prob. 3.14PPCh. 3.6 - Prob. 3.15PPCh. 3.6 - Prob. 3.16PPCh. 3.6 - Practice Problem 3.17 (solution page 331) An...Ch. 3.6 - Practice Problem 3.18 (solution page 332) Starting...Ch. 3.6 - Prob. 3.19PPCh. 3.6 - Prob. 3.20PPCh. 3.6 - Prob. 3.21PPCh. 3.6 - Prob. 3.22PPCh. 3.6 - Prob. 3.23PPCh. 3.6 - Practice Problem 3.24 (solution page 335) For C...Ch. 3.6 - Prob. 3.25PPCh. 3.6 - Prob. 3.26PPCh. 3.6 - Practice Problem 3.27 (solution page 336) Write...Ch. 3.6 - Prob. 3.28PPCh. 3.6 - Prob. 3.29PPCh. 3.6 - Practice Problem 3.30 (solution page 338) In the C...Ch. 3.6 - Prob. 3.31PPCh. 3.7 - Prob. 3.32PPCh. 3.7 - Prob. 3.33PPCh. 3.7 - Prob. 3.34PPCh. 3.7 - Prob. 3.35PPCh. 3.8 - Prob. 3.36PPCh. 3.8 - Prob. 3.37PPCh. 3.8 - Prob. 3.38PPCh. 3.8 - Prob. 3.39PPCh. 3.8 - Prob. 3.40PPCh. 3.9 - Prob. 3.41PPCh. 3.9 - Prob. 3.42PPCh. 3.9 - Practice Problem 3.43 (solution page 344) Suppose...Ch. 3.9 - Prob. 3.44PPCh. 3.9 - Prob. 3.45PPCh. 3.10 - Prob. 3.46PPCh. 3.10 - Prob. 3.47PPCh. 3.10 - Prob. 3.48PPCh. 3.10 - Prob. 3.49PPCh. 3.11 - Practice Problem 3.50 (solution page 347) For the...Ch. 3.11 - Prob. 3.51PPCh. 3.11 - Prob. 3.52PPCh. 3.11 - Practice Problem 3.52 (solution page 348) For the...Ch. 3.11 - Practice Problem 3.54 (solution page 349) Function...Ch. 3.11 - Prob. 3.55PPCh. 3.11 - Prob. 3.56PPCh. 3.11 - Practice Problem 3.57 (solution page 350) Function...Ch. 3 - For a function with prototype long decoda2(long x,...Ch. 3 - The following code computes the 128-bit product of...Ch. 3 - Prob. 3.60HWCh. 3 - In Section 3.6.6, we examined the following code...Ch. 3 - The code that follows shows an example of...Ch. 3 - This problem will give you a chance to reverb...Ch. 3 - Consider the following source code, where R, S,...Ch. 3 - The following code transposes the elements of an M...Ch. 3 - Prob. 3.66HWCh. 3 - For this exercise, we will examine the code...Ch. 3 - Prob. 3.68HWCh. 3 - Prob. 3.69HWCh. 3 - Consider the following union declaration: This...Ch. 3 - Prob. 3.71HWCh. 3 - Prob. 3.72HWCh. 3 - Prob. 3.73HWCh. 3 - Prob. 3.74HWCh. 3 - Prob. 3.75HW
Knowledge Booster
Background pattern image
Similar questions
SEE MORE QUESTIONS
Recommended textbooks for you
Text book image
C++ for Engineers and Scientists
Computer Science
ISBN:9781133187844
Author:Bronson, Gary J.
Publisher:Course Technology Ptr
Text book image
C++ Programming: From Problem Analysis to Program...
Computer Science
ISBN:9781337102087
Author:D. S. Malik
Publisher:Cengage Learning
Text book image
COMPREHENSIVE MICROSOFT OFFICE 365 EXCE
Computer Science
ISBN:9780357392676
Author:FREUND, Steven
Publisher:CENGAGE L