EBK ALGEBRA 2
EBK ALGEBRA 2
11th Edition
ISBN: 9780544714304
Author: Larson
Publisher: HMH PUB
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Chapter 3.3, Problem 46PS
Solution

(a)

Elvis’s running speed is about 6.4 meters per second, Write a function r(x) for the time he spends running from point A to point D. Elvis’s swimming speed is 0.9 meter per second. Write a function s(x) for the time he spends swimming from point D to point B.

  r(x)=20x6.4

  s(x)=122+x20.9

Given:

A mathematician at a lake throws a tennis ball from point A along the water’s edge to point B in the water, as shown. His dog, Elvis, runs along the beach from point A to point D and then swims to fetch the ball at point B.

  EBK ALGEBRA 2, Chapter 3.3, Problem 46PS , additional homework tip  1

Concept Used:

  • The composition function fg can be found by replacing x by gx in the function fx
  • The domain of a function y=fx is the set of all x values for which the function is defined.
  • A rational function y=fx is undefined for the values of x , for which the denominator is zero.
  • A radical function is defined for positive values greater than or equal to zero.
  • Zero product property: if ab=0 thena=0orb=0

Calculation:

Elvis’s running speed is about 6.4 meters per second

Function for the time he spends running from point A to point D =r(x)

Distance A to D = 20x

  r(x)=distanceAtoDrunningspeed=20x6.4

Function for the time he spends swimming from point D to point B =s(x)

Elvis’s swimming speed is 0.9 meter per second

Distance D to B = 122+x2

  s(x)=distanceDtoBswimmingspeed=122+x20.9

(b)

Write a function t(x) that represents the total time Elvis spends travelling from point A to point D to point B.

  t(x)=20x6.4+122+x20.9

Given:

A mathematician at a lake throws a tennis ball from point A along the water’s edge to point B in the water, as shown. His dog, Elvis, runs along the beach from point A to point D and then swims to fetch the ball at point B.

  EBK ALGEBRA 2, Chapter 3.3, Problem 46PS , additional homework tip  2

Concept Used:

  • The composition function fg can be found by replacing x by gx in the function fx
  • The domain of a function y=fx is the set of all x values for which the function is defined.
  • A rational function y=fx is undefined for the values of x , for which the denominator is zero.
  • A radical function is defined for positive values greater than or equal to zero.
  • Zero product property: if ab=0 thena=0orb=0

Calculation:

Function that represents the total time Elvis spends travelling from point A to point D to point B = tx

  r(x)=20x6.4

  s(x)=122+x20.9

  t(x)=r(x)+s(x)=20x6.4+122+x20.9

Function for the total time he spends swimming from A to point D to point B tx

  =20x6.4+122+x20.9

(c)

Use a graphing calculator to graph t(x). Find the value of x that minimizes t(x). Explain the meaning of this value.

x=1.704m

Given:

A mathematician at a lake throws a tennis ball from point A along the water’s edge to point B in the water, as shown. His dog, Elvis, runs along the beach from point A to point D and then swims to fetch the ball at point B.

  EBK ALGEBRA 2, Chapter 3.3, Problem 46PS , additional homework tip  3

Concept Used:

  • The composition function fg can be found by replacing x by gx in the function fx
  • The domain of a function y=fx is the set of all x values for which the function is defined.
  • A rational function y=fx is undefined for the values of x , for which the denominator is zero.
  • A radical function is defined for positive values greater than or equal to zero.
  • Zero product property: if ab=0 thena=0orb=0

Calculation:

Function that represents the total time Elvis spends travelling from point A to point D to point B = tx

  t(x)=20x6.4+122+x20.9

The graph of t(x)=20x6.4+122+x20.9 is -

  EBK ALGEBRA 2, Chapter 3.3, Problem 46PS , additional homework tip  4

At x=1.704 the value of t(x) will be minimum because if x = 1.704 Elvis have to cover minimum distance to reach B from A to D to B.

Chapter 3 Solutions

EBK ALGEBRA 2

Ch. 3.1 - Prob. 11GPCh. 3.1 - Prob. 12GPCh. 3.1 - Prob. 13GPCh. 3.1 - Prob. 14GPCh. 3.1 - Prob. 15GPCh. 3.1 - Prob. 16GPCh. 3.1 - Prob. 17GPCh. 3.1 - Prob. 18GPCh. 3.1 - Prob. 19GPCh. 3.1 - Prob. 1ECh. 3.1 - Prob. 2ECh. 3.1 - Prob. 3ECh. 3.1 - Prob. 4ECh. 3.1 - Prob. 5ECh. 3.1 - Prob. 6ECh. 3.1 - Prob. 7ECh. 3.1 - Prob. 8ECh. 3.1 - Prob. 9ECh. 3.1 - Prob. 10ECh. 3.1 - Prob. 11ECh. 3.1 - Prob. 12ECh. 3.1 - Prob. 13ECh. 3.1 - Prob. 14ECh. 3.1 - Prob. 15ECh. 3.1 - Prob. 16ECh. 3.1 - Prob. 17ECh. 3.1 - Prob. 18ECh. 3.1 - Prob. 19ECh. 3.1 - Prob. 20ECh. 3.1 - Prob. 21ECh. 3.1 - Prob. 22ECh. 3.1 - Prob. 23ECh. 3.1 - Prob. 24ECh. 3.1 - Prob. 25ECh. 3.1 - Prob. 26ECh. 3.1 - Prob. 27ECh. 3.1 - Prob. 28ECh. 3.1 - Prob. 29ECh. 3.1 - Prob. 30ECh. 3.1 - Prob. 31ECh. 3.1 - Prob. 32ECh. 3.1 - Prob. 33ECh. 3.1 - Prob. 34ECh. 3.1 - Prob. 35ECh. 3.1 - Prob. 36ECh. 3.1 - Prob. 37ECh. 3.1 - Prob. 38ECh. 3.1 - Prob. 39ECh. 3.1 - Prob. 40ECh. 3.1 - Prob. 41ECh. 3.1 - Prob. 42ECh. 3.1 - Prob. 43ECh. 3.1 - Prob. 44ECh. 3.1 - 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Prob. 40ECh. 3.4 - Prob. 41ECh. 3.4 - Prob. 42ECh. 3.4 - Prob. 43ECh. 3.4 - Prob. 44ECh. 3.4 - Prob. 45ECh. 3.4 - Prob. 46PSCh. 3.4 - Prob. 47PSCh. 3.4 - Prob. 48PSCh. 3.4 - Prob. 49PSCh. 3.4 - Prob. 50PSCh. 3.4 - Prob. 51PSCh. 3.4 - Prob. 1QCh. 3.4 - Prob. 2QCh. 3.4 - Prob. 3QCh. 3.4 - Prob. 4QCh. 3.4 - Prob. 5QCh. 3.4 - Prob. 6QCh. 3.4 - Prob. 7QCh. 3.4 - Prob. 8QCh. 3.4 - Prob. 9QCh. 3.4 - Prob. 10QCh. 3.4 - Prob. 11QCh. 3.4 - Prob. 12QCh. 3.4 - Prob. 13QCh. 3.4 - Prob. 14QCh. 3.4 - Prob. 15QCh. 3.4 - Prob. 16QCh. 3.4 - Prob. 17QCh. 3.4 - Prob. 18QCh. 3.4 - Prob. 19QCh. 3.5 - Prob. 1GPCh. 3.5 - Prob. 2GPCh. 3.5 - Prob. 3GPCh. 3.5 - Prob. 4GPCh. 3.5 - Prob. 5GPCh. 3.5 - Prob. 6GPCh. 3.5 - Prob. 7GPCh. 3.5 - Prob. 8GPCh. 3.5 - Prob. 9GPCh. 3.5 - Prob. 10GPCh. 3.5 - Prob. 11GPCh. 3.5 - Prob. 1ECh. 3.5 - Prob. 2ECh. 3.5 - Prob. 3ECh. 3.5 - Prob. 4ECh. 3.5 - Prob. 5ECh. 3.5 - Prob. 6ECh. 3.5 - Prob. 7ECh. 3.5 - Prob. 8ECh. 3.5 - Prob. 9ECh. 3.5 - Prob. 10ECh. 3.5 - Prob. 11ECh. 3.5 - Prob. 12ECh. 3.5 - 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