Explanation Calculation: The given inequality is, 3 x − 2 y > − 13 Consider the above inequality in equation form, 3 x − 2 y = − 13 …… (1) Substitute 0 for x in equation (1). 3 ( 0 ) − 2 y = − 13 2 y = 13 y = 6.5 For x = 0 , y is 6.5 , therefore first point is ( 0 , 6.5 ) . Let y = 0 Substitute 0 for y in equation (1). 3 x − 2 ( 0 ) = − 13 3 x = − 13 x = − 4.3 For y = 0 , x is − 4.3 , therefore second point is ( − 4.3 , 0 ) . Plot the obtained points in the graph and join them. The given inequality is, − x + 2 y > 5 Consider the above inequality in equation form, − x + 2 y = 5 …… (2) Substitute 0 for x in equation (1)

Finite Mathematics for the Managerial, Life, and Social Sciences

12th Edition

ISBN: 9781337405782

Author: Soo T. Tan

Publisher: Cengage Learning

See similar textbooks

Videos

Question

Chapter 3.1, Problem 24E

To determine

The graphical solution of inequalities, 3x−2y>−13 and −x+2y>5, and to indicate whether the solution set is bounded or unbounded.

Expert Solution & Answer

Want to see the full answer?

Check out a sample textbook solution

See solution

Chapter 3.1, Problem 23E

Chapter 3.1, Problem 25E

Students have asked these similar questions

For the Big-M tableau (of a maximization LP and row0 at bottom and M=1000), Z Ꮖ 1 x2 x3 81 82 83 e4 a4 RHS 0 7 0 0 1 0 4 3 -3 20 0 -4.5 0 0 0 1 -8 -2.5 2.5 6 0 7 0 1 0 0 8 3 -3 4 0 -1 50 1 0 0 0-2 -1 1 4 0000 0 30 970 200 If the original value of c₁ is increased by 60, what is the updated value of c₁ (meaning keeping the same set for BV. -10? Having made that change, what is the new optimal value for ž?

Here is the optimal tableau for a standard Max problem. zx1 x2 x3 24 81 82 83 rhs 1 0 5 3 0 6 0 1 .3 7.5 0 - .1 .2 0 0 28 360 0 -8 522 0 2700 0 6 12 1 60 0 0 -1/15-3 1 1/15 -1/10 0 2 Using that the dual solution y = CBy B-1 and finding B = (B-¹)-¹ we find the original CBV and rhs b. The allowable increase for b₂ is If b₂ is increased by 3 then, using Dual Theorem, the new value for * is If c₂ is increased by 10, then the new value for optimal > is i.e. if no change to BV, then just a change to profit on selling product 2. The original coefficients c₁ = =☐ a and c4 = 5 If c4 is changed to 512, then (first adjusting other columns of row0 by adding Delta times row belonging to x4 or using B-matrix method to update row0) the new optimal value, after doing more simplex algorithm, for > is

Please show in mathematical form.

Chapter 3 Solutions

Finite Mathematics for the Managerial, Life, and Social Sciences

Ch. 3.1 - a. What is the difference between the graph of the...Ch. 3.1 - Prob. 2CQ Ch. 3.1 - In Exercises 110, find the graphical solution to...Ch. 3.1 - Prob. 2E Ch. 3.1 - Prob. 3E Ch. 3.1 - In Exercises 110, find the graphical solution to...Ch. 3.1 - In Exercises 110, find the graphical solution to...Ch. 3.1 - In Exercises 110, find the graphical solution to...Ch. 3.1 - In Exercises 110, find the graphical solution to...Ch. 3.1 - In Exercises 110, find the graphical solution to...

Knowledge Booster

Learn more about

Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, subject and related others by exploring similar questions and additional content below.

The graphical solution of inequalities, 3 x − 2 y > − 13 and − x + 2 y > 5 , and to indicate whether the solution set is bounded or unbounded.

Solution Summary: The author calculates the graphical solution of inequalities 3x-2y>-13 and -x+2y >5, and indicates whether the solution set is bounded or unbound.

Videos

The graphical solution of inequalities, 3x−2y>−13 and −x+2y>5, and to indicate whether the solution set is bounded or unbounded.

Want to see the full answer?

Chapter 3 Solutions

The graphical solution of inequalities, 3 x − 2 y &gt; − 13 and − x + 2 y &gt; 5 , and to indicate whether the solution set is bounded or unbounded.

Solution Summary: The author calculates the graphical solution of inequalities 3x-2y>-13 and -x+2y >5, and indicates whether the solution set is bounded or unbound.

Videos

The graphical solution of inequalities, 3x−2y>−13 and −x+2y>5, and to indicate whether the solution set is bounded or unbounded.

Want to see the full answer?

Chapter 3 Solutions

The graphical solution of inequalities, 3 x − 2 y > − 13 and − x + 2 y > 5 , and to indicate whether the solution set is bounded or unbounded.