Explanation Given: Function f ( x ) = 3 x + cos ( 5 x ) . Formula Used: Formula of derivatives are as follows: d d x ( cos x ) = − sin x d d x ( x n ) = n x n − 1 d d x c . f ( x ) = c . d d x f ( x ) Equation of a straight line: y = m x + c ; where m is the tangent and c is constant. Calculation: Function is given as f ( x ) = 3 x + cos ( 5 x ) . Derivative of the above function is calculated as d d x ( f ( x ) ) = d d x ( 3 x + cos ( 5 x ) ) f ′ ( x ) = d d x ( 3 x ) + d d x ( cos ( 5 x ) ) f ′ ( x ) = 3 d d x ( x ) + d d x ( cos ( 5 x ) ) Let t = 5 x

6th Edition

ISBN: 9781119399322

Author: Hughes-Hallett

Publisher: WILEY

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Chapter 3.5, Problem 22P

To determine

To find line tangent to the below function.

f(x)=3x+cos(5x) at x=0

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Chapter 3.5, Problem 21P

Chapter 3.5, Problem 23P

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To find line tangent to the below function. f ( x ) = 3 x + cos ( 5 x ) at x = 0

Solution Summary: The author explains how to find line tangent to the below function. The function is given as f(x)=3x+mathrm

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To find line tangent to the below function.

f(x)=3x+cos(5x) at x=0

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Chapter 3 Solutions

To find line tangent to the below function. f ( x ) = 3 x + cos ( 5 x ) at x = 0

Solution Summary: The author explains how to find line tangent to the below function. The function is given as f(x)=3x+mathrm

Videos

To find line tangent to the below function. f(x)=3x+cos(5x) at x=0

Want to see the full answer?

Chapter 3 Solutions

To find line tangent to the below function.

f(x)=3x+cos(5x) at x=0