Explanation 1) Concept: The rate of change of magnetic flux is related to line integral of electric field by Faraday’s law, so we can use Faraday’s law to evaluate line integral, ∮ E → · d s → . Using this, we can find magnitude of electric field inside the solenoid at distance r from the axis of solenoid. 2) Formula: i) ϵ i n d = - d ϕ B d t = ∮ E → · d s → ii) d ϕ B = B → · d A → iii) Magnitude electric field inside solenoid at distance r from the axis of solenoid, E = r 2 d B d t iv) Angular frequency of oscillation of field, ω = 2 π f 3) Given: i) r = 1.6 × 10 - 2 m ii) Diameter of cylindrical magnet D = 3.3 c m = 3.3 × 10 - 2 m iii) Frequency of sinusoidally varying magnetic field f = 15.0 H z 4) Calculations: As mentioned in the problem the magnetic field is varying sinusoidally, let’s assume that the following form of time is dependent on magnetic field B = B 0 sin ⁡ ω t = B 0 sin ⁡ ( 2 π f t ) As the field is varying in between two values 30.0 T and 29.6 T Taking difference and dividing it by 2, we get the amplitude of field B 0 = 30.0 - 29.6 2 = 0

11th Edition

ISBN: 9781119455608

Author: Halliday

Publisher: WILEY

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Question

Chapter 30, Problem 39P

To determine

To find:

Amplitude of electric field induced, Em

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Chapter 30, Problem 38P

Chapter 30, Problem 40P

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