OWLv2 with MindTap Reader, 1 term (6 months) Printed Access Card for Brown/Iverson/Anslyn/Foote's Organic Chemistry, 8th Edition
OWLv2 with MindTap Reader, 1 term (6 months) Printed Access Card for Brown/Iverson/Anslyn/Foote's Organic Chemistry, 8th Edition
8th Edition
ISBN: 9781305582439
Author: Brown, William H.; Iverson, Brent L.; Anslyn, Eric; Foote, Christopher S.
Publisher: Cengage Learning
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Chapter 3.3, Problem 3.3P

(a)

Interpretation Introduction

Interpretation:

The configuration for the given moleculehas to be assigned.

Concept Introduction:

Priority rules:

  • Priorities based on atomic number

-H,-CH3,-NH2,-OH,-SH,-Cl,-Br,-IIncreasingpriority

  • When priority cannot be assigned on the basis of the atoms bonded directly to the chiral center

-CH2H,-CH2CH3,-CH2NH2,-CH2OH,-CH2ClIncreasingpriority

  • Atoms participating in a double or triple bond are considered to be bonded to an equivalent number of phantom atoms.

For example,

OWLv2 with MindTap Reader, 1 term (6 months) Printed Access Card for Brown/Iverson/Anslyn/Foote's Organic Chemistry, 8th Edition, Chapter 3.3, Problem 3.3P , additional homework tip  1

  • Priority assignment is made at the first point of difference between groups (should not be based on the larger group).

(b)

Interpretation Introduction

Interpretation:

The configuration for the given molecule has to be assigned.

Concept Introduction:

Priority rules:

  • Priorities based on atomic number

-H,-CH3,-NH2,-OH,-SH,-Cl,-Br,-IIncreasingpriority

  • When priority cannot be assigned on the basis of the atoms bonded directly to the chiral center

-CH2H,-CH2CH3,-CH2NH2,-CH2OH,-CH2ClIncreasingpriority

  • Atoms participating in a double or triple bond are considered to be bonded to an equivalent number of phantom atoms.

For example,

OWLv2 with MindTap Reader, 1 term (6 months) Printed Access Card for Brown/Iverson/Anslyn/Foote's Organic Chemistry, 8th Edition, Chapter 3.3, Problem 3.3P , additional homework tip  2

  • Priority assignment is made at the first point of difference between groups (should not be based on the larger group).

(c)

Interpretation Introduction

Interpretation:

The configuration for the given molecule has to be assigned.

Concept Introduction:

Priority rules:

  • Priorities based on atomic number

-H,-CH3,-NH2,-OH,-SH,-Cl,-Br,-IIncreasingpriority

  • When priority cannot be assigned on the basis of the atoms bonded directly to the chiral center

-CH2H,-CH2CH3,-CH2NH2,-CH2OH,-CH2ClIncreasingpriority

  • Atoms participating in a double or triple bond are considered to be bonded to an equivalent number of phantom atoms.

For example,

OWLv2 with MindTap Reader, 1 term (6 months) Printed Access Card for Brown/Iverson/Anslyn/Foote's Organic Chemistry, 8th Edition, Chapter 3.3, Problem 3.3P , additional homework tip  3

  • Priority assignment is made at the first point of difference between groups (should not be based on the larger group).

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5. A solution of sucrose is fermented in a vessel until the evolution of CO2 ceases. Then, the product solution is analyzed and found to contain, 45% ethanol; 5% acetic acid; and 15% glycerin by weight. If the original charge is 500 kg, evaluate; e. The ratio of sucrose to water in the original charge (wt/wt). f. Moles of CO2 evolved. g. Maximum possible amount of ethanol that could be formed. h. Conversion efficiency. i. Per cent excess of excess reactant. Reactions: Inversion reaction: C12H22O11 + H2O →2C6H12O6 Fermentation reaction: C6H12O6 →→2C2H5OH + 2CO2 Formation of acetic acid and glycerin: C6H12O6 + C2H5OH + H₂O→ CH3COOH + 2C3H8O3
Show work. don't give Ai generated solution.  How many carbons and hydrogens are in the structure?
13. (11pts total) Consider the arrows pointing at three different carbon-carbon bonds in the molecule depicted below. Bond B 2°C. +2°C. cleavage Bond A •CH3 + 26.← Cleavage 2°C. + Bond C +3°C• CH3 2C Cleavage E 2°C. 26. weakest bond Intact molecule Strongest 3°C 20. Gund Largest argest a. (2pts) Which bond between A-C is weakest? Which is strongest? Place answers in appropriate boxes. C Weakest bond A Produces Most Bond Strongest Bond Strongest Gund produces least stable radicals Weakest Stable radical b. (4pts) Consider the relative stability of all cleavage products that form when bonds A, B, AND C are homolytically cleaved/broken. Hint: cleavage products of bonds A, B, and C are all carbon radicals. i. Which ONE cleavage product is the most stable? A condensed or bond line representation is fine. 13°C. formed in bound C cleavage ii. Which ONE cleavage product is the least stable? A condensed or bond line representation is fine. • CH3 methyl radical Formed in Gund A Cleavage c.…

Chapter 3 Solutions

OWLv2 with MindTap Reader, 1 term (6 months) Printed Access Card for Brown/Iverson/Anslyn/Foote's Organic Chemistry, 8th Edition

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