EBK ALGEBRA 2
EBK ALGEBRA 2
11th Edition
ISBN: 9780544714304
Author: Larson
Publisher: HMH PUB
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Chapter 3.4, Problem 47PS
Solution

(a)

Find the inverse of the given model.

  l1=2w6

Given information:

When calibrating a spring scale, you need to know how far the spring stretches for various weights. Hooke’s law states that the length a spring stretches is proportional to the weight attached to it. A model for one scale is l=0.5w+3 where l is the total length (in inches) of the stretched spring is and w is the weight (in pounds) of the object.

Concept used:

In order to find the inverse of a function y=fx, follow below steps:

Step 1: interchange x and y in the given function

Step 2: solve for y and that will give the required inverse function

Calculation:

Hooke’s law states that the length ( l ) a spring stretches is proportional to the weight ( w ) attached to it.

  l=0.5w+3

The inverse of l=0.5w+3 is-

  l=0.5w+3y=ly=0.5w+3swapwwithyw=0.5y+3solveforyw=0.5y+30.5y=w3y=w30.5y=w0.530.5y=2w6l1=2w6

Thus the inverse of the given function l=0.5w+3 is l1=2w6 .

(b)

If you place a weight on the scale and the spring stretches to a total length of 6.5 inches, how heavy is the weight?

7 pounds.

Given information:

When calibrating a spring scale, you need to know how far the spring stretches for various weights. Hooke’s law states that the length a spring stretches is proportional to the weight attached to it. A model for one scale is l=0.5w+3 where l is the total length (in inches) of the stretched spring is and w is the weight (in pounds) of the object.

Concept used:

In order to find the inverse of a function y=fx, follow below steps:

Step 1: interchange x and y in the given function

Step 2: solve for y and that will give the required inverse function

Calculation:

Hooke’s law states that the length ( l ) a spring stretches is proportional to the weight ( w ) attached to it.

  l=0.5w+3

If we place a weight on the scale and the spring stretches to a total length ( l ) of 6.5 inches.

Then the weight is -

  l=0.5w+36.5=0.5w+36.53=0.5w3.5=0.5ww=3.50.5w=7

So, the weight = 7 pounds

Chapter 3 Solutions

EBK ALGEBRA 2

Ch. 3.1 - Prob. 11GPCh. 3.1 - Prob. 12GPCh. 3.1 - Prob. 13GPCh. 3.1 - Prob. 14GPCh. 3.1 - Prob. 15GPCh. 3.1 - Prob. 16GPCh. 3.1 - Prob. 17GPCh. 3.1 - Prob. 18GPCh. 3.1 - Prob. 19GPCh. 3.1 - Prob. 1ECh. 3.1 - Prob. 2ECh. 3.1 - Prob. 3ECh. 3.1 - Prob. 4ECh. 3.1 - Prob. 5ECh. 3.1 - Prob. 6ECh. 3.1 - Prob. 7ECh. 3.1 - Prob. 8ECh. 3.1 - Prob. 9ECh. 3.1 - Prob. 10ECh. 3.1 - Prob. 11ECh. 3.1 - Prob. 12ECh. 3.1 - Prob. 13ECh. 3.1 - Prob. 14ECh. 3.1 - Prob. 15ECh. 3.1 - Prob. 16ECh. 3.1 - Prob. 17ECh. 3.1 - Prob. 18ECh. 3.1 - Prob. 19ECh. 3.1 - Prob. 20ECh. 3.1 - Prob. 21ECh. 3.1 - Prob. 22ECh. 3.1 - Prob. 23ECh. 3.1 - Prob. 24ECh. 3.1 - Prob. 25ECh. 3.1 - Prob. 26ECh. 3.1 - Prob. 27ECh. 3.1 - Prob. 28ECh. 3.1 - Prob. 29ECh. 3.1 - Prob. 30ECh. 3.1 - Prob. 31ECh. 3.1 - Prob. 32ECh. 3.1 - Prob. 33ECh. 3.1 - Prob. 34ECh. 3.1 - Prob. 35ECh. 3.1 - Prob. 36ECh. 3.1 - Prob. 37ECh. 3.1 - Prob. 38ECh. 3.1 - Prob. 39ECh. 3.1 - Prob. 40ECh. 3.1 - Prob. 41ECh. 3.1 - Prob. 42ECh. 3.1 - Prob. 43ECh. 3.1 - Prob. 44ECh. 3.1 - 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