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Chapter 31, Problem 29P
To determine

The travelled distance.

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In the figure below, a semicircular conductor of radius R = 0.260 m is rotated about the axis AC at a constant rate of 130 rev/min. A uniform magnetic field of magnitude 1.22 T fills the entire region below the axis and is directed out of the page. In this illustration, a wire extends straight to the right from point A, then curves up and around in a semicircle of radius R. On the right side of the semicircle, the wire continues straight to the right to point C. The wire lies in the plane of the page, in a region of no magnetic field. Directly below the axis A C is a region of uniform magnetic field pointing out of the page, vector Bout. If viewed from the right, the wire can rotate counterclockwise, so that the semicircular part can rotate into the region of magnetic field. (a) Calculate the maximum value of the emf induced between the ends of the conductor.  V(b) What is the value of the average induced emf for each complete rotation? Consider carefully whether the correct answer is…
A coil of 15 turns and radius 10.0 cm surrounds a long solenoid of radius 2.20 cm and 1.00  103 turns/meter (see figure below). The current in the solenoid changes as I = 6.00 sin(120t), where I is in amperes and t is in seconds. Find the induced emf (in volts) in the 15-turn coil as a function of time. (Do not include units in your answer.) =
A coil of 15 turns and radius 10.0 cm surrounds a long solenoid of radius 1.80 cm and 1.00  103 turns/meter (see figure below). The current in the solenoid changes as I = 5.00 sin(120t), where I is in amperes and t is in seconds. Find the induced emf (in volts) in the 15-turn coil as a function of time. (Do not include units in your answer.) =

Chapter 31 Solutions

Bundle: Principles of Physics: A Calculus-Based Text, 5th + WebAssign Printed Access Card for Serway/Jewett's Principles of Physics: A Calculus-Based Text, 5th Edition, Multi-Term

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Time Dilation - Einstein's Theory Of Relativity Explained!; Author: Science ABC;https://www.youtube.com/watch?v=yuD34tEpRFw;License: Standard YouTube License, CC-BY