Explanation Given: An object originally at 3 .0 m is brought to 30 cm from eye. Formula used: Write the expression for the thin lens equation for the first position of the object from eye. 1 u 1 + 1 v 1 = 1 f 1 Here, u 1 is the distance of the first object, v 1 is the distance of the first image and f 1 is the focal length of the eye for the first position of the object. Rewrite the above equation for calculate focal length for first position of object. f 1 = u 1 v 1 u 1 + v 1 ...... (1) Write the expression for the thin lens equation for the second position of the object from eye. 1 u 2 + 1 v 2 = 1 f 2 Here, u 2 is the distance of the second object, v 2 is the distance of the second image and f 2 is the focal length of the eye for the second position of the object. Rewrite the above equation for calculate focal length for first position of object. f 2 = u 2 v 2 u 2 + v 2 ...... (2) Write the changes of the focal length of the eye for two positions of the object. Δ f = f 2 − f 1 ...... (3) Here, Δ f is change of the focal length of the eye for the two positions of the object. Calculation: Substitute 3.0 m for u 1 , 2.5 cm for v 1 in equation (1)

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Chapter 32, Problem 63P

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Chapter 32, Problem 62P

Chapter 32, Problem 64P

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