Physics (5th Edition)
5th Edition
ISBN: 9780134051802
Author: Walker
Publisher: PEARSON
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Chapter 32, Problem 4CQ
To determine
The reason behind the different isotopes of a given element having same chemical properties.
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Chapter 32 Solutions
Physics (5th Edition)
Ch. 32.1 - Prob. 1EYUCh. 32.2 - A given nucleus can decay by alpha decay, beta...Ch. 32.3 - Prob. 3EYUCh. 32.4 - Prob. 4EYUCh. 32.5 - Prob. 5EYUCh. 32.6 - Prob. 6EYUCh. 32.7 - Prob. 7EYUCh. 32.8 - Prob. 8EYUCh. 32.9 - Prob. 9EYUCh. 32 - Prob. 1CQ
Ch. 32 - Prob. 2CQCh. 32 - Prob. 3CQCh. 32 - Prob. 4CQCh. 32 - Prob. 5CQCh. 32 - Prob. 6CQCh. 32 - Prob. 7CQCh. 32 - Prob. 8CQCh. 32 - Prob. 9CQCh. 32 - Prob. 1PCECh. 32 - Prob. 2PCECh. 32 - Prob. 3PCECh. 32 - Prob. 4PCECh. 32 - Prob. 5PCECh. 32 - Prob. 6PCECh. 32 - Prob. 7PCECh. 32 - Prob. 8PCECh. 32 - Prob. 9PCECh. 32 - Prob. 10PCECh. 32 - Prob. 11PCECh. 32 - Prob. 12PCECh. 32 - Prob. 13PCECh. 32 - Prob. 14PCECh. 32 - Prob. 15PCECh. 32 - Prob. 16PCECh. 32 - Prob. 17PCECh. 32 - Prob. 18PCECh. 32 - Prob. 19PCECh. 32 - Prob. 20PCECh. 32 - Prob. 21PCECh. 32 - Prob. 22PCECh. 32 - Prob. 23PCECh. 32 - Prob. 24PCECh. 32 - Prob. 25PCECh. 32 - Prob. 26PCECh. 32 - Prob. 27PCECh. 32 - Prob. 28PCECh. 32 - Suppose we were to discover that the ratio of...Ch. 32 - A radioactive sample is placed in a closed...Ch. 32 - Radon gas has a half-life of 3.82 d. What is the...Ch. 32 - Prob. 32PCECh. 32 - The number of radioactive nuclei in a particular...Ch. 32 - Prob. 34PCECh. 32 - Prob. 35PCECh. 32 - Prob. 36PCECh. 32 - Prob. 37PCECh. 32 - Prob. 38PCECh. 32 - Prob. 39PCECh. 32 - Prob. 40PCECh. 32 - Prob. 41PCECh. 32 - Prob. 42PCECh. 32 - Prob. 43PCECh. 32 - Prob. 44PCECh. 32 - Prob. 45PCECh. 32 - Prob. 46PCECh. 32 - Prob. 47PCECh. 32 - Prob. 48PCECh. 32 - Prob. 49PCECh. 32 - Prob. 50PCECh. 32 - Prob. 51PCECh. 32 - Prob. 52PCECh. 32 - Prob. 53PCECh. 32 - Prob. 54PCECh. 32 - Prob. 55PCECh. 32 - Consider a fusion reaction in which two deuterium...Ch. 32 - Prob. 57PCECh. 32 - Prob. 58PCECh. 32 - Prob. 59PCECh. 32 - Prob. 60PCECh. 32 - Prob. 61PCECh. 32 - Prob. 62PCECh. 32 - Prob. 63PCECh. 32 - Prob. 64PCECh. 32 - Prob. 65PCECh. 32 - Prob. 66PCECh. 32 - Prob. 67PCECh. 32 - Prob. 68GPCh. 32 - Prob. 69GPCh. 32 - Prob. 70GPCh. 32 - Prob. 71GPCh. 32 - Prob. 72GPCh. 32 - Prob. 73GPCh. 32 - Moon Rocks In one of the rocks brought back from...Ch. 32 - Prob. 75GPCh. 32 - Prob. 76GPCh. 32 - Prob. 77GPCh. 32 - Prob. 78GPCh. 32 - Prob. 79GPCh. 32 - Prob. 80GPCh. 32 - Prob. 81GPCh. 32 - Prob. 82GPCh. 32 - Prob. 83GPCh. 32 - Prob. 84GPCh. 32 - Prob. 85GPCh. 32 - Prob. 86GPCh. 32 - Prob. 87GPCh. 32 - Prob. 88GPCh. 32 - Prob. 89PPCh. 32 - Prob. 90PPCh. 32 - Prob. 91PP
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Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, physics and related others by exploring similar questions and additional content below.Similar questions
- (a) Calculate BE/A for 235U, the rarer of the two most common uranium isotopes. (b) Calculate BE/A for 238U. (Most of uranium is 238U.) Note that 238U has even numbers at both protons and neutrons. Is the BE/A of 238U significantly different from that of 235U?arrow_forwardSilver has two stable isotopes. The nucleus, 47107Ag , has atomic mass 106.905095 g/mol with an abundance of 51.83% ; whereas 47107Aghas atomic mass 108.904754 g/mol with an abundance of 48.17% . Find the atomic mass of the element silver.arrow_forward2H is a loosely hound isotope of hydrogen. Called deuterium or heavy hydrogen, it is stable but relatively rareit is 0.015% of natural hydrogen. Note that deuterium has Z = N, which should tend to make it more tightly bound, but both are odd numbers. Calculate BE/A, the binding energy per nucleon, for 2H and compare it with the approximate value obtained from line graph in Figure 31.27.arrow_forward
- Suppose you have a pure radioactive material with a half-life of T1/2. You begin with N0 undecayed nuclei of the material at t = 0. At t=12T1/2, how many of the nuclei have decayed? (a) 14N0 (b) 12N0(C) 34N0 (d) 0.707N0 (e) 0.293N0arrow_forwardA radioactive sample initially contains 2.40102 mol of a radioactive material whose half-life is 6.00 h. How many moles of the radioactive material remain after 6.00 h? After 12.0 h? After 36.0 h?arrow_forwardAccording to your lab partner, a 2.00-cm-thick sodium-iodide crystal absorbs all but 10% of lays from a radioactive source and a 4.00-cm piece of the same material absorbs all but 5%? Is this result reasonable?arrow_forward
- What are isotopes? Why do isotopes of the same atom share the same chemical properties?arrow_forwardWhy is the number of neutrons greater than the number of protons in stable nuclei that have an A greater than about 40? Why is this effect more pronounced for the heaviest nuclei?arrow_forwardData from the appendices and the periodic table may be needed for these problems. Construct Your Own Problem Consider the generation of electricity by a radioactive isotope in a space probe, such as described in Exercise 31.64. Construct a problem in which you calculate the mass of a radioactive isotope you need in order to supply power for a long space flight. Among the things to consider are the isotope chosen, its halflife and decay energy, the power needs of the probe and the length of the flight.arrow_forward
- Data from the appendices and the periodic table may be needed for these problems. Unreasonable Results (a) Repeat Exercise 31.57 but include the 0.0055% natural abundance of 234U with its 2.45105y halflife. (b) What is unreasonable about this result? (c) What assumption is responsible? (d) Where does the 234U come from if it is not primordial?arrow_forwardThe purpose of this problem is to show in three ways that the binding energy at the election in a hydrogen atom is negligible compared with the masses of the proton and electron. (a) Calculate the mass equivalent in u of the 13.6eV binding energy of an electron in a hydrogen atom, and compete this with the mass of the hydrogen atom obtained from Appendix A. (b) Subtract the mass at the proton given in Table 31.2 from the mass at the hydrogen atom given in Appendix A. You will find the difference is equal to the electron’s mass to three digits, implying the binding energy is small in comparison. (c) Take the ratio of the binding energy at the electron (13.6 eV) to the energy equivalent of the electron's mass (0.511 MeV). (d) Discuss how your answers confirm the stated purpose of this problem.arrow_forwardThe purpose of producing 99Mo (usually by neutron activation of natural molybdenum, as in the preceding problem) is to produce 99mTc. Using the rules, verily that the decay of 99Mo produces 99mTc. (Most 99mTc nuclei produced in this decay are left in a metastable excited state denoted 99mTc.)arrow_forward
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