Explanation Kinetic energy is an energy of motion. The amount of kinetic energy that all moving objects have depends on their speed and mass. The kinetic energy is calculated by the formula, K E = − 13.6 eV n 2 Here, n is the principal quantum number (energy state). Substitute the given value of n ( 4 ) in the above equation to find K E . K E = − 13.6 eV n 2 = − 13.6 4 2 = 0.85 J The conversion of energy from J to eV is done as, 1.6 × 10 − 19 J = 1 eV 1 J = 1 1.6 × 10 − 19 eV 0.85 J = 1 1.6 × 10 − 19 × 0.85 = 0.053 eV Therefore, the kinetic energy of the hydrogen atom is 0.053 eV . The other formula for calculating the kinetic energy is given as, K E = 1 2 m v 2 Here, m is the mass of the atom. v is the speed of the hydrogen atom

5th Edition

ISBN: 8220103026918

Author: Walker

Publisher: PEARSON

See similar textbooks

Concept explainers

The Bohr model

Students often get confused between Rutherford’s model and Bohr model of an atom. They interpret the postulates of both these models to be the same, which is incorrect. Rutherford’s model differs from Bohr’s model in the following ways:

Question

Chapter 31, Problem 32PCE

To determine

The minimum speed necessary to leave both hydrogen atoms in their n=4 state after the head-on collision.

Expert Solution & Answer

Want to see the full answer?

Check out a sample textbook solution

See solution

Chapter 31, Problem 31PCE

Chapter 31, Problem 33PCE

Students have asked these similar questions

Consider a head-on collision between two hydrogen atoms, both initially in their ground state and moving with the same speed. Find the minimum speed necessary to leave both atoms in their n = 4 state after the collision

Consider a head-on collision between two hydrogen atoms,both initially in their ground state and moving with the sameaspeed. Find the minimum speed necessary to leave both atoms intheir n = 4 state after the collision.

(a) How much energy is required to cause an electron in hydrogen to move from the n = 2 state to the n = 5 state? in J(b) Suppose the atom gains this energy through collisions among hydrogen atoms at a high temperature. At what temperature would the average atomic kinetic energy 3/2 * kBT be great enough to excite the electron? Here kB is Boltzmann's constant. in K

Chapter 31 Solutions

EBK PHYSICS

Ch. 31.1 - Prob. 1EYU Ch. 31.2 - Prob. 2EYU Ch. 31.3 - Prob. 3EYU Ch. 31.4 - Prob. 4EYU Ch. 31.5 - Prob. 5EYU Ch. 31.6 - Prob. 6EYU Ch. 31.7 - Prob. 7EYU Ch. 31 - Prob. 1CQ Ch. 31 - Prob. 2CQ Ch. 31 - Prob. 3CQ

Ch. 31 - Prob. 4CQ Ch. 31 - Prob. 5CQ Ch. 31 - Prob. 6CQ Ch. 31 - Prob. 7CQ Ch. 31 - Prob. 8CQ Ch. 31 - Prob. 9CQ Ch. 31 - Prob. 1PCE Ch. 31 - Prob. 2PCE Ch. 31 - Prob. 3PCE Ch. 31 - Prob. 4PCE Ch. 31 - Prob. 5PCE Ch. 31 - Prob. 6PCE Ch. 31 - Prob. 7PCE Ch. 31 - Prob. 8PCE Ch. 31 - Prob. 9PCE Ch. 31 - Prob. 10PCE Ch. 31 - Prob. 11PCE Ch. 31 - Prob. 12PCE Ch. 31 - Prob. 13PCE Ch. 31 - Prob. 14PCE Ch. 31 - Prob. 15PCE Ch. 31 - Prob. 16PCE Ch. 31 - Prob. 17PCE Ch. 31 - Prob. 18PCE Ch. 31 - Prob. 19PCE Ch. 31 - Prob. 20PCE Ch. 31 - Prob. 21PCE Ch. 31 - Prob. 22PCE Ch. 31 - Prob. 23PCE Ch. 31 - Prob. 24PCE Ch. 31 - Prob. 25PCE Ch. 31 - Prob. 26PCE Ch. 31 - Prob. 27PCE Ch. 31 - Prob. 28PCE Ch. 31 - Prob. 29PCE Ch. 31 - Prob. 30PCE Ch. 31 - Prob. 31PCE Ch. 31 - Prob. 32PCE Ch. 31 - Prob. 33PCE Ch. 31 - Prob. 34PCE Ch. 31 - Prob. 35PCE Ch. 31 - Prob. 36PCE Ch. 31 - Prob. 37PCE Ch. 31 - Prob. 38PCE Ch. 31 - Prob. 39PCE Ch. 31 - Prob. 40PCE Ch. 31 - Prob. 41PCE Ch. 31 - Prob. 42PCE Ch. 31 - Prob. 43PCE Ch. 31 - Prob. 44PCE Ch. 31 - Prob. 45PCE Ch. 31 - Prob. 46PCE Ch. 31 - Prob. 47PCE Ch. 31 - Prob. 48PCE Ch. 31 - Prob. 49PCE Ch. 31 - Prob. 50PCE Ch. 31 - Prob. 51PCE Ch. 31 - Prob. 52PCE Ch. 31 - Give the electronic configuration for the ground...Ch. 31 - Prob. 54PCE Ch. 31 - Prob. 55PCE Ch. 31 - Prob. 56PCE Ch. 31 - The configuration of the outer electrons in Ni is...Ch. 31 - Prob. 58PCE Ch. 31 - Prob. 59PCE Ch. 31 - Prob. 60PCE Ch. 31 - Prob. 61PCE Ch. 31 - Prob. 62PCE Ch. 31 - Prob. 63PCE Ch. 31 - Prob. 64PCE Ch. 31 - Prob. 65PCE Ch. 31 - Prob. 66PCE Ch. 31 - Prob. 67PCE Ch. 31 - Prob. 68GP Ch. 31 - Prob. 69GP Ch. 31 - Prob. 70GP Ch. 31 - Prob. 71GP Ch. 31 - Prob. 72GP Ch. 31 - Prob. 73GP Ch. 31 - Prob. 74GP Ch. 31 - Prob. 75GP Ch. 31 - Prob. 76GP Ch. 31 - Prob. 77GP Ch. 31 - Prob. 78GP Ch. 31 - Prob. 79GP Ch. 31 - Prob. 80GP Ch. 31 - Prob. 81GP Ch. 31 - Prob. 82GP Ch. 31 - Prob. 83GP Ch. 31 - Prob. 84PP Ch. 31 - Prob. 85PP Ch. 31 - Prob. 86PP Ch. 31 - Prob. 87PP Ch. 31 - Prob. 88PP Ch. 31 - Prob. 89PP

Knowledge Booster

Learn more about

Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, physics and related others by exploring similar questions and additional content below.

The minimum speed necessary to leave both hydrogen atoms in their n = 4 state after the head-on collision.

Solution Summary: The author explains that kinetic energy is an energy of motion.

Concept explainers

The minimum speed necessary to leave both hydrogen atoms in their n=4 state after the head-on collision.

Want to see the full answer?

Chapter 31 Solutions