Explanation Given: Function f ( x ) = x 2 e − x Formula Used: Equation of line using slope-point form is given as ( y − y 1 ) = m ( x − x 1 ) where ( x 1 , y 1 ) is point of line and m is the slope of the line Calculation: Function is given as f ( x ) = x 2 e − x Let us find the point on graph where tangent is drawn Put x = 0 in f ( x ) , we get f ( 0 ) = ( 0 ) 2 e − 0 f ( 0 ) = 0 Also, slope of the line is calculated by taking the derivative of the function f ′ ( x ) = d d x ( x 2 e − x ) Using product rule of derivative, we have f ′ ( x ) = d d x ( x 2 ) × ( e − x ) + x 2 × d d x ( e − x ) f ′ ( x ) = (

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ISBN: 9781119399322

Author: Hughes-Hallett

Publisher: WILEY

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Chapter 3.4, Problem 36P

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To find the equation of tangent line to the graph of f(x)=x2e−x at the point at which x=0 and also graph the function and the tangent line.

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Chapter 3.4, Problem 35P

Chapter 3.4, Problem 37P

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Chapter 3 Solutions

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To find the equation of tangent line to the graph of f ( x ) = x 2 e − x at the point at which x = 0 and also graph the function and the tangent line.

Solution Summary: The author explains how to find the equation of tangent line to the graph of f(x)=x

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To find the equation of tangent line to the graph of f(x)=x2e−x at the point at which x=0 and also graph the function and the tangent line.

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Chapter 3 Solutions