Principles of Instrumental Analysis
7th Edition
ISBN: 9781305577213
Author: Douglas A. Skoog, F. James Holler, Stanley R. Crouch
Publisher: Cengage Learning
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Question
Chapter 31, Problem 31.3QAP
Interpretation Introduction
Interpretation:
Thermogravimetric curve is to be determined from the given mass and melting point.
Concept introduction:
Thermogravimetric curve is a plot ofthe percentage of mass and temperature, comprising of a progression of a numbers of steps, acquired by estimating the mass of a sample during heating. It is a strategy used for heat calculation where the mass of a sample is estimated after some time as the temperature changes.
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Use the standard reaction energies given below to determine AG*rxn for the
following reaction:
XY4(g) + Y₂O(g) --> XO(g) + 3Y2(g)
Given: 2Y2(g) + XO(g) --> XY3OY(1)
2XY4(g) + O2(g) --> 2XY3OY(1)
2Y2(g) + O2(g) --> 2Y2O(g)
Give answer in KJ/mol. Give answer to two decimal places. Do not include units
answer.
DG = -155.61 kJxmol-1
DG = -139.48 kJxmol-1
DH° -147.08 kJxmol-1
Kk.41.
Calculate AS values for the following reactions by using tabulated Sº values from Appendix C..
(a) C₂H4(9) + H₂(g) = C₂H6(9)
Asº =
J/K
(b) 2 CH₂OH(g) + 3 0₂(g) = 2 CO₂(g) + 4H₂O(g)
AS⁰ =
3/K
(c) 2 PC13(g) + O₂(g) =2 POCI3(9)
AS⁰ =
J/K
(d) N₂04(0) = 2 NO₂(9)
AS⁰ =
J/K
Chapter 31 Solutions
Principles of Instrumental Analysis
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Similar questions
- how to sketch the thermogravimetric curve anticipated when a 25 mg sample of FeCl3.6H2O is heated from 0 deg C to 400 deg C. The following table summarizes some data about three iron (III) chlorides Compound Molecular mass Melting point, deg C FeCl3.6H2O 270 37 FeCl3.5/2H2O 207 56 FeCl3 162 306arrow_forwardch.6.7.arrow_forwardCalculate the change in internal energy, AU (in kcal), for the reaction H2(g) + 1/2O2(g) = H₂O(1). Given that the heat of combustion of H2(g) at 1 atm and 25 °C is -68.32 kcal mol-¹. Pressure is constant and water has a density of 1.00 x 10³ kg m-³. Do not neglect the volume of H₂O (1).arrow_forward
- For the following chemical reaction, CO (g) + H2O (g) CO2 (g) + H2 (g) Kc = 0.0257 What is the Kc expression for this reaction?arrow_forwardPlease help, I can't figure thus out. Please show work so that I can understand.arrow_forwardWhy do we heat the prepared solution KMnO4 to a boiling boil for 1hrarrow_forward
- 7- Given the following data: AG --51 kJ 2H: (g) + C (s) → CHa (g) 2H2 (g) + O: (g) - 2H:0 (1) C (s) + 02 (g) → CO: (g) Calculate AG° for CH4 (g) + 202 (g)CO2 (g) + 2H;0 (). AG-474 kJ AG°--394 kJarrow_forward4arrow_forwardCalculate the standard enthalpies of formation of (a) KCIO3(s) with the following information: K(s) + 1/2 Cl₂(g) KCI(s) 2 KCIO3(s)→2 KCl(s) + 3 O₂(g) ArH=-436.75 kJ mol-¹ A,H-89.4 kJ mol-¹ (b) NaHCO3(s) with the following information: Na(s) + 1/2 O₂(g) + 1/2 H₂(g) → NaOH(s) C(s) + O₂(g) → CO₂(g) NaOH(s) + CO₂(g)→→NaHCO3(s) A,H-425.61 kJ mol-¹ ArH=-393.51 kJ mol-¹ A,H= -127.5 kJ mol-¹arrow_forward
- How would you answer this question?arrow_forwardG.231.arrow_forwardWhich of the following processes have a AS > 0? O CH3OH(1) – CH30H(s) O N2(g) + 3 H2(g) – 2 NH3(g) O CH4(8) + H2O(g) - CO(g) + 3 H2(g) O Na2CO3(s) + H20(g) + CO2(g) – 2 NaHCO3(s) O All of the above processes have a DS > 0.arrow_forward
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