Suppose that you have a maximum of $50 to spend on cab fare, and you need to make a round trip, both to and from a certain location. Which of the following inequalities best describes this situation?
a.
b.
c.
d.

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Chapter 3 Solutions
ALEKS 360 ACCESS CODE- PATHWAY MATH LIT
- Write an equation for the polynomial graphed below 6+ 5 + -5 -4 3 y(x) = 4 3 2 1 -1 1 1 -1 -2 -3 -4 -5 2 3 4 5arrow_forwardWrite an equation for the polynomial graphed below 5+ 4 3 1 + + + -5-4-3-2 1 13 4 5 -1 -2 -3 -4 -5+ 4 5 Q y(x) =arrow_forward1. Name the ongiewing) 2. Name five pairs of supple 3 27 and 19 form a angles 210 and 21 are complementary angies 4. m210=32 mal!= 5 mc11-72 m10= 6 m210-4x mc11=2x x= 7 m210=x m 11 =x+20; x= 12 and 213 are supplementary angles 8 ma 12 2y m13-3y-15 y= 9 m 12-y+10 m13-3y+ 10: y= 10. The measure of 212 is five times the measure of 13. Find the 213 and 214 are complementary angles, and 14 and 15 are supplementary angies 11 mc13 47 m/14- 12 m 14-78 m13- m215- m15 13 m15-135 m. 13- m.14arrow_forward
- 3. Solve the inequality, and give your answer in interval notation. - (x − 4)³ (x + 1) ≥ 0arrow_forward1. Find the formula to the polynomial at right. Show all your work. (4 points) 1- 2 3 сл 5 6 -4 -3 -2 -1 0 2 3arrow_forward2. Find the leading term (2 points): f(x) = −3x(2x − 1)²(x+3)³ -arrow_forward
- 1- √ √ √³ e³/√xdy dx 1 cy² 2- √ √² 3 y³ exy dx dy So 3- √ √sinx y dy dx 4- Jo √² Sy² dx dyarrow_forwardA building that is 205 feet tall casts a shadow of various lengths æ as the day goes by. An angle of elevation is formed by lines from the top and bottom of the building to the tip of the shadow, as de seen in the following figure. Find the rate of change of the angle of elevation when x 278 feet. dx Round to 3 decimal places. Γ X radians per footarrow_forwardFind The partial fraction decomposition for each The following 2× B) (x+3) a 3 6 X-3x+2x-6arrow_forward
- 1) Find the partial feraction decomposition for each of 5- X 2 2x+x-1 The following: 3 B) 3 X + 3xarrow_forwardUse the information in the following table to find h' (a) at the given value for a. x|f(x) g(x) f'(x) g(x) 0 0 0 4 3 1 4 4 3 0 2 7 1 2 7 3 3 1 2 9 4 0 4 5 7 h(x) = f(g(x)); a = 0 h' (0) =arrow_forwardUse the information in the following table to find h' (a) at the given value for a. x f(x) g(x) f'(x) g'(x) 0 0 3 2 1 1 0 0 2 0 2 43 22 4 3 3 2 3 1 1 4 1 2 0 4 2 h(x) = (1/(2) ²; 9(x) h' (3)= = ; a=3arrow_forward
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