LIFE: THE SCIENCE OF BIOLOGY
11th Edition
ISBN: 9781319145125
Author: Sadava
Publisher: MAC HIGHER
expand_more
expand_more
format_list_bulleted
Concept explainers
Videos
Question
Chapter 36.2, Problem 3R
Summary Introduction
To review:
Two experiments to test the hypothesis that bacterium corn stunt spiroplasma inhibits gibberellin synthesis in corn plants.
Introduction:
The bacterium corn stunt spiroplasma infects corn plants and causes a significant reduction in the growth of plant leading to dwarf plants. These plants appear similar to a genetically dwarf corn plant. It was hypothesized that the bacterium inhibits gibberellin synthesis in plants.
Expert Solution & Answer
Want to see the full answer?
Check out a sample textbook solution
Students have asked these similar questions
*Example 2: Tracing the path of an autosomal dominant trait
Trait: Neurofibromatosis
Forms of the trait:
The dominant form is neurofibromatosis, caused by the production of an abnormal form of the protein
neurofibromin. Affected individuals show spots of abnormal skin pigmentation and non-cancerous
tumors that can interfere with the nervous system and cause blindness. Some tumors can convert to a
cancerous form. i
The recessive form is a normal protein - in other words, no neurofibromatosis.moovi
A typical pedigree for a family that carries neurofibromatosis is shown below. Note that carriers are not
indicated with half-colored shapes in this chart. Use the letter "N" to indicate the dominant neurofibromatosis
allele, and the letter "n" for the normal allele.
Nn
nn
nn
2
nn
Nn
A
3
N-
I want to be a super nutrition guy what u guys like recommend me
Please finish the chart at the bottom. Some of the answers have been filled in.
Chapter 36 Solutions
LIFE: THE SCIENCE OF BIOLOGY
Knowledge Booster
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, biology and related others by exploring similar questions and additional content below.Similar questions
- 9. Aerobic respiration of one lipid molecule. The lipid is composed of one glycerol molecule connected to two fatty acid tails. One fatty acid is 12 carbons long and the other fatty acid is 18 carbons long in the figure below. Use the information below to determine how much ATP will be produced from the glycerol part of the lipid. Then, in part B, determine how much ATP is produced from the 2 fatty acids of the lipid. Finally put the NADH and ATP yields together from the glycerol and fatty acids (part A and B) to determine your total number of ATP produced per lipid. Assume no other carbon source is available. 18 carbons fatty acids 12 carbons 9 glycerol A. Glycerol is broken down to glyceraldehyde 3-phosphate, a glycolysis intermediate via the following pathway shown in the figure below. Notice this process costs one ATP but generates one FADH2. Continue generating ATP with glyceraldehyde-3-phosphate using the standard pathway and aerobic respiration. glycerol glycerol-3- phosphate…arrow_forwardNormal dive (for diving humans) normal breathing dive normal breathing Oz level CO2 level urgent need to breathe Oz blackout zone high CO2 triggers breathing 6. This diagram shows rates of oxygen depletion and carbon dioxide accumulation in the blood in relation to the levels needed to maintain consciousness and trigger the urgent need to breathe in diving humans. How might the location and slope of the O₂ line differ for diving marine mammals such as whales and dolphins? • How might the location and slope of the CO₂ line differ for diving marine mammals such as whales and dolphins? • • Draw in predicted lines for O2 and CO2, based on your reasoning above. How might the location of the Urgent Need to Breathe line and the O2 Blackout Zone line differ for diving marine mammals? What physiological mechanisms account for each of these differences, resulting in the ability of marine mammals to stay submerged for long periods of time?arrow_forwardforaging/diet type teeth tongue stomach intestines cecum Insectivory numerous, spiky, incisors procumbentExample: moleExample: shrew -- simple short mostly lacking Myrmecophagy absent or reduced in numbers, peg-likeExample: tamandua anteater extremely long simple, often roughened short small or lacking Terrestrial carnivory sharp incisors; long, conical canines; often carnassial cheek teeth; may have crushing molarsExample: dog -- simple short small Aquatic carnivory homodont, spiky, numerousExample: common dolphin -- simple or multichambered (cetaceans only) variable small or absent Sanguinivory very sharp upper incisors; reduced cheek teethExample: vampire bat grooved tubular, highly extensible long small or lacking Herbivory (except nectivores) incisors robust or absent; canines reduced or absent; diastema; cheek teeth enlarged with complex occlusal surfacesExample: beaver -- simple (hindgut fermenters) or multichambered (ruminants) long large Filter feeding none…arrow_forward
- 3. Shown below is the dental formula and digestive tract anatomy of three mammalian species (A, B, and C). What kind of diet would you expect each species to have? Support your answers with what you can infer from the dental formula and what you can see in the diagram. Broadly speaking, what accounts for the differences? Species A 3/3, 1/1, 4/4, 3/3 པར『ན་ cm 30 Species B 4/3, 1/1, 2/2, 4/4 cm 10 Species C 0/4, 0/0,3/3, 3/3 020arrow_forward3. Shown below is the dental formula and digestive tract anatomy of three mammalian species (A, B, and C). What kind of diet would you expect each species to have? Support your answers with what you can infer from the dental formula and what you can see in the diagram. Broadly speaking, what accounts for the differences? Species A 3/3, 1/1, 4/4, 3/3 cm 30 Species B 0/4, 0/0, 3/3, 3/3 cm 10 Species C 4/3, 1/1, 2/2, 4/4 E 0 cm 20 AILarrow_forwardNormal dive (for diving humans) normal breathing dive normal breathing Oz level CO₂ level urgent need to breathe Oz blackout zone high CO₂ triggers breathing 6. This diagram shows rates of oxygen depletion and carbon dioxide accumulation in the blood in relation to the levels needed to maintain consciousness and trigger the urgent need to breathe in diving humans. • How might the location and slope of the O2 line differ for diving marine mammals such as whales and dolphins? • How might the location and slope of the CO2 line differ for diving marine mammals such as whales and dolphins? • • Draw in predicted lines for O2 and CO2, based on your reasoning above. How might the location of the Urgent Need to Breathe line and the O2 Blackout Zone line differ for diving marine mammals? What physiological mechanisms account for each of these differences, resulting in the ability of marine mammals to stay submerged for long periods of time?arrow_forward
- How much ATP will be produced during the following metabolic scenario: Aerobic respiration of a 5mM lipid solution that is made up of one glycerol and an 8-carbon fatty acid and 12-carbon fatty acid. Recall that when glycerol breaks down to Glyceraldehyde-3-phosphate it costs one ATP but your get an extra FADH2. Every two carbons of a fatty acid break down to one acetyl-CoA. Units cannot be entered in this style of question but the units of your answer should be in mM of ATP.arrow_forwardIf a bacterium using aerobic respiration was to degrade one small protein molecule into 8 molecules of pyruvic acid, how many ATP would that cell make? Assume there is no other carbon source. Units cannot be entered in this style of question but the units of your answer should be in molecules of ATP.arrow_forwardIf a bacterium using aerobic respiration was to degrade a 30 mM solution of citric acid, how many ATP would that cell make? Assume no other carbon source is available. Units cannot be entered in this style of question but the units of your answer should be in mM of ATP.arrow_forward
- How much ATP will be produced during the following metabolic scenario: Aerobic respiration of a 5mM lipid solution that is made up of one glycerol and an 8-carbon fatty acid and 12-carbon fatty acid. Recall that when glycerol breaks down to Glyceraldehyde-3-phosphate it costs one ATP but your get an extra FADH2. Every two carbons of a fatty acid break down to one acetyl-CoA. (pathways will be provided on the exam) Units cannot be entered in this style of question but the units of your answer should be in mM of ATP.arrow_forwardWhen beta-lactamase was isolated from Staphylcoccus aureus and treated with a phosphorylating agent, only the active site, serine was phosphorylated. Additionally, the serine was found to constitute 0.35% (by weight) of this beta-lactamase enzyme. Using this, calculate the molecular weight of this enzyme and estimate the number of amino acids present in the polypeptide.arrow_forwardBased on your results from the Mannitol Salt Agar (MSA) media, which of your bacteria were mannitol fermenters and which were not mannitol fermenters?arrow_forward
arrow_back_ios
SEE MORE QUESTIONS
arrow_forward_ios
Recommended textbooks for you
- Basic Clinical Lab Competencies for Respiratory C...NursingISBN:9781285244662Author:WhitePublisher:Cengage
Human Heredity: Principles and Issues (MindTap Co...BiologyISBN:9781305251052Author:Michael CummingsPublisher:Cengage Learning
BiochemistryBiochemistryISBN:9781305577206Author:Reginald H. Garrett, Charles M. GrishamPublisher:Cengage Learning
Basic Clinical Lab Competencies for Respiratory C...
Nursing
ISBN:9781285244662
Author:White
Publisher:Cengage
Human Heredity: Principles and Issues (MindTap Co...
Biology
ISBN:9781305251052
Author:Michael Cummings
Publisher:Cengage Learning
Biochemistry
Biochemistry
ISBN:9781305577206
Author:Reginald H. Garrett, Charles M. Grisham
Publisher:Cengage Learning
cell culture and growth media for Microbiology; Author: Scientist Cindy;https://www.youtube.com/watch?v=EjnQ3peWRek;License: Standard YouTube License, CC-BY