Explanation Given: Function A ( t ) = − 2 cos ( 2 π 5 t ) + 2 Formula Used: Formulas of derivatives are as follows: d d x ( cos x ) = − sin x d d x ( x n ) = n x n − 1 d d x { c . f ( x ) } = c . d d x f ( x ) Calculation: It is given that adult takes about 12 breaths per minute. Thus, we have 12 breaths in 1 min 1 breath in 1 12 min Also, we know 1 min = 60 sec Thus, 1 breath&# To determine (b) To find: The derivative at t = 1 , where A ( t ) = − 2 cos ( 2 π 5 t ) + 2.

6th Edition

ISBN: 9781119399322

Author: Hughes-Hallett

Publisher: WILEY

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Question

Chapter 3.5, Problem 26P

To determine

(a)

To find:

One breathing cycle of an adult for the below function:

A(t)=−2cos(2π5t)+2

To determine

(b)

To find:

The derivative at t=1, where

A(t)=−2cos(2π5t)+2.

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Chapter 3.5, Problem 25P

Chapter 3.5, Problem 27P

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(a) To find: One breathing cycle of an adult for the below function: A ( t ) = − 2 cos ( 2 π 5 t ) + 2

Solution Summary: The author explains how one breathing cycle of an adult is of 5mathrmsec.

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(a)

To find:

One breathing cycle of an adult for the below function:

A(t)=−2cos(2π5t)+2

(b)

To find:

The derivative at t=1, where

A(t)=−2cos(2π5t)+2.

Want to see the full answer?

Chapter 3 Solutions

(a) To find: One breathing cycle of an adult for the below function: A ( t ) = − 2 cos ( 2 π 5 t ) + 2

Solution Summary: The author explains how one breathing cycle of an adult is of 5mathrmsec.

Concept explainers

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(a) To find: One breathing cycle of an adult for the below function: A(t)=−2cos(2π5t)+2

(b) To find: The derivative at t=1, where A(t)=−2cos(2π5t)+2.

Want to see the full answer?

Chapter 3 Solutions

(a)

To find:

One breathing cycle of an adult for the below function:

A(t)=−2cos(2π5t)+2

(b)

To find:

The derivative at t=1, where

A(t)=−2cos(2π5t)+2.