MyProgrammingLab with Pearson eText -- Access Code Card -- for Building Java Programs
MyProgrammingLab with Pearson eText -- Access Code Card -- for Building Java Programs
5th Edition
ISBN: 9780135472460
Author: REGES, Stuart, Stepp, Marty
Publisher: PEARSON
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Chapter 3.3, Problem 19SCP

a.

Explanation of Solution

Result of “str1.length()”:

  • The function “length()”is used to return the number of characters in the given string.
  • The variable “str1” is assigned the string value “Frodo Baggins”...

b.

Explanation of Solution

Result of “str1.charAt(7)”:

  • The function “charAt()”is used to return the character at the given index position.
  • The variable “str1” is assigned the string value “Frodo Baggins”...

c.

Explanation of Solution

Result of “str2.charAt(0)”:

  • The function “charAt()”is used to return the character at the given index position.
  • The variable “str2” is assigned the string value “Gandalf the GRAY”...

d.

Explanation of Solution

Result of “str1.indexOf(“o”)”:

  • The function “indexOf()”is used to return the index of the first occurrences of the given character.
  • The variable “str1” is assigned the string value “Frodo Baggins”...

e.

Explanation of Solution

Result of “str2.toUpperCase()”:

  • The function “toUpperCase()”is used to return the string with all uppercase letters...

f.

Explanation of Solution

Result of “str1.toLowerCase().indexOf(“B”)””:

  • The function “toLowerCase()”is used to return the string with all lowercase letters.
  • The “str1.toLowerCase()” returns the string “Frodo Baggins” with all lowercase letters, which is “frodo baggins”...

g.

Explanation of Solution

Result of “str1.substring(4)”:

  • The function “substring()”is used to return the substring for the specified index range.
  • The variable “str1” is assigned the string value “Frodo Baggins”...

h.

Explanation of Solution

Result of “str2.substring(3,14)”:

  • The function “substring()”is used to return the substring for the specified index range.
  • The variable “str2” is assigned the string value “Gandalf the GRAY”...

i.

Explanation of Solution

Result of “str2.replace(“a”, “oo”)”:

  • The function “replace()”is used to return the new string resulting from replacing all the occurrences of old characters in the string with new characters.
  • The variable “str2” is assigned the string value “Gandalf the GRAY”...

j.

Explanation of Solution

Result of “str2.replace(“gray”, “white”)”:

  • The function “replace()”is used to return the new string resulting from replacing all the occurrences of old characters in the string with new characters.
  • The variable “str2” is assigned the string value “Gandalf the GRAY”.
  • The given expression “str2...

k.

Explanation of Solution

Result of “str1”.replace(“r”, “range”):

  • The function “replace()”is used to return the new string resulting from replacing all the occurrences of old characters  in the string with new characters.
  • In the given expression “str1” is the string...

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Students have asked these similar questions
Can you help me solve this problem using Master's Theorem:Solve the recurrence relation f(n) = 3af(n/a) + (n + a)2 with f(1) = 1 and a > 1 byfinding an expression for f(n) in big-Oh notation.
here is example 7.6## Example 7.6 Suppose the sample population is χ 2 (2), which is non-normal but with same variance 4. ▶ Repeat the simulation, but replacing the N(0, 4) samples with χ 2 (2) samples. ▶ Calculate the empirical confidence level.(Empirical confidence level) n <- 20 alpha <- 0.05 UCL <- replicate(1000, expr = { x <- rchisq(n,df=2) (n-1)*var(x)/qchisq(alpha,df=n-1) }) sum(UCL >4) mean(UCL > 4) ## t.test function n <- 20 x <- rnorm(n,mean=2) result <- t.test(x,mu=1) result$statistic result$parameter result$p.value result$conf.int result$estimate
using r language

Chapter 3 Solutions

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