Physics for Scientists and Engineers With Modern Physics
9th Edition
ISBN: 9781133953982
Author: SERWAY, Raymond A./
Publisher: Cengage Learning
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Chapter 36, Problem 45P
A converging lens has a focal length of 10.0 cm. Locate the object if a real image is located at a distance from the lens of (a) 20.0 cm and (b) 50.0 cm. What If? Redo the calculations if the images are virtual and located at a distance from the lens of (c) 20.0 cm and (d) 50.0 cm.
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Chapter 36 Solutions
Physics for Scientists and Engineers With Modern Physics
Ch. 36.1 - Prob. 36.1QQCh. 36.2 - You wish to start a fire by reflecting sunlight...Ch. 36.2 - Consider the image in the mirror in Figure 35.14....Ch. 36.3 - Prob. 36.4QQCh. 36.3 - Prob. 36.5QQCh. 36.4 - What is the focal length of a pane of window...Ch. 36.6 - Prob. 36.7QQCh. 36.7 - Prob. 36.8QQCh. 36 - Prob. 1OQCh. 36 - Prob. 2OQ
Ch. 36 - Prob. 3OQCh. 36 - Prob. 4OQCh. 36 - Prob. 5OQCh. 36 - Prob. 6OQCh. 36 - Prob. 7OQCh. 36 - Prob. 8OQCh. 36 - Prob. 9OQCh. 36 - Prob. 10OQCh. 36 - Prob. 11OQCh. 36 - Prob. 12OQCh. 36 - Prob. 13OQCh. 36 - Prob. 14OQCh. 36 - Prob. 1CQCh. 36 - Prob. 2CQCh. 36 - Prob. 3CQCh. 36 - Prob. 4CQCh. 36 - Prob. 5CQCh. 36 - Explain why a fish in a spherical goldfish bowl...Ch. 36 - Prob. 7CQCh. 36 - Prob. 8CQCh. 36 - Prob. 9CQCh. 36 - Prob. 10CQCh. 36 - Prob. 11CQCh. 36 - Prob. 12CQCh. 36 - Prob. 13CQCh. 36 - Prob. 14CQCh. 36 - Prob. 15CQCh. 36 - Prob. 16CQCh. 36 - Prob. 17CQCh. 36 - Prob. 1PCh. 36 - Prob. 2PCh. 36 - (a) Does your bathroom mirror show you older or...Ch. 36 - Prob. 4PCh. 36 - Prob. 5PCh. 36 - Two flat mirrors have their reflecting surfaces...Ch. 36 - Prob. 7PCh. 36 - Prob. 8PCh. 36 - Prob. 9PCh. 36 - Prob. 10PCh. 36 - A convex spherical mirror has a radius of...Ch. 36 - Prob. 12PCh. 36 - An object of height 2.00 cm is placed 30.0 cm from...Ch. 36 - Prob. 14PCh. 36 - Prob. 15PCh. 36 - Prob. 16PCh. 36 - Prob. 17PCh. 36 - Prob. 18PCh. 36 - (a) A concave spherical mirror forms an inverted...Ch. 36 - Prob. 20PCh. 36 - Prob. 21PCh. 36 - A concave spherical mirror has a radius of...Ch. 36 - Prob. 23PCh. 36 - Prob. 24PCh. 36 - Prob. 25PCh. 36 - Prob. 26PCh. 36 - Prob. 27PCh. 36 - Prob. 28PCh. 36 - One end of a long glass rod (n = 1.50) is formed...Ch. 36 - Prob. 30PCh. 36 - Prob. 31PCh. 36 - Prob. 32PCh. 36 - Prob. 33PCh. 36 - Prob. 34PCh. 36 - Prob. 35PCh. 36 - Prob. 36PCh. 36 - Prob. 37PCh. 36 - Prob. 38PCh. 36 - Prob. 39PCh. 36 - Prob. 40PCh. 36 - Prob. 41PCh. 36 - An objects distance from a converging lens is 5.00...Ch. 36 - Prob. 43PCh. 36 - Prob. 44PCh. 36 - A converging lens has a focal length of 10.0 cm....Ch. 36 - Prob. 46PCh. 36 - Prob. 47PCh. 36 - Prob. 48PCh. 36 - Prob. 49PCh. 36 - Prob. 50PCh. 36 - Prob. 51PCh. 36 - Prob. 52PCh. 36 - Prob. 53PCh. 36 - Prob. 54PCh. 36 - Prob. 55PCh. 36 - Prob. 56PCh. 36 - Prob. 57PCh. 36 - Prob. 58PCh. 36 - Prob. 59PCh. 36 - Prob. 60PCh. 36 - Prob. 61PCh. 36 - Prob. 62PCh. 36 - Prob. 63PCh. 36 - A simple model of the human eye ignores its lens...Ch. 36 - Prob. 65PCh. 36 - Prob. 66PCh. 36 - Prob. 67PCh. 36 - Prob. 68PCh. 36 - Prob. 69PCh. 36 - Prob. 70PCh. 36 - Prob. 71APCh. 36 - Prob. 72APCh. 36 - Prob. 73APCh. 36 - The distance between an object and its upright...Ch. 36 - Prob. 75APCh. 36 - Prob. 76APCh. 36 - Prob. 77APCh. 36 - Prob. 78APCh. 36 - Prob. 79APCh. 36 - Prob. 80APCh. 36 - Prob. 81APCh. 36 - In many applications, it is necessary to expand or...Ch. 36 - Prob. 83APCh. 36 - Prob. 84APCh. 36 - Two lenses made of kinds of glass having different...Ch. 36 - Prob. 86APCh. 36 - Prob. 87APCh. 36 - Prob. 88APCh. 36 - Prob. 89APCh. 36 - Prob. 90APCh. 36 - Prob. 91APCh. 36 - Prob. 92APCh. 36 - Prob. 93CPCh. 36 - A zoom lens system is a combination of lenses that...Ch. 36 - Prob. 95CPCh. 36 - Prob. 96CPCh. 36 - Prob. 97CP
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- Find the ratio of the diameter of silver to iron wire, if they have the same resistance per unit length (as they might in household wiring). d. Ag dFe = 2.47 ×arrow_forwardFind the ratio of the diameter of silver to iron wire, if they have the same resistance per unit length (as they might in household wiring). d Ag = 2.51 dFe ×arrow_forwardShow that the units 1 v2/Q = 1 W, as implied by the equation P = V²/R. Starting with the equation P = V²/R, we can get an expression for a watt in terms of voltage and resistance. The units for voltage, V, are equivalent to [? v2 v2 A, are equivalent to J/C ✓ X . Therefore, 1 = 1 = 1 A V1 J/s Ω V-A X = 1 W. . The units for resistance, Q, are equivalent to ? The units for current,arrow_forward
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