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Imagine a single object whose mass is equal to the mass of system C and whose momentum is equal at all times to
The velocity that you have found is called the velocity of the center of mass,
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- A man of mass 80 kg is standing stationary in the middle of a train carriage (see the figure below). The train is moving horizontally with a constant speed of 20 m/s (see the figure below), and the carriage is L=20 m long. Suddenly, the train starts to accelerate uniformly with a=2 m/s2 horizontally. a) Is the reference frame of the train now an inertial frame? Design an experiment that allows you to find out. b) Draw a free-body diagram of the man. Label the forces appropriately and explain their physical origin (one line each will suffice). c) If the coefficient of friction between the man's shoes and the `floor' of the train is μ=0.1, what is the maximum time that the man takes to hit the back of the train carriage? For simplicity, you can assume that the coefficient of static friction is the same as the coefficient of kinetic friction. Assume that there are no obstacles between the man and the back of the train. d) How does your answer change if the coefficient of…arrow_forwardThe four masses shown in the diagram are connected by massless, rigid rods. The mass of the A particle is 400 g, the mass of the B particle is 900 g, the mass of the C particle is 500 g, and the mass of the D particle is 450 g. The length of the rods is 10 cm. Consider the A particle to be the origin of the coordinate system. The x coordinate of the center of mass (in cm) is? Consider the A particle to be the origin of the coordinate system. The y coordinate of the center of mass (in cm) is ? Find the moment of inertia (in kg*m*m) about an axis that passes through mass A and is perpendicular to the page.arrow_forwardAn atomic nucleus suddenly bursts apart (fission) into two pieces. Piece A with mass mA travels to the left with a speed of vA. Piece B with mass mB travels to the right with speed vB. Show the velocity of piece B in terms of mA, mB and VA. Solution: Consider that the nucleus is not acted by an external force. Thus, momentum is conserved, so: pBf + pAf = 0 Substituting the expression for momentum results to mBv + mAv = 0 Deriving the expression for the velocity of piece B results toarrow_forward
- C Chegg X C Sign In https://bconline.broward.edu/d21/lms/quizzing/user/attempt/quiz_start_frame_auto.d2l?ou=514283&is... A Q If a projectile mass of 1.0 kg moving at 19.0 m/s collides with a motionless target mass of 15.0 kg perfectly inelastically what is the total kinetic energy of the projectile and target after the collision? X 1 OneLoc X Quizzes X Q instagra X Your Answer: Use standard MKS unit abbreviations. Instagra X Answer units (75,834 X C Reset P. X X New ta X + {}arrow_forwardF The force F = 460 N acts on the frame. Resolve this force into components acting along members AB and AC, and determine the magnitude of each component. Given that a = 34° and ß = 47°, The magnitude along AB is (round to one decimal place): The magnitude along AC is (round to one decimal place): Narrow_forwardUse Lagrangian formalism to solve the following problem: A block of mass m is held motionless on a frictionless plane of mass M and angle of inclination @ (see Figure below). Here x1 and x2 are the horizontal positions of the plane and block respectively. The plane rests on a frictionless horizontal surface. The block is released. a) What is the change in the vertical height of the block when the plane and the block moved horizontally x1 and x2 distances respectively? b) Write the Lagrangian for the system. c) Derive the Euler-Lagrangian equations for the x1 and x2. b) What is the horizontal acceleration of the plane?arrow_forward
- Two particles of mass m1 = 1.4 kg and m2 = 2.9 kg undergo a one-dimensional head-on collision as shown in the figure below. Their initial velocities aling x are v1i = 11 m/s and v2i = -7.2 m/s. The two particles stick together after the collision (a completely inelastic collision). (Assume to the right as the positive direction). a) Find the velocity after the collision. answer is - 1.27 m/s b) How much kinetic energy is lost in the collision?arrow_forwardIn the four momentum treatment of relativistic particle collisions or decays, The mass of a particle is different for various observers. O Momentum and energy are still conserved in any inertial frame of reference. O The energy equals the sum of the momentum, pc, plus the mass, mc2. O The momentum and energy for a process are the same in all frames of reference.arrow_forwardIn a pulley mass experiment, you have two blocks of masses M₁ and M₂ are connected with an ideal string that passes over a massless and frictionless pulley. You noticed that after you releases the system, M, mass accelerates rightward. Now your goal is to make the system move with constant speed. Determine the mass of m that can be placed over M, with which the system moves with constant speed. Assume the coefficient of friction between table and block is μ. M₁ 47 M2arrow_forward
- A firework explodes into three pieces as shown in the diagram below. Now that you have set up the equation for the x and y components of the final momentum of the firework, let's do some physics! Given: The initial firework had a mass of 9.0 kg and was launched at vi = 110 m/s vertically straight up. The firework explodes into three pieces of equal mass 3.0 kg. The angles θ1 = θ3 = 20 ∘. Speed v1 = 100 m/s. What is the speed v2? Note: the angles shown for mass m1 and mass m3 are relative to the horizontal x axis. Mass m2 is moving straight up (y axis).arrow_forwardPLEASE SEND IN 10 MINUTES!!! Consider the collision pictured below. While m2=10kg is initially at rest, horizontally moving m1=6kg with a speed of v1=11.8m/s collides with it. After the collision, the two masses scatter with speeds of v1′=7.8m/s and v2′. If θ1=48o, determine the angle θ2. Express your answer in units of degrees with zero decimal places. Note: Please note that we do not know whether or not this is an elastic collision.arrow_forward→ A student runs an experiment with two carts on a low-friction track. As measured in the Earth reference frame, cart 1 (m 0.36 kg) moves from left to right at 1.0 m/s as the student walks along next to it at the same velocity. (a) What velocity v E2,¡ in the Earth reference frame must cart 2 (m 0.12 kg) have before the collision if, in the student's reference frame, cart 2 comes to rest right after the collision and cart 1 reverses direction and travels from right to left at 0.33 m/s? (b) What does the student measure for the momentum of the two-cart system? (c) What does a person standing in the Earth reference frame measure for the momentum of each cart before the collision? .. =arrow_forward
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