Bisection Method for Approximating Zeros of a Function f We begin with two consecutive integers, a and a + 1 , such that f ( a ) and f ( a + 1 ) are of opposite sign. Evaluate f at the midpoint m 1 of a and a + 1 . If f ( m 1 ) = 0 . then m 1 is the zero of f , and we are finished. Otherwise, f ( m 1 ) is of opposite sign to either f ( a ) or f ( a + 1 ) . Suppose that it is f ( a ) and f ( m 1 ) that are of opposite sign. Now evaluate f at the midpoint m 2 of a and m 1 . Repeat this process until the desired degree of accuracy is obtained. Note that each iteration places the zero in an interval whose length is half that of the previous interval. Use the bisection method to approximate the zero of f ( x ) = 8 x 4 − 2 x 2 + 5 x − 1 in the interval [ 0 , 1 ] correct to three decimal places. Verify your result using a graphing utility. [ Hint: The process ends when both endpoints agree to the desired number of decimal places.]
Bisection Method for Approximating Zeros of a Function f We begin with two consecutive integers, a and a + 1 , such that f ( a ) and f ( a + 1 ) are of opposite sign. Evaluate f at the midpoint m 1 of a and a + 1 . If f ( m 1 ) = 0 . then m 1 is the zero of f , and we are finished. Otherwise, f ( m 1 ) is of opposite sign to either f ( a ) or f ( a + 1 ) . Suppose that it is f ( a ) and f ( m 1 ) that are of opposite sign. Now evaluate f at the midpoint m 2 of a and m 1 . Repeat this process until the desired degree of accuracy is obtained. Note that each iteration places the zero in an interval whose length is half that of the previous interval. Use the bisection method to approximate the zero of f ( x ) = 8 x 4 − 2 x 2 + 5 x − 1 in the interval [ 0 , 1 ] correct to three decimal places. Verify your result using a graphing utility. [ Hint: The process ends when both endpoints agree to the desired number of decimal places.]
Solution Summary: The author explains the bisection method to approximate the zero of f ( x ) = 8 2 / 2 + 5 in the interval.
Bisection Method for Approximating Zeros of a Function
We begin with two consecutive integers,
and
, such that
and
are of opposite sign. Evaluate
at the midpoint
of
and
. If
. then
is the zero of
, and we are finished. Otherwise,
is of opposite sign to either
or
. Suppose that it is
and
that are of opposite sign. Now evaluate
at the midpoint
of
and
. Repeat this process until the desired degree of accuracy is obtained. Note that each iteration places the zero in an interval whose length is half that of the previous interval. Use the bisection method to approximate the zero of
in the interval
correct to three decimal places. Verify your result using a graphing utility.
[Hint: The process ends when both endpoints agree to the desired number of decimal places.]
Use the information to find and compare Δy and dy. (Round your answers to four decimal places.)
y = x4 + 7 x = −3 Δx = dx = 0.01
Δy =
dy =
4. A car travels in a straight line for one hour. Its velocity, v, in miles per hour at six minute intervals is shown
in the table. For each problem, approximate the distance the car traveled (in miles) using the given method,
on the provided interval, and with the given number of rectangles or trapezoids, n.
Time (min) 0 6 12 18|24|30|36|42|48|54|60
Speed (mph) 0 10 20 40 60 50 40 30 40 40 65
a.) Left Rectangles, [0, 30] n=5
b.) Right Rectangles, [24, 42] n=3
c.) Midpoint Rectangles, [24, 60] n=3
d.) Trapezoids, [0, 24] n=4
The bracket BCD is hinged at C and attached to a control cable at B. Let F₁ = 275 N and F2 = 275 N.
F1
B
a=0.18 m
C
A
0.4 m
-0.4 m-
0.24 m
Determine the reaction at C.
The reaction at C
N Z
F2
D
Chapter 3 Solutions
Pearson eText for Precalculus: Concepts Through Functions, A Right Triangle Approach to Trigonometry -- Instant Access (Pearson+)
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, calculus and related others by exploring similar questions and additional content below.