In conventional television, signals are broadcast from towers to home receivers. Even when a receiver is not in direct view of tower because of a hill or building, it can still intercept a signal if the signal diffracts enough around the obstacle, into the obstacle’s “shadow region.” Previously, television signals had a wavelength of about 50 cm, but digital television signals that are transmitted from towers have a wavelength of about 10 mm. (a) Did this change in wavelength increase or decrease the diffraction of the signals into the shadow regions of obstacles? Assume that a signal passes through an opening of 5.0 m width between two adjacent buildings. What is the angular spread of the central diffraction maximum (out to the first minima) for wavelengths of (b) 50 cm and (c) 10 mm?
In conventional television, signals are broadcast from towers to home receivers. Even when a receiver is not in direct view of tower because of a hill or building, it can still intercept a signal if the signal diffracts enough around the obstacle, into the obstacle’s “shadow region.” Previously, television signals had a wavelength of about 50 cm, but digital television signals that are transmitted from towers have a wavelength of about 10 mm. (a) Did this change in wavelength increase or decrease the diffraction of the signals into the shadow regions of obstacles? Assume that a signal passes through an opening of 5.0 m width between two adjacent buildings. What is the angular spread of the central diffraction maximum (out to the first minima) for wavelengths of (b) 50 cm and (c) 10 mm?
In conventional television, signals are broadcast from towers to home receivers. Even when a receiver is not in direct view of tower because of a hill or building, it can still intercept a signal if the signal diffracts enough around the obstacle, into the obstacle’s “shadow region.” Previously, television signals had a wavelength of about 50 cm, but digital television signals that are transmitted from towers have a wavelength of about 10 mm. (a) Did this change in wavelength increase or decrease the diffraction of the signals into the shadow regions of obstacles? Assume that a signal passes through an opening of 5.0 m width between two adjacent buildings. What is the angular spread of the central diffraction maximum (out to the first minima) for wavelengths of (b) 50 cm and (c) 10 mm?
A cab driver heads south with a steady speed of v₁ = 20.0 m/s for t₁ = 3.00 min, then makes a right turn and travels at v₂ = 25.0 m/s for t₂ = 2.80 min, and then drives northwest at v3 = 30.0 m/s for t3 = 1.00 min. For this 6.80-min trip, calculate the following.
Assume +x is in the eastward direction.
(a) total vector displacement (Enter the magnitude in m and the direction in degrees south of west.)
magnitude
direction
For each straight-line movement, model the car as a particle under constant velocity, and draw a diagram of the displacements, labeling the distances and angles. Let the starting point be the origin of your coordinate system. Use the relationship
speed = distance/time to find the distances traveled during each segment. Write the displacement vector, and calculate its magnitude and direction. Don't forget to convert min to s! m
Model the car as a particle under constant velocity, and draw a diagram of the displacements, labeling the distances and angles. Let the…
î
A proton is projected in the positive x direction into a region of uniform electric field E = (-5.50 x 105) i N/C at t = 0. The
proton travels 7.20 cm as it comes to rest.
(a) Determine the acceleration of the proton.
magnitude 5.27e13
direction -X
m/s²
(b) Determine the initial speed of the proton.
8.71e-6
magnitude The electric field is constant, so the force is constant, which means the acceleration will be constant.
m/s
direction +X
(c) Determine the time interval over which the proton comes to rest.
1.65e-7
Review you equations for constant accelerated motion. s
Three charged particles are at the corners of an equilateral triangle as shown in the figure below. (Let q = 2.00 μC, and
L = 0.750 m.)
y
7.00 με
60.0°
L
9
-4.00 μC
x
(a) Calculate the electric field at the position of charge q due to the 7.00-μC and -4.00-μC charges.
112
Once you calculate the magnitude of the field contribution from each charge you need to add these as vectors.
KN/CI + 64
×
Think carefully about the direction of the field due to the 7.00-μC charge. KN/Cĵ
(b) Use your answer to part (a) to determine the force on charge q.
240.0
If you know the electric field at a particular point, how do you find the force that acts on a charge at that point? mN
Î + 194.0
×
If you know the electric field at a particular point, how do you find the force that acts on a charge at that point? mN
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