Bundle: Principles of Physics: A Calculus-Based Text, 5th + WebAssign Printed Access Card for Serway/Jewett's Principles of Physics: A Calculus-Based Text, 5th Edition, Multi-Term
5th Edition
ISBN: 9781133422013
Author: Raymond A. Serway; John W. Jewett
Publisher: Cengage Learning
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Question
Chapter 31, Problem 9CQ
To determine
The number of quarks in each particle. The explanation for which baryons have half-intergral spin and mesons have spins 0 or 1.
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(a) Three quarks form a baryon. How many combinations of the six known quarks are there if all combinations are possible?(b) This number is less than the number of known baryons.Explain why.
Give three (3) combinations of quarks (not antiquarks!) that will give baryons with the following charges. (Select all that apply.)
(a) charge +1
ccd
ddd
ccb
dst
uud
ddt
bbd
(b) charge −1
ttd
sss
bbb
bbc
bbs
sbu
ctd
(c) charge 0
sbc
ddb
ucs
tts
bbt
ssb
ddu
Give three (3) combinations of quarks (not antiquarks!) that will give baryons with the following charges. (Select all that apply.)
(a) charge +1
O bbd
st
uub
SS
ucb
ddt
ctd
(b) charge -1
O ssd
ucs
bbt
cts
bbb
dsc
bbs
(c) charge 0
dds
dsu
SSC
dsb
ttd
ddu
ctb
Chapter 31 Solutions
Bundle: Principles of Physics: A Calculus-Based Text, 5th + WebAssign Printed Access Card for Serway/Jewett's Principles of Physics: A Calculus-Based Text, 5th Edition, Multi-Term
Ch. 31.2 - Given the identification of the particles in...Ch. 31.5 - Prob. 31.2QQCh. 31.5 - Prob. 31.3QQCh. 31.5 - Prob. 31.4QQCh. 31.9 - Prob. 31.5QQCh. 31 - Prob. 1OQCh. 31 - Prob. 2OQCh. 31 - Prob. 3OQCh. 31 - Prob. 4OQCh. 31 - Prob. 5OQ
Ch. 31 - Prob. 6OQCh. 31 - Prob. 7OQCh. 31 - Prob. 8OQCh. 31 - Prob. 1CQCh. 31 - Prob. 2CQCh. 31 - Prob. 3CQCh. 31 - Prob. 4CQCh. 31 - Prob. 5CQCh. 31 - Prob. 6CQCh. 31 - Prob. 7CQCh. 31 - Prob. 8CQCh. 31 - Prob. 9CQCh. 31 - Prob. 10CQCh. 31 - Prob. 11CQCh. 31 - Prob. 12CQCh. 31 - Prob. 13CQCh. 31 - Prob. 1PCh. 31 - Prob. 2PCh. 31 - Prob. 3PCh. 31 - Prob. 4PCh. 31 - Prob. 5PCh. 31 - Prob. 6PCh. 31 - Prob. 7PCh. 31 - Prob. 8PCh. 31 - Prob. 9PCh. 31 - Prob. 10PCh. 31 - Prob. 11PCh. 31 - Prob. 12PCh. 31 - Prob. 13PCh. 31 - Prob. 14PCh. 31 - Prob. 15PCh. 31 - Prob. 16PCh. 31 - Prob. 17PCh. 31 - Prob. 18PCh. 31 - Prob. 19PCh. 31 - Prob. 20PCh. 31 - Prob. 21PCh. 31 - Prob. 22PCh. 31 - Prob. 23PCh. 31 - Prob. 24PCh. 31 - Prob. 25PCh. 31 - Prob. 26PCh. 31 - Prob. 27PCh. 31 - Prob. 28PCh. 31 - Prob. 29PCh. 31 - Prob. 30PCh. 31 - Prob. 31PCh. 31 - Prob. 32PCh. 31 - Prob. 33PCh. 31 - Prob. 34PCh. 31 - Prob. 35PCh. 31 - Prob. 36PCh. 31 - Prob. 37PCh. 31 - Prob. 38PCh. 31 - Prob. 39PCh. 31 - Prob. 40PCh. 31 - Prob. 41PCh. 31 - Prob. 42PCh. 31 - Prob. 43PCh. 31 - Prob. 44PCh. 31 - Prob. 45PCh. 31 - Prob. 46PCh. 31 - Prob. 47PCh. 31 - Prob. 48PCh. 31 - Prob. 49PCh. 31 - Prob. 50PCh. 31 - Prob. 51PCh. 31 - Prob. 52PCh. 31 - Prob. 53PCh. 31 - Prob. 54PCh. 31 - Prob. 55PCh. 31 - Prob. 56PCh. 31 - Prob. 57PCh. 31 - Prob. 58PCh. 31 - Prob. 59PCh. 31 - Prob. 60PCh. 31 - Prob. 61PCh. 31 - Prob. 62PCh. 31 - Prob. 63PCh. 31 - Prob. 64PCh. 31 - Prob. 65P
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- (a) Is a hadron always a baryon? (b) Is a baryon always a hadron? (c) Can an unstable baryon decay into a meson, leaving no other baryon?arrow_forward(a) Three quarks form a baryon. How many combinations of the six known quarks are there if all combinations are possible? (b) This number is less than the number of known baryons. Explain why.arrow_forward(a) Show than all combinations of three quarks produce integral changes. Thus baryons must have integral charge. (b) Show than all combinations at a quark and an antiquark produce only integral charges. Thus mesons must have integral change.arrow_forward
- (a) Show that the conjectured decay of the proton, violates conservation of baryon number and conservation of lepton number. (b) What is the analogous decay process for the antiproton?arrow_forward(a) Is the decay possible considering the appropriate conservation laws? State why or why not. (b) Write the decay in terms of the quark constituents of the particles.arrow_forwardThe K0 meson is an uncharged member of the particle “zoo” that decays into two charged pions according to K0 → π+ + π−. The pions have opposite charges, as indicated, and the same mass, mπ = 140 MeV/c2. Suppose that a K0 at rest decays into two pions in a bubble chamber in which a magnetic field of 2.0 T is present (see Fig. P2.22). If the radius of curvature of the pions is 34.4 cm, find (a) the momenta and speeds of the pions and (b) the mass of the K0 meson.arrow_forward
- The primary decay mode for the negative pion is +v . (a) What is the energy release in MeV in this decay? (b) Using conservation of momentum, how much energy does each of the decay products receive, given the is at rest when it decays? You may assume the muon antineutrino is massless and has momentum p = E/c , just like a photon.arrow_forward(a) Do all particles having strangeness also have at least one strange quark in them? (b) Do all hadrons with a strange quark also have nonzero strangeness?arrow_forwardExplain how conservation of baryon number is responsible for conservation of total atomic mass (total number at nucleons) in nuclear decay and reactions.arrow_forward
- (a) Estimate the mass of the luminous matter in the known universe, given there are 1011 galaxies, each containing 1011 stars of average mass 1.5 times that of our Sun. (b) How many protons (the most abundant nuclide) are there in this mates? (c) Estimate the total number of particles in the observable universe by multiplying the answer to (b) by two, since there is an electron for each proton, and then by 109, since there are far more particles (such as photons and neutrinos) in space than in luminous matter.arrow_forwardThe reaction (described in the preceding problem) takes place via the strong force. (a) What is the baryon number of the particle? (b) Draw a Feynman diagram of the reaction showing the individual quarks involved.arrow_forward(a) Is the decay possible considering the appropriate conservation laws? Stale why or why not. (b) Write the decay in terms of the quark constituents of the particles.arrow_forward
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