Concept explainers
(a)
Interpretation:
The mass fraction of carbon
Concept introduction:
Molar mass is defined as the mass of
The mass fraction of an element in a compound is defined as the ratio of the sum of the masses of all the atoms of that element to that of the mass of one mole of compound.
The steps to calculate the mass fraction of an element are as follows:
Step 1: Determine the molar mass and the formula of the compound. From the formula, determine the relative number of moles of each element. To determine the mass fraction of an element, calculate its total mass. The formula to calculate the total mass of an element A present in the compound is as follows:
Step 2: To calculate the mass fraction of an element A, take the ratio of the total mass of element A and the mass of one mole of compound. The formula to calculate the mass fraction of an element A is as follows:
(b)
Interpretation:
The mass fraction of oxygen
Concept introduction:
Molar mass is defined as the mass of
The mass fraction of an element in a compound is defined as the ratio of the sum of the masses of all the atoms of that element to that of the mass of one mole of compound.
The steps to calculate the mass fraction of an element are as follows:
Step 1: Determine the molar mass and the formula of the compound. From the formula, determine the relative number of moles of each element. To determine the mass fraction of an element, calculate its total mass. The formula to calculate the total mass of an element A present in the compound is as follows:
Step 2: To calculate the mass fraction of an element A, take the ratio of the total mass of element A and the mass of one mole of compound. The formula to calculate the mass fraction of an element A is as follows:
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Chapter 3 Solutions
CHEMISTRY(LOOSELEAF) W/CONNECT+EBOOK
- Show work. Don't give Ai generated solutionarrow_forwardPlease correct answer and don't use hand ratingarrow_forwardQ: Draw the molecular orbital energy level diagram for the following molecules. 1- The SF4 molecule is seesaw molecular geometry and has C2v point group. 2- The Mn(CO)s molecule with C4v point group is square pyramidal.arrow_forward
- Please correct answer and don't use hand ratingarrow_forwardwhen a 0.150 g sample of the compound was burned, it produced 0.138 g CO2 & 0.0566 g H2O. All the nitrogen in a different 0.200 g sample of the compound was converted to NH3, which was found to weigh 0.0238 g. Finally, the chlorine in a 0.125 g sample of the compound was converted to Cl- and by reacting it with AgNO3, all of the chlorine was recovered as the solid AgCl. The AgCl, when dried was found to weigh 0.251 g. What is the empirical formulaarrow_forwardPlease correct answer and don't use hand rating and don't use Ai solutionarrow_forward
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