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A proton enters a region with a uniform electric field
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Chapter 30 Solutions
Physics for Scientists and Engineers: Foundations and Connections
- A particle moving downward at a speed of 6.0106 m/s enters a uniform magnetic field that is horizontal and directed from east to west. (a) If the particle is deflected initially to the north in a circular arc, is its charge positive or negative? (b) If B = 0.25 T and the charge-to-mass ratio (q/m) of the particle is 40107 C/kg. what is ±e radius at the path? (c) What is the speed of the particle after c has moved in the field for 1.0105s ? for 2.0s?arrow_forwardAlong, straight wire lies along the z-axis and carries current I=60.0 A in the+z-direction. A small particle with mass 3.50 x 10 kg and charge 8.00 x 10 c is traveling in the vicinity of the wire. At an instant when the particle is on the y-axis at y 9.00 cm, its acceleration has components a-5.00 x 10³ m/s² and a 49.00 x 10³ m/s² Part A At that instant what are the 2- and y-components of the velocity of the particle? Express your answer in kilometers per second. Enter your answers numerically separated by a comma 19Η ΑΣΦ OPO Submit Previous Answers Request Answer X Incorrect; Try Again; 3 attempts remaining Provide Feedback ? km/sarrow_forwardA proton moves through a uniform electric field given by vector E = 50.0 j hat V/m and a uniform magnetic field vector B = (0.200 i hat+ 0.300 j hat+ 0.400 k hat) T. Determine the acceleration of the proton when it has a velocity vector v = 200 i m/sarrow_forward
- A particle of mass m and charge q is accelerated along the +x axis (in the plane of the page) from rest through an electric potential difference V. The particle then enters a region, defined by x> 0, containing a uniform magnetic field. V = 400.0 V B = 0.850 T q = -1.602 × 10-19 m = 6.68 × 10-27 kg B = 0 9. What is the radius of the particle's path, and how long does it take the particle to exit the magnetic field region?arrow_forwardA long, straight wire lies along the r-axis and carries current I = 60.0 A in the +x-direction. A small particle with mass 3.00 x 10-6 kg and charge 8.00 × 10-3 C is traveling in the vicinity of the wire. At an instant when the particle is on the y-axis at y = 7.00 cm, its acceleration has components a, = -5.00 x 10³ m/s? and a, = 19.00 x 103 m/s². Part A At that instant what are the - and y-components of the velocity of the particle? Express your answer in kilometers per second. Enter your answers numerically separated by a comma. Vz, Vy = km/s Submit Request Answerarrow_forwardA particle with mass 0.8 gram and charge .02 μC is moving in the x-y plane with a velocity v(t) given by the formula v(t) = (15000 i + 30000 j )m/s. It enters a region of space where a magnetic field B exists, given by B = (1.5 i + 2j) T. What is the force on the charge? (Hint: i, j and k are the unit vectors along x, y and z-axis respectively. Use the relationships i x i = j x j = k x k = 0, and i x j = k, etc.) a) .0003 N along positive z b) .0003 N along positive x c) .0003 N along negative z. What is its acceleration? 0.375 m/s2 along negative z b) 0.375 m/s2 along positive x c) 0.375 m/s2 along positive zarrow_forward
- A particle with charge 4.16 x 10^-6 C moves at 5.78 x 10^6 m/s through a magnetic field of strength 2.58 T. The angle between the particle s velocity and the magnetic field direction is 35.1 degrees and the particle undergoes an acceleration of 11.9 m/s^2. What is the particle s mass? 17.9 kg 3.00 kg 6.0 kg 7.1 kgarrow_forwardA particle with charge q = 1.2 C and a long wire carrying current I = 6 A is on the xy-plane at the moment the charge is at point P at distance d = 0.4 cm from the wire and has velocity v = 1.8 m/s in the I d x-direction. What is the magnitude of the magnetic force acting on the charge in units of nanonewtons? (u = 47 x 10-7T · m/A) Answer:arrow_forwardA long, straight wire lies along the x-axis and carries current I = 60.0 A in the +x-direction. A small particle with mass 3.50 x 100 kg and charge 8.00 x 10-3 C is traveling in the vicinity of -6 the wire. At an instant when the particle is on the y-axis at y=7.00 cm, its acceleration has components a = -5.00 x 103 m/s² and ay=+9.00 x 103 m/s².arrow_forward
- A particle with mass 3×10−2 kgkg and charge +7 μCμC enters a region of space where there is a magnetic field of 1 TT that is perpendicular to the velocity of the particle. When the particle encounters the magnetic field, it experiences an acceleration of 17 m/s2m/s2 . What is the speed of the particle when it enters the magnetic-field region? Express your answer in meters per second.arrow_forwardA particle with positive charge q = 3.52 x 1018 C moves with a velocity v = (5î + 4ĵ – k) m/s through a region where both a uniform magnetic field and a uniform electric field exist. (a) Calculate the total force on the moving particle, taking B = (3î + 2ĵ + k) T and E = (3î - j - 2k) V/m. (Give your answers in N for each component.) Ey = Ey = F, = (b) What angle does the force vector make with the positive x-axis? (Give your answer in degrees counterclockwise from the +x-axis.) ° counterclockwise from the +x-axis (c) What If? For what vector electric field would the total force on the particle be zero? (Give your answers in V/m for each component.) E, = V/m E, = V/m E, = V/marrow_forwardA positively charged particle slides off a frictionless and smooth surface with initial X X X X X X X X speed v, =v, . It then enters into a region with X X X X X x x x X uniform magnetic field pointing into the page. X X X X x x x x X x x x x x X x x x The particle eventually hits the ground with final speed v, air time and range S · The particle slides off the edge again with identical initial speed, but this time without the magnetic field. The particle then hits the ground with final speed v,, air time t, , and range s,. Determine the relationships between v, and v,, t, and t, , as well as s, and s, (3 marks). Please note that no calculation is needed. You were to provide the relationship in the sense that whether one variable is greater than, smaller than, or equals to the other one (>, <, or =). Provide a rough explanation (3 marks).arrow_forward
- Principles of Physics: A Calculus-Based TextPhysicsISBN:9781133104261Author:Raymond A. Serway, John W. JewettPublisher:Cengage LearningPhysics for Scientists and Engineers: Foundations...PhysicsISBN:9781133939146Author:Katz, Debora M.Publisher:Cengage Learning