Chapter 3.4, Problem 7STP

The perimeter of a rectangle is at least $32\text{cm}.$

The length of the rectangle is $9\text{cm}.$

What are the possible widths of the rectangle? Show your work.

To determine

To find: the possible widths of the given rectangle.

Answer to Problem 7STP

The width of the given rectangle is equal to 7 cm.

Explanation of Solution

Given information:

The perimeter of the rectangle $=32\text{cm}$

The length of the rectangle $=9\text{cm}$

Concept used:

The perimeter of the rectangle is given by

  $=2\left(\text{length}+\text{width}\right)$

Calculation:

Apply the above concept, it gives

  $\begin{array}{l}32=2\left(9+\text{width}\right)\\ 9+\text{width}=\frac{32}{2}\\ 9+\text{width}=16\\ \text{width}=16-9\\ \text{width}=7\text{cm}\end{array}$