Explanation Given Info: The number of photons emitted by laser per second is 1.49 × 10 19 . The wavelength of half of the photons is 488.0 nm and wavelength of other half of photon is 514.5 nm . The power of laser is, P = h c p 2 ( 1 λ 1 + 1 λ 2 ) Here, h is the Planck’s constant. c is the speed of light . p is the number of photons. λ 1 is the wavelength of first half of photons. λ 2 is the wavelength of second half of photon. The Planck’s constant is 6.63 × 10 − 34 J ⋅ s . The speed of light is 3 × 10 8 m / s . Substitute 6.63 × 10 − 34 J ⋅ s for h , 3 × 10 8 m / s for c , 1.49 × 10 19 for p , 488 × 10 − 9 m for λ 1 and 514

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Chapter 31, Problem 84PP

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The power output of the laser in watts.

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Chapter 31, Problem 83GP

Chapter 31, Problem 85PP

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Suppose an argon laser emits 1.49 * 1019 photons per second,half with a wavelength of 488.0 nm and half with a wavelength of514.5 nm. What is the power output of this laser in watts?A. 1.49 W B. 5.76 WC. 5.92 W D. 6.07 W

10% of the energy supplied to a bulb is radiated as visible light. How many photons are emitted per second by a 50 W bulb? Take the wavelength of visible light as 660 nm. A. 2.66 x 1019 B. 1.66 x 1020 C. 1.66 x 1019 D. 2.66 x 1020

Plus dye laser emits light of energy of photon 3.6 eV in 0.25 ms pulses to remove skin blemishes such as birthmarks. Suppose that the output of one such laser is 15.0W. How many photons are delivered during that pulse? A. 2.13 x 10¹4. B. 4.10 x 10¹4. C. 6.50 x 1015. D. 8.00 x 1015.

Chapter 31 Solutions

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