In Exercises 11 − 16 : a ) Find a matrix B in reduced echlon form such that B is row equivalent to the given matrix A . b ) Find a basis for the null space of A . c ) As in Example 6 , find a basis for the range of A that consists of columns of A . For each column, A j , of A that does not appear in the basis, express A j as a linear combination of the basis vectors. d ) Exhibit a basis for the row space of A . A = [ 2 1 2 2 2 1 2 3 0 ]
In Exercises 11 − 16 : a ) Find a matrix B in reduced echlon form such that B is row equivalent to the given matrix A . b ) Find a basis for the null space of A . c ) As in Example 6 , find a basis for the range of A that consists of columns of A . For each column, A j , of A that does not appear in the basis, express A j as a linear combination of the basis vectors. d ) Exhibit a basis for the row space of A . A = [ 2 1 2 2 2 1 2 3 0 ]
Solution Summary: The author explains how a matrix is in row echelon form if it satisfies the following conditions: 1. Non zero number in each row is called leading entry.
a
)
Find a matrix
B
in reduced echlon form such that
B
is row equivalent to the given matrix
A
.
b
)
Find a basis for the null space of
A
.
c
)
As in Example
6
, find a basis for the range of
A
that consists of columns of
A
. For each column,
A
j
, of
A
that does not appear in the basis, express
A
j
as a linear combination of the basis vectors.
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