
Concept explainers
(a)
Interpretation:
The type of the glycogen synthesis mechanism should be determined.
Concept introduction:
Glycogen synthesis is the process of formation of glycogen from the glucose monomer units. By this process, glucose is stored in the liver cells in the form of glycogen biomacromolecule. This reaction is catalyzed by the glycogen synthase enzyme. The main hormone behind this process is insulin, which signals liver cells to take up glucose and convert it into glycogen.
(b)
Interpretation:
The type of the fatty acid synthesis mechanism should be determined.
Concept introduction:
Fatty acid is an aliphatic
(c)
Interpretation:
The type of mechanism followed by cholesterol synthesis.
Concept introduction:
Cholesterol is the sterol, which is mainly found in animal tissues. In the tissues and blood plasma, cholesterol is found in the free state or bound with the fatty acid chain to form cholesteryl ester. It is formed by fusing four rings together and plays various functions in the human body.
(d)
Interpretation:
The mechanism followed by DNA synthesis process.
Concept introduction:
The building block of DNA and RNA is termed as the nucleotides. Nucleotides are the organic molecules, that plays important roles during cell signaling, enzymatic reactions, and
(e)
Interpretation:
The mechanism followed by RNA synthesis process.
Concept introduction:
The building block of DNA and RNA is termed as the nucleotides. Nucleotides are the organic molecules, that plays important roles during cell signaling, enzymatic reactions, and metabolic reactions. It contains a phosphate group, a ribose sugar, and a nitrogenous base (pyrimidine or purine).
(f)
Interpretation:
Type of mechanism followed by protein synthesis.
Concept introduction:
Protein synthesis (translation) is a process of generating new protein sequences inside the cell. This process takes place in the cytoplasm of the cell. this process is balanced by the degradation or export of cellular proteins. It is constituted of three steps, initiation, elongation, and termination.

Want to see the full answer?
Check out a sample textbook solution
Chapter 31 Solutions
Biochemistry
- 12:33 CO Problem 8 of 15 4G. 53% Submit Using the following reaction data points, construct a Lineweaver-Burk plot by dragging the points to their relevant coordinates on the graph and drawing a line of best fit. Based on the plot, determine the value of kcat given that the enzyme concentration in this experiment is 5.0 μM. 1 [S] , мм -1 1 V₁ s μM 1 100.0 0.100 75.0 0.080 50.0 0.060 15.0 0.030 10.0 0.025 5.0 0.020 Answer: ||| Гarrow_forward1:33 5G. 46% Problem 12 of 15 Submit Using the following reaction data points, construct a Lineweaver-Burk plot for an enzyme with and without an uncompetitive inhibitor by dragging the points to their relevant coordinates on the graph and drawing a line of best fit. 1 -1 1 mM [S]' 20 V' s mM¹ with 10 μg per 54 10 36 > ст 5 27 2.5 23 1.25 20 Answer: |||arrow_forward12:33 CO Problem 7 of 15 4G. 53% Submit Using the following reaction data points, construct a Lineweaver-Burk plot by dragging the points to their relevant coordinates on the graph and drawing a line of best fit. Based on the plot, determine the value of Vmax. Report your answer to three significant figures. 1 , mM-1 1 [S] V' sμM-¹ 100.0 0.100 75.0 0.080 50.0 0.060 15.0 0.030 10.0 0.025 5.0 0.020 Answer: ||| Гarrow_forward
- 12:33 CO Problem 5 of 15 4G 54% Done On the following Lineweaver-Burk 1 plot, identify the by dragging the Vmax point to the appropriate value on the line. NI 35 30- 25 20- 15- 10 5. 1 Vmax -15 10 -5 0 5 10 15 20 20 ||| で Г 25 30 1/[S]arrow_forward12:20 V 0.1- 0:09. 0.08 0:07 0.06 -0.05- 0:04- -0.03- -0.02- 4G 56% Problem 1 of 15 Done On the following Michaelis-Menten plot, estimate the value of - Vmax by 1 2 dragging the line to the appropriate value on the y-axis. 0.01 V max 0 0.5 ||| 1.5 2.5 3.5 4 ISLarrow_forward12:33 CO 4G 54% Problem 6 of 15 Submit Using the following reaction data points, construct a Lineweaver-Burk plot by dragging the points to their relevant coordinates on the graph and drawing a line of best fit. Based on the plot, determine the Km. 1 mM-1 1 [S]' " s mM-1 V 100.0 0.100 75.0 0.080 50.0 0.060 15.0 0.030 10.0 0.025 5.0 0.020 Answer: ||| Гarrow_forward
- V 0.1- 0:09 0:08 0:07- -0.06 -0.05 0:04- 0:03 0:02 0:01- Problem 2 of 15 Done On the following Michaelis-Menten plot, estimate the value of Kм by dragging the point to the appropriate value on the x-axis. I T | 0 0.5 1.5 2 KM -0:01- ||| 25 2.5 3 3.5 4 Г [S] powered by desmosarrow_forward9. Sketch NMR of the following compound. Clearly label each H-atom in the molecule and where it appears in your NMR. Clearly label the splitting (coupling) pattern (singlet, doublet etc) for each set of equivalent protons. For each signal, clearly label the integration value or the number of protons represented by the signal. Brarrow_forwardPlease help with this Mass Spectrometry Question. Thank you For the mass spec. shown in the attached image, please determine and give the amino acid sequence of the pentapeptide. Show which end is the amino terminus and which is the carboxy terminus. How does one arrive at the solution?arrow_forward
- Draw a tripeptide of your choosing at pH 7. Have the N-terminus on the left and the C-terminus on the right. Then: Draw a triangle around the α-carbons. Draw a box around the R-groups. Circle the atoms capable of hydrogen bonding. Highlight the atoms involved in the formation of the peptide bonds. What type of structure have you drawn? (primary, secondary, tertiary or quaternary protein structure).arrow_forward2. For the flow of fluid over a flat membrane of length 10cm, determine the length-average mass transfer coefficient. The relevant properties of the system are u=0.01cm²/s, D=5 x 106 cm²/s, and v = 5.0 cm/s.arrow_forwardBackground Freezing isn't the only challenge in cryopreservation - thawing can be just as difficult. A microwave oven seems like a nice solution, since it deposits energy quickly and microwaves are non-ionizing radiation (they do not cause DNA mutation). However, water absorbs microwaves more effectively than ice does, meaning that the portion of an organ that has already melted will get warmer at a higher rate than the remaining ice – the opposite of what we want! - The transmission of radiation through a weakly absorbing material such as ice or water can be modeled by Beer's law, which assumes that the rate of absorption at a depth x is proportional to the local radiation intensity I(x) times an absorption coefficient, which is often written as μ or a or just µ). Noting that absorption decreases the intensity, we can write a differential equation a Solving the differential equation with the boundary condition on the surface being gives the relationship For a standard microwave oven…arrow_forward
- BiochemistryBiochemistryISBN:9781305577206Author:Reginald H. Garrett, Charles M. GrishamPublisher:Cengage LearningBiology: The Dynamic Science (MindTap Course List)BiologyISBN:9781305389892Author:Peter J. Russell, Paul E. Hertz, Beverly McMillanPublisher:Cengage LearningBiology: The Unity and Diversity of Life (MindTap...BiologyISBN:9781305073951Author:Cecie Starr, Ralph Taggart, Christine Evers, Lisa StarrPublisher:Cengage Learning
- Human Heredity: Principles and Issues (MindTap Co...BiologyISBN:9781305251052Author:Michael CummingsPublisher:Cengage LearningBiology (MindTap Course List)BiologyISBN:9781337392938Author:Eldra Solomon, Charles Martin, Diana W. Martin, Linda R. BergPublisher:Cengage LearningBiochemistryBiochemistryISBN:9781305961135Author:Mary K. Campbell, Shawn O. Farrell, Owen M. McDougalPublisher:Cengage Learning





