MyProgrammingLab with Pearson eText -- Access Code Card -- for Building Java Programs
MyProgrammingLab with Pearson eText -- Access Code Card -- for Building Java Programs
5th Edition
ISBN: 9780135472460
Author: REGES, Stuart, Stepp, Marty
Publisher: PEARSON
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Chapter 3.3, Problem 20SCP

a.

Explanation of Solution

Result of “str1.length()”:

  • The function “length()”is used to return the number of characters in the given string.
  • The variable “str1” is assigned the string value “Q.E...

b.

Explanation of Solution

Result of “str2.length()”:

  • The function “length()”is used to return the number of characters in the given string.
  • The variable “str2” is assigned the string value “Arcturan Megadonkey”...

c.

Explanation of Solution

Result of “str1.toUpperCase()”:

  • The function “toUpperCase()”is used to return the string with all uppercase letters...

d.

Explanation of Solution

Result of “str2.toUpperCase()”:

  • The function “toUpperCase()”is used to return the string with all uppercase letters...

e.

Explanation of Solution

Result of “str1.substring(2,4)”:

  • The function “substring()”is used to return the substring for the specified index range.
  • The variable “str1” is assigned the string value “Q.E.D.”.
  • The starting index of the string is “0”...

f.

Explanation of Solution

Result of “str2.substring(10,14)”:

  • The function “substring()”is used to return the substring for the specified index range.
  • The variable “str2” is assigned the string value “Arcturan Megadonkey”.
  • The starting index of the string is “0”...

g.

Explanation of Solution

Result of “str1.indexOf(“D”)”:

  • The function “indexOf()”is used to return the index of the first occurrences of the given character “D”.
  • The variable “str1” is assigned the string value “Q.E.D.”.
  • The starting index of the string is “0”...

h.

Explanation of Solution

Result of “str1.indexOf(“.”)”:

  • The function “indexOf()”is used to return the index of the first occurrences of the given character “.”.
  • The variable “str1” is assigned the string value “Q.E.D.”.
  • The starting index of the string is “0”...

i.

Explanation of Solution

Result of “str2.indexOf(“donkey”)”:

  • The function “indexOf()”is used to return the index of the first occurrences of the given strinf “donkey”.
  • The variable “str2” is assigned the string value “Arcturan Megadonkey”.
  • The starting index of the string is “0”...

j.

Explanation of Solution

Result of “str3.indexOf(“X”)”:

  • The function “indexOf()”is used to return the index of the first occurrences of the given character “X”.
  • The variable “str3” is assigned the string value “Sirius Cybernetics Corporation”.
  • The starting index of the string is “0”...

k.

Explanation of Solution

Result of “str2 + str3 . charAt(17)”:

  • The function “charAt()”is used to return the character at the given index.
  • The variable “str2” is assigned the string value “Arcturan Megadonkey”.
  • The variable “str3” is assigned the string value “Sirius Cybernetics Corporation”...

l.

Explanation of Solution

Result of “str3.substring(9,str3.index0f("e"))”:

  • The function “indexOf()” is used to return the index of the first occurrences of the given character.
  • The variable “str3” is assigned the string value “Sirius Cybernetics Corporation”.
  • The function “indexOf(“e”)” returns the index of first occurrence of the character “e”. Hence the index is “10”...

m.

Explanation of Solution

Result of “str3.substring(7,12)”:

  • The function “substring()” is used to return the substring for the specified index range.
  • The variable “str3” is assigned the string value “Sirius Cybernetics Corporation”.
  • The starting index of the string is “0”...

n.

Explanation of Solution

Result of “str2.toLowerCase().substring(9,13) + str3. substring(18,str3.length() - 7)”:

  • The function “substring()” is used to return the substring for the specified index range.
  • The function “toLowerCase()” is used to return the string with all lowercase letters.
  • The function “length()”is used to return the number of characters in the given string.
  • The variable “str3” is assigned the string value “Sirius Cybernetics Corporation”.
  • The variable “str2” is assigned the string value “Arcturan Megadonkey”.
  • The starting index of the string is “0”.
  • The expression “str2.toLowerCase()” returns the string “arcturan megadonkey”.
  • The given expression “str2...

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