Radioactive decay. A cesium isotope has a half-life of 30 years. What is the continuous compound rate of decay? (Use the radioactive decay model in Problem 43.) 43. Radioactive decay. A mathematical model for the decay of radioactive substances is given by Q = Q 0 e r t where Q 0 = amount of the substance at time t = 0 r = continuous compound rate of decay t = time in years Q = amount of the substance at time t If the continuous compound rate of decay of radium per year is r = −0.000 433 2, how long will it take a certain amount of radium to decay to half the original amount? (This period is the half-life of the substance.)
Radioactive decay. A cesium isotope has a half-life of 30 years. What is the continuous compound rate of decay? (Use the radioactive decay model in Problem 43.) 43. Radioactive decay. A mathematical model for the decay of radioactive substances is given by Q = Q 0 e r t where Q 0 = amount of the substance at time t = 0 r = continuous compound rate of decay t = time in years Q = amount of the substance at time t If the continuous compound rate of decay of radium per year is r = −0.000 433 2, how long will it take a certain amount of radium to decay to half the original amount? (This period is the half-life of the substance.)
Solution Summary: The author explains the rate of decay r of cesium isotope has a half-life of 30 years.
Radioactive decay. A cesium isotope has a half-life of 30 years. What is the continuous compound rate of decay? (Use the radioactive decay model in Problem 43.)
43. Radioactive decay. A mathematical model for the decay of radioactive substances is given by
Q
=
Q
0
e
r
t
where
Q
0
=
amount
of
the
substance
at
time
t
=
0
r
=
continuous
compound
rate
of
decay
t
=
time
in
years
Q
=
amount
of
the
substance
at
time
t
If the continuous compound rate of decay of radium per year is r = −0.000 433 2, how long will it take a certain amount of radium to decay to half the original amount? (This period is the half-life of the substance.)
موضوع الدرس
Prove that
Determine the following groups
Homz(QZ) Hom = (Q13,Z)
Homz(Q), Hom/z/nZ, Qt
for neN-
(2) Every factor group of
adivisible group is divisble.
• If R is a Skew ficald (aring with
identity and each non Zero element is
invertible then every R-module is free.
A: Tan Latitude / Tan P
A = Tan 04° 30'/ Tan 77° 50.3'
A= 0.016960 803 S CA named opposite to latitude,
except when hour angle between 090° and 270°)
B: Tan Declination | Sin P
B Tan 052° 42.1'/ Sin 77° 50.3'
B = 1.34 2905601 SCB is alway named same as
declination)
C = A + B = 1.35 9866404 S CC correction, A+/- B:
if A and B have same name - add, If
different name- subtract)
=
Tan Azimuth 1/Ccx cos Latitude)
Tan Azimuth = 0.737640253
Azimuth
=
S 36.4° E CAzimuth takes combined
name of C correction and Hour Angle - If LHA
is between 0° and 180°, it is named "west", if
LHA is between 180° and 360° it is named "east"
True Azimuth= 143.6°
Compass Azimuth = 145.0°
Compass Error = 1.4° West
Variation 4.0 East
Deviation: 5.4 West
A: Tan Latitude / Tan P
A = Tan 04° 30'/ Tan 77° 50.3'
A= 0.016960 803 S CA named opposite to latitude,
except when hour angle between 090° and 270°)
B: Tan Declination | Sin P
B Tan 052° 42.1'/ Sin 77° 50.3'
B = 1.34 2905601 SCB is alway named same as
declination)
C = A + B = 1.35 9866404 S CC correction, A+/- B:
if A and B have same name - add, If
different name- subtract)
=
Tan Azimuth 1/Ccx cos Latitude)
Tan Azimuth = 0.737640253
Azimuth
=
S 36.4° E CAzimuth takes combined
name of C correction and Hour Angle - If LHA
is between 0° and 180°, it is named "west", if
LHA is between 180° and 360° it is named "east"
True Azimuth= 143.6°
Compass Azimuth = 145.0°
Compass Error = 1.4° West
Variation 4.0 East
Deviation: 5.4 West
Chapter 3 Solutions
Calculus for Business, Economics, Life Sciences, and Social Sciences (13th Edition)
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