To explain: The differences between the peak absorbance of the native (untreated) and reduced (denatured) RNase A.
Introduction: RNase A is an enzyme/ protein that stimulates the catabolism of RNA into micro-molecules. It is a nuclease that has 4 disulfide bridges between the cysteine molecules with an overall length of 124 amino acids. UV spectroscopy is used to measure the intensity of the light that is absorbed by the molecule at different wavelengths.
To explain: The changes observed when the protein RNAase A was reoxidized.
Introduction: Proteins when denatured lose their structure and function. Under stimulated conditions a protein can refold again to form the disulfide bridges and other interactions.
To conclude: The structure of RNase on the basis of the experiment.
Introduction: RNase A is a nuclease that catalyzes the degradation of the RNA molecules. This reaction is exergonic and will release energy.
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Chapter 3 Solutions
PRINCIPLE OF LIFE (LL)W/ACHIEVE>CUSTOM<
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- 10. Write a simple formula for converting μm to mm when the number of μm's are known. Use the variable X to represent the number of um's in your formula.arrow_forward8. How many μm² is in one cm²; express the result in scientific notation. Show your calculations. 1 cm = 10 mm; 1 mm = 1000 μmarrow_forwardFind the dental formula and enter it in the following format: I3/3 C1/1 P4/4 M2/3 = 42 (this is not the correct number, just the correct format) Please be aware: the upper jaw is intact (all teeth are present). The bottom jaw/mandible is not intact. The front teeth should include 6 total rectangular teeth (3 on each side) and 2 total large triangular teeth (1 on each side).arrow_forward
- Answer iarrow_forwardAnswerarrow_forwardcalculate the questions showing the solution including variables,unit and equations all the questiosn below using the data a) B1, b) B2, c) hybrid rate constant (1) d) hybrid rate constant (2) e) t1/2,dist f) t1/2,elim g) k10 h) k12 i) k21 j) initial concentration (C0) k) central compartment volume (V1) l) steady-state volume (Vss) m) clearance (CL) AUC (0→10 min) using trapezoidal rule n) AUC (20→30 min) using trapezoidal rule o) AUCtail (AUC360→∞) p) total AUC (using short cut method) q) volume from AUC (VAUC)arrow_forward
- QUESTION 8 For the following pedigree, assume that the mode of inheritance is X-linked recessive, and that the trait has full penetrance and expressivity and occurs at a very low frequency in the hum population. Using XA for the dominant allele and Xa for the recessive allele, assign genotypes for the following individuals (if it is not possible to figure out the second allele of a genotype, that with an underscore): 2 m 1 2 1 2 4 5 6 7 8 9 IV 1 2 3 5 6 7 8 CO 9 10 12 13 V 1, 2 3 4 5 6 7 8 9 10 11 12 13 a. Il-1: b. 11-2: c. III-3: d. III-4: e. If individuals IV-11 and IV-12 have another child, what is the probability that they will have a boy with the disorder?arrow_forwardAnswerrarrow_forwardplease,show workings ahd solutions calculate the questions showing the solution including variables,unit and equations all the questiosn below using the data a) B1, b) B2, c) hybrid rate constant (1) d) hybrid rate constant (2) e) t1/2,dist f) t1/2,elim g) k10 h) k12 i) k21 j) initial concentration (C0) k) central compartment volume (V1) l) steady-state volume (Vss) m) clearance (CL) AUC (0→10 min) using trapezoidal rule n) AUC (20→30 min) using trapezoidal rule o) AUCtail (AUC360→∞) p) total AUC (using short cut method) q) volume from AUC (VAUC)arrow_forward
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