(a)
Interpretation:
A balanced chemical equation for a reaction between sodium and water to form hydrogen gas and the solution of sodium hydroxide is to be written.
Concept introduction:
A balanced chemical equation obeyed the law of conservation of mass since the total mass of reactants and products are equal in a balanced chemical equation.
Following are the steps to write a balanced chemical equation.
Step 1: Translate the chemical statement into a skeleton equation. The reactants are the chemical substances that undergo a change, thus, write the reactants on the left side of the yield arrow. The products are the chemical substances that are produced during the chemical change, thus, write the products on the right side of the yield arrow. Put a blank before each formula while beginning the balancing process.
Step 2: Identify the most complex substance and choose an element such that the element must be present only in one reactant and one product. Place the stoichiometric coefficient before the element/elements such that the number of atoms of that element(s) is the same on both sides.
Step 3: Balance the remaining atoms by placing the
Step 4: In a balanced
Step 5: Check whether the chemical equation is balanced or not by counting the number of atoms of each element on both sides.
Step 6: Specify the
(b)
Interpretation:
A balanced chemical equation for a reaction between aqueous nitric acid and calcium carbonate to form carbon dioxide, water, and an aqueous solution of calcium nitrate is to be written.
Concept introduction:
A balanced chemical equation obeyed the law of conservation of mass since the total mass of reactants and products are equal in a balanced chemical equation.
Following are the steps to write a balanced chemical equation.
Step 1: Translate the chemical statement into a skeleton equation. The reactants are the chemical substances that undergo a change, thus, write the reactants on the left side of the yield arrow. The products are the chemical substances that are produced during the chemical change, thus, write the products on the right side of the yield arrow. Put a blank before each formula while beginning the balancing process.
Step 2: Identify the most complex substance and choose an element such that the element must be present only in one reactant and one product. Place the stoichiometric coefficient before the element/elements such that the number of atoms of that element(s) is the same on both sides.
Step 3: Balance the remaining atoms by placing the stoichiometric coefficients before the element/elements such that the number of atoms of that element(s) is the same on both sides. Identify the least complex substance and end with it.
Step 4: In a balanced chemical reaction, the smallest whole number coefficients are most preferred. Hence, adjusting the coefficients in such a way that the smallest whole number coefficients are obtained for each element.
Step 5: Check whether the chemical equation is balanced or not by counting the number of atoms of each element on both sides.
Step 6: Specify the states of matter of each chemical substance present in the balanced chemical equation. The table for the abbreviations used for each state is as follows:
(c)
Interpretation:
A balanced chemical equation for a reaction between phosphorous trichloride and hydrogen fluoride to form phosphorous trifluoride and hydrogen chloride is to be written.
Concept introduction:
A balanced chemical equation obeyed the law of conservation of mass since the total mass of reactants and products are equal in a balanced chemical equation.
Following are the steps to write a balanced chemical equation.
Step 1: Translate the chemical statement into a skeleton equation. The reactants are the chemical substances that undergo a change, thus, write the reactants on the left side of the yield arrow. The products are the chemical substances that are produced during the chemical change, thus, write the products on the right side of the yield arrow. Put a blank before each formula while beginning the balancing process.
Step 2: Identify the most complex substance and choose an element such that the element must be present only in one reactant and one product. Place the stoichiometric coefficient before the element/elements such that the number of atoms of that element(s) is the same on both sides.
Step 3: Balance the remaining atoms by placing the stoichiometric coefficients before the element/elements such that the number of atoms of that element(s) is the same on both sides. Identify the least complex substance and end with it.
Step 4: In a balanced chemical reaction, the smallest whole number coefficients are most preferred. Hence, adjusting the coefficients in such a way that the smallest whole number coefficients are obtained for each element.
Step 5: Check whether the chemical equation is balanced or not by counting the number of atoms of each element on both sides.
Step 6: Specify the states of matter of each chemical substance present in the balanced chemical equation. The table for the abbreviations used for each state is as follows:
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Chapter 3 Solutions
CHEMISTRY(LOOSELEAF) W/CONNECT+EBOOK
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- 16. Consider the probability distribution p(x) = ax", 0 ≤ x ≤ 1 for a positive integer n. A. Derive an expression for the constant a, to normalize p(x). B. Compute the average (x) as a function of n. C. Compute σ2 = (x²) - (x)², the variance of x, as a function of n.arrow_forward451. Use the diffusion model from lecture that showed the likelihood of mixing occurring in a lattice model with eight lattice sites: Case Left Right A B C Permeable Barrier → and show that with 2V lattice sites on each side of the permeable barrier and a total of 2V white particles and 2V black particles, that perfect de-mixing (all one color on each side of the barrier) becomes increasingly unlikely as V increases.arrow_forward46. Consider an ideal gas that occupies 2.50 dm³ at a pressure of 3.00 bar. If the gas is compressed isothermally at a constant external pressure so that the final volume is 0.500 dm³, calculate the smallest value Rest can have. Calculate the work involved using this value of Rext.arrow_forward
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