Autocollimation. You place an object alongside a white screen, and a plane mirror is 60.0 cm to the right of the object and the screen, with the surface of the mirror tilted slightly from the perpendicular to the line from object to mirror. You then place a converging lens between the object and the mirror. Light from the object passes through the lens, reflects from the mirror, and passes back through the lens; the image is projected onto the screen. You adjust the distance of the lens from the object until a sharp image of the object is focused on the screen. The lens is then 22.0 cm from the object. Because the screen is alongside the object, the distance from object to lens is the same as the distance from screen to lens. (a) Draw a sketch that shows the locations of the object, lens, plane mirror, and screen. (b) What is the focal length of the lens?
Autocollimation. You place an object alongside a white screen, and a plane mirror is 60.0 cm to the right of the object and the screen, with the surface of the mirror tilted slightly from the perpendicular to the line from object to mirror. You then place a converging lens between the object and the mirror. Light from the object passes through the lens, reflects from the mirror, and passes back through the lens; the image is projected onto the screen. You adjust the distance of the lens from the object until a sharp image of the object is focused on the screen. The lens is then 22.0 cm from the object. Because the screen is alongside the object, the distance from object to lens is the same as the distance from screen to lens. (a) Draw a sketch that shows the locations of the object, lens, plane mirror, and screen. (b) What is the focal length of the lens?
Autocollimation. You place an object alongside a white screen, and a plane mirror is 60.0 cm to the right of the object and the screen, with the surface of the mirror tilted slightly from the perpendicular to the line from object to mirror. You then place a converging lens between the object and the mirror. Light from the object passes through the lens, reflects from the mirror, and passes back through the lens; the image is projected onto the screen. You adjust the distance of the lens from the object until a sharp image of the object is focused on the screen. The lens is then 22.0 cm from the object. Because the screen is alongside the object, the distance from object to lens is the same as the distance from screen to lens. (a) Draw a sketch that shows the locations of the object, lens, plane mirror, and screen. (b) What is the focal length of the lens?
5. The radius of a circle is 5.5 cm.
(a) What is the circumference in meters?
(b) What is its area in square meters?
6. Using the generic triangle below, solve the following:
0 = 55 and c = 32 m, solve for a and b.
a = 250 m and b = 180 m, solve for the angle and c.
b=104 cm and c = 65 cm, solve for a and the angle
b
a
7. Consider the figure below representing the Temperature (T in degrees Celsius) as a function of time
t (in seconds)
4
12
20
(a) What is the area under the curve in the figure below?
(b) The area under the graph can be calculated using integrals or derivatives?
(c) During what interval is the derivative of temperature with respect to time equal to zero?
Part 3: Symbolic Algebra
Often problems in science and engineering are done with variables only. Don't let the different letters
confuse you. Manipulate them algebraically as though they were numbers.
1. Solve 3x-7= x + 3 for x
2x-1
2. Solve-
for x
2+2
In questions 3-11 solve for the required symbol/letter
3. v2 +2a(s-80), a =
=
4. B=
Ho I
2π r
5. K = kz²
6.xm=
MAL
,d=
d
7.T, 2
=
8.F=Gm
9. mgh=mv²
10.qV = mu²
80
12. Suppose that the height in meters of a thrown ball after t seconds is given by h =6+4t-t².
Complete the square to find the highest point and the time when this happens.
13. Solve by completing the square c₁t² + cat + 3 = 0.
14. Solve for the time t in the following expression = 0 + vot+at²
A blacksmith cools a 1.60 kg chunk of iron, initially
at a temperature of 650.0° C, by trickling 30.0°C
water over it. All the water boils away, and the iron
ends up at a temperature of 120.0° C.
For related problem-solving tips and strategies, you
may want to view a Video Tutor Solution of
Changes in both temperature and phase.
Part A
How much water did the blacksmith trickle over the iron?
Express your answer with the appropriate units.
HÅ
mwater =
Value
0
?
Units
Submit
Request Answer
Chapter 34 Solutions
University Physics, Volume 2 - Technology Update Custom Edition for Texas A&M - College Station, 2/e
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