Explanation Given: The given line is y = x . Formula used: The distance formula between 2 points ( x 1 , y 1 ) and ( x 2 , y 2 ) is d = ( x 2 − x 1 ) 2 + ( y 2 − y 1 ) 2 Consider a quadratic function of the form f ( x ) = a x 2 + b x + c , a ≠ 0 . Then the graph of the above function is a parabola with vertex ( − b 2 a , f ( − b 2 a ) ) . This vertex is the highest point if a < 0 and the lowest point if a > 0 . Therefore, the maximum (or the minimum) value of the function will be f ( − b 2 a ) . Calculation: Here, we have ( x 1 , y 1 ) = ( 3 , 1 ) . Therefore, the distance between the points ( x 1 , y 1 ) and ( x 2 , y 2 ) is d ( x ) = ( x 2 − 3 ) 2 + ( y 2 − 1 ) 2 ⇒ ( d ( x

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Chapter 3.3, Problem 99AYU

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To calculate: The point on the line that is closest to the point $(3, 1)$ .

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Chapter 3.3, Problem 98AYU

Chapter 3.3, Problem 100AYU

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