An electric circuit, whether it’s a simple lightbulb or a complex amplifier, has two input terminals that are connected to the two output terminals of the voltage source. The impedance between the two input terminals (often a function of frequency) is the circuit’s input impedance. Most circuits are designed to have large input impedance. To see why, suppose you need to amplify the output of a high-pass filter that is constructed with a
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MASTERPHYS:KNIGHT'S PHYSICS ACCESS+WKB
- An PLC series circuit with R=600 , L = 30 mH. and c=0.050F is driven by an ac source whose frequency and voltage amplitude are 500 Hz and 50 V, respectively, (a) What is the impedance of the circuit? (b) What is the amplitude of the current in the circuit? (c) What is the phase angle between the emf of the source and the current?arrow_forwardAn ac source of voltage amplitude 100 V and frequency 1.0 kHz drives an PLC series circuit with R=20, L = 4.0 mH, and C=50F . (a) Determine the rms current through the circuit, (b) What are the rms voltages across the three elements? (c) What is the phase angle between the emf and the current? (d) What is the power output of the source? (e) What is the power dissipated in the resistor?arrow_forwardWhat is the impedance of a series combination of a 50resistor, a 5.0F capacitor, and a 10F capacitor at a frequency of 2.0 kHz?arrow_forward
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- A 6.0-µF capacitor is connected to an ac signal with a frequency of 60 Hz. If the maximum voltage applied to the capacitor is 8.0 V, what is its capacitive reactance? O 160 Q O 7.5 x 1062 O 740 Q 1 O 6.0 Q O 440 Qarrow_forwardA simple circuit with R = 50N, and L= 200 mH, would be O A low-pass filter with f0 = 40 Hz O A low-pass filter with f0 = 250 Hz O A high-pass filter with f0 = 40 Hz O A high-pass filter with f0 250 Hzarrow_forwardA sine-wave voltage source drives the circuit. This question attempts to measure the capacitance. You may use I = dQ/dt with VC = Q/C. Alternatively, you may use the capacitive reactance, XC = 1/ωC. The current in the circuit is I = I0*cos(ωt). You use the oscilloscope to measure the peak-to-peak voltage for the capacitor (VCp), and then for the resistor (VRp). Knowing the frequency (ω) and the resistance (R), one can (in theory) calculate the capacitance. Calculate the capacitance (in microfarads, μF = 10-6 F). These are the numbers: VCp = 15 volts VRp = 10 volts ω = 7,814 rad/s R = 608 ohmsarrow_forward
- Physics for Scientists and Engineers: Foundations...PhysicsISBN:9781133939146Author:Katz, Debora M.Publisher:Cengage LearningPhysics for Scientists and Engineers, Technology ...PhysicsISBN:9781305116399Author:Raymond A. Serway, John W. JewettPublisher:Cengage Learning