Explanation Given: Length of fishing rod is 6 ft . Magnitude of force in line is 6 lb . Concept used: Write the expression to represent the force in line in vector form. F → = | F | ( cos 8 ° sin 30 ° i ^ − sin 8 ° j ^ − cos 8 ° cos 30 ° k ^ ) Simplify the above expression. F → = | F | ( 0.495 i ^ − 0.139 j ^ − 0.8576 k ^ ) …… (1) Here, F → is the force in line in vector form and | F | is the magnitude of force in line. Write the expression for the position vector for point B with respect to A. d → A B = l ( sin 45 ° j ^ − cos 45 ° k ^ ) ……. (2) Here, d → A B is the position vector for point B with respect to A and l is the length of fishing rod. Write the expression for moment about point A. M A = d → A B × F → …… (3) Here, M A is the moment about point A. Write the expression for magnitude of moment about point A. | M A | = M A x 2 + M A y 2 + M A z 2 …… (4) Here, | M A | is the magnitude of moment about point A, M A x is the x component of moment, M A y is the y component of moment and M A z is the z component of moment. Write the expression for perpendicular distance from point A to line pass through B and C. | M A | = | F | ⋅ d …… (5) Here, d is the perpendicular distance from point A to line pass through B and C. Calculation: Substitute 6 lb for | F | in equation (1) F → = ( 6 ) ( 0.495 i ^ − 0.139 j ^ − 0.8576 k ^ ) = ( 2.97 i ^ − 0.834 j ^ − 5.146 k ^ ) lb Substitute 6 ft for l in equation (2) d → A B = 6 ( sin 45 ° j ^ − cos 45 ° k ^ ) = ( 4.243 j ^ − 4.243 k ^ ) ft Substitute ( 2

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ISBN: 9780073398167

Author: Ferdinand P. Beer, E. Russell Johnston Jr., John T. DeWolf, David Mazurek

Publisher: McGraw-Hill Education

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Chapter 3.1, Problem 21P

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Perpendicular distance from point A to line drawn through BC.

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Chapter 3 Solutions

Statics and Mechanics of Materials

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Perpendicular distance from point A to line drawn through BC.

Solution Summary: The author explains the perpendicular distance from point A to line drawn through BC and the magnitude of force in line.

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Chapter 3 Solutions