Explanation 1) Concept: By using the concept of the solenoid and Faraday’s law, we can find the amplitude of the induced emf in the loop. 2) Formula: i) Magnetic field inside the solenoid B = μ 0 n I ii) Faraday's law ε = d φ d t iii) Magnetic flux φ = ∮ B d A iv) Time t = 1 f 3) Given: i) Area of the loop A = 6.8 m m 2 = 6.8 × 10 - 6 m 2 ii) Turns/cm in solenoid n = 854 t u r n s c m = 85400 t u r n s m iii) Current through solenoid I = 1.28 A iv) Angular frequency of current f = 212 r a d / s 4) Calculations: A long, tightly wound helical coil of wire is called a solenoid. When the current flows though the wire, the magnetic field induced inside the solenoid is given by B = μ 0 n I B = 4 × π × 10 - 7 × 85400 × 1.28 B = 0.1372 T … … … … … … … … … … … … … … … … … … … … … … … … … … … … … … …

11th Edition

ISBN: 9781119455608

Author: Halliday

Publisher: WILEY

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Chapter 30, Problem 9P

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The amplitude of the emf induced in the loop.

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Ch. 30 - If the circular conductor in Fig. 30-21 undergoes...Ch. 30 - Prob. 2Q Ch. 30 - Prob. 3Q Ch. 30 - Prob. 4Q Ch. 30 - Prob. 5Q Ch. 30 - Prob. 6Q Ch. 30 - Prob. 7Q Ch. 30 - Prob. 8Q Ch. 30 - Prob. 9Q Ch. 30 - Prob. 10Q

Ch. 30 - Figure 30-31 shows three situations in which a...Ch. 30 - Figure 30-32 gives four situations in which we...Ch. 30 - Prob. 1P Ch. 30 - A certain elastic conducting material is stretched...Ch. 30 - Prob. 3P Ch. 30 - A wire loop of radius 12 cm and resistance 8.5 is...Ch. 30 - Prob. 5P Ch. 30 - Figure 30-37a shows a circuit consisting of an...Ch. 30 - In Fig. 30-38, the magnetic flux through the loop...Ch. 30 - Prob. 8P Ch. 30 - Prob. 9P Ch. 30 - Prob. 10P Ch. 30 - A rectangular coil of N turns and of length a and...Ch. 30 - Prob. 12P Ch. 30 - Prob. 13P Ch. 30 - GO In Fig. 30-42a, a uniform magnetic field B...Ch. 30 - GO A square wire loop with 2.00 m sides is...Ch. 30 - GO Figure 30-44a shows a wire that forms a...Ch. 30 - A small circular loop of area 2.00 cm2 is placed...Ch. 30 - Prob. 18P Ch. 30 - ILW An electric generator contains a coil of 100...Ch. 30 - At a certain place, Earths magnetic field has...Ch. 30 - Prob. 21P Ch. 30 - A rectangular loop area = 0.15 m2 turns in a...Ch. 30 - SSM Figure 30-47 shows two parallel loops of wire...Ch. 30 - Prob. 24P Ch. 30 - GO Two long, parallel copper wires of diameter 2.5...Ch. 30 - GO For the wire arrangement in Fig. 30-49, a =...Ch. 30 - ILW As seen in Fig. 30-50, a square loop of wire...Ch. 30 - Prob. 28P Ch. 30 - Prob. 29P Ch. 30 - Prob. 30P Ch. 30 - Prob. 31P Ch. 30 - A loop antenna of area 2.00 cm2 and resistance...Ch. 30 - GO Figure 30-54 shows a rod of length L = 10.0 cm...Ch. 30 - Prob. 34P Ch. 30 - Prob. 35P Ch. 30 - Prob. 36P Ch. 30 - Prob. 37P Ch. 30 - Prob. 38P Ch. 30 - Prob. 39P Ch. 30 - Prob. 40P Ch. 30 - A circular coil has a 10.0 cm radius and consists...Ch. 30 - Prob. 42P Ch. 30 - Prob. 43P Ch. 30 - Prob. 44P Ch. 30 - Prob. 45P Ch. 30 - Prob. 46P Ch. 30 - Inductors in series. Two inductors L1 and L2 are...Ch. 30 - Prob. 48P Ch. 30 - Prob. 49P Ch. 30 - Prob. 50P Ch. 30 - ILW The current in an RL circuit drops from 1.0 A...Ch. 30 - Prob. 52P Ch. 30 - Prob. 53P Ch. 30 - Prob. 54P Ch. 30 - Prob. 55P Ch. 30 - Prob. 56P Ch. 30 - In Fig. 30-65, R = 15 , L = 5.0 H, the ideal...Ch. 30 - Prob. 58P Ch. 30 - Prob. 59P Ch. 30 - Prob. 60P Ch. 30 - Prob. 61P Ch. 30 - A coil with an inductance of 2.0 H and a...Ch. 30 - Prob. 63P Ch. 30 - Prob. 64P Ch. 30 - Prob. 65P Ch. 30 - A circular loop of wire 50 mm in radius carries a...Ch. 30 - Prob. 67P Ch. 30 - Prob. 68P Ch. 30 - ILW What must be the magnitude of a uniform...Ch. 30 - Prob. 70P Ch. 30 - Prob. 71P Ch. 30 - Prob. 72P Ch. 30 - Prob. 73P Ch. 30 - Prob. 74P Ch. 30 - Prob. 75P Ch. 30 - Prob. 76P Ch. 30 - Prob. 77P Ch. 30 - Prob. 78P Ch. 30 - SSM In Fig. 30-71, the battery is ideal and = 10...Ch. 30 - Prob. 80P Ch. 30 - Prob. 81P Ch. 30 - A uniform magnetic field B is perpendicular to the...Ch. 30 - Prob. 83P Ch. 30 - Prob. 84P Ch. 30 - Prob. 85P Ch. 30 - Prob. 86P Ch. 30 - Prob. 87P Ch. 30 - Prob. 88P Ch. 30 - A coil with an inductance of 2.0 H and a...Ch. 30 - Prob. 90P Ch. 30 - Prob. 91P Ch. 30 - Prob. 92P Ch. 30 - Prob. 93P Ch. 30 - A long cylindrical solenoid with 100 turns/cm has...Ch. 30 - Prob. 95P Ch. 30 - A square loop of wire is held in a uniform 0.24 T...Ch. 30 - Prob. 97P Ch. 30 - The inductance of a closely wound coil is such...Ch. 30 - The magnetic field in the interstellar space of...Ch. 30 - Prob. 100P Ch. 30 - A toroid has a 5.00 cm square cross section, an...

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The amplitude of the emf induced in the loop.

Solution Summary: The author explains the concept of the solenoid and Faraday's law to find the amplitude of emf induced in the loop.

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To find: The amplitude of the emf induced in the loop.

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Chapter 30 Solutions

To find:

The amplitude of the emf induced in the loop.