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Principles of Physics: A Calculus-Based Text
5th Edition
ISBN: 9781133104261
Author: Raymond A. Serway, John W. Jewett
Publisher: Cengage Learning
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Chapter 30, Problem 42P
To determine
Derive an equation for neutron mass by considering head on collisions of neutrons with two stationary target nucleus.
To determine
The mass of the neutron found using the above expression.
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Chapter 30 Solutions
Principles of Physics: A Calculus-Based Text
Ch. 30.1 - Prob. 30.1QQCh. 30.1 - Prob. 30.2QQCh. 30.3 - Prob. 30.3QQCh. 30.3 - Suppose you have a pure radioactive material with...Ch. 30.4 - Which of the following is the correct daughter...Ch. 30.4 - Which of the following is the correct daughter...Ch. 30 - Prob. 1OQCh. 30 - Prob. 2OQCh. 30 - Prob. 3OQCh. 30 - Prob. 4OQ
Ch. 30 - Prob. 5OQCh. 30 - Prob. 6OQCh. 30 - Prob. 7OQCh. 30 - Prob. 8OQCh. 30 - Prob. 9OQCh. 30 - Prob. 10OQCh. 30 - Which of the following quantities represents the...Ch. 30 - Prob. 12OQCh. 30 - Prob. 1CQCh. 30 - Prob. 2CQCh. 30 - Prob. 3CQCh. 30 - Prob. 4CQCh. 30 - Prob. 5CQCh. 30 - Prob. 6CQCh. 30 - Prob. 7CQCh. 30 - If no more people were to be born, the law of...Ch. 30 - Prob. 9CQCh. 30 - Prob. 10CQCh. 30 - Prob. 11CQCh. 30 - What fraction of a radioactive sample has decayed...Ch. 30 - Prob. 13CQCh. 30 - Prob. 14CQCh. 30 - Prob. 15CQCh. 30 - Prob. 16CQCh. 30 - Prob. 17CQCh. 30 - Prob. 1PCh. 30 - Prob. 2PCh. 30 - Prob. 3PCh. 30 - Prob. 4PCh. 30 - Prob. 5PCh. 30 - Prob. 6PCh. 30 - Prob. 7PCh. 30 - Prob. 8PCh. 30 - Prob. 9PCh. 30 - Prob. 10PCh. 30 - Prob. 11PCh. 30 - Prob. 12PCh. 30 - Prob. 13PCh. 30 - Prob. 14PCh. 30 - Prob. 16PCh. 30 - Prob. 17PCh. 30 - Prob. 18PCh. 30 - What time interval elapses while 90.0% of the...Ch. 30 - Prob. 20PCh. 30 - Prob. 21PCh. 30 - Prob. 22PCh. 30 - Prob. 23PCh. 30 - Prob. 24PCh. 30 - Prob. 25PCh. 30 - Prob. 26PCh. 30 - Prob. 27PCh. 30 - Prob. 28PCh. 30 - Prob. 29PCh. 30 - Prob. 30PCh. 30 - Prob. 31PCh. 30 - Prob. 32PCh. 30 - Prob. 33PCh. 30 - Prob. 34PCh. 30 - Prob. 35PCh. 30 - Prob. 36PCh. 30 - Prob. 37PCh. 30 - Prob. 38PCh. 30 - Prob. 39PCh. 30 - Prob. 41PCh. 30 - Prob. 42PCh. 30 - Prob. 43PCh. 30 - Prob. 45PCh. 30 - Prob. 46PCh. 30 - Prob. 47PCh. 30 - Prob. 48PCh. 30 - Prob. 49PCh. 30 - Prob. 50PCh. 30 - Prob. 51PCh. 30 - Prob. 52PCh. 30 - Prob. 53PCh. 30 - Prob. 54PCh. 30 - Prob. 55PCh. 30 - Prob. 56PCh. 30 - Prob. 57PCh. 30 - Prob. 58PCh. 30 - Prob. 59PCh. 30 - Prob. 60PCh. 30 - Prob. 61PCh. 30 - Prob. 62PCh. 30 - Prob. 63PCh. 30 - Prob. 64PCh. 30 - Prob. 65PCh. 30 - Prob. 66PCh. 30 - Prob. 67PCh. 30 - Prob. 68PCh. 30 - Prob. 69PCh. 30 - Prob. 70P
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- Rutherford fired a beam of alpha particles (helium nuclei) at a thin sheet of gold. An alpha particle was observed to be deflected by 90.0°; its speed was unchanged. The alpha particles used in the experiment had an initial speed of 2.4 ✕ 107 m/s and a mass of 6.7 ✕ 10−27 kg.Assume the alpha particle collided with a gold nucleus that was initially at rest. Find the speed of the nucleus after the collision. ?m/sarrow_forwardFirst part is already answered but the process would still be appreciated.arrow_forwardRutherford fired a beam of alpha particles (helium nuclei) at a thin sheet of gold. An alpha particle was observed to be deflected by 90.0°; its speed was unchanged. The alpha particles used in the experiment had an initial speed of 2.4 ✕ 107 m/s and a mass of 6.7 ✕ 10−27 kg. Assume the alpha particle collided with a gold nucleus that was initially at rest. Find the speed of the nucleus after the collision. m/sarrow_forward
- Ernest Rutherford (the first New Zealander to be awarded the Nobel Prize in Chemistry) demonstrated that nuclei were very small and dense by scattering helium-4 nuclei (4He) from gold-197 nuclei (197Au ). The energy of the incoming helium nucleus was 8.00×10−13J, and the masses of the helium and gold nuclei were 6.68×10−27kg and 3.29×10−25kg, respectively (note that their mass ratio is 4 to 197). (a) If a helium nucleus scatters to an angle of 120º during an elastic collision with a gold nucleus, calculate the helium nucleus’s final speed and the final velocity (magnitude and direction) of the gold nucleus. (b) What is the final kinetic energy of the helium nucleus?arrow_forwardThe nucleus of an atom consists of protons and neutrons (no electrons). A nucleus of a carbon-12 isotope contains six protons and six neutrons, while a nitrogen-14 nucleus comprises seven protons and seven neutrons. A graduate student performs a nuclear physics experiment in which she bombards nitrogen-14 nuclei with very high speed carbon-12 nuclei emerging from a particle accelerator. As a result of each such collision, the two nuclei disintegrate completely, and a mix of different particles are emitted, including electrons, protons, antiprotons (with electric charge -e each), positrons (with charge +e each), and various neutral particles (including neutrons and neutrinos). For a particular collision, she detects the emitted products and find 17 protons, 4 antiprotons, 7 positrons, and 21 neutral particles. How many electrons are also emitted?arrow_forwardDuring fission in nuclear power plants, uranium-235 can be used as radioactive material to produce energy. One shoots a neutron at the uranium nucleus, which then splits into two daughter nuclei plus three neutrons according to the reaction Suppose that a certain nuclear power plant splits 4.3% of all uranium nuclei in its reactors according to the formula and that it emits a total output of 3.8 GW. How long does it take for the nuclear power plant to consume 1 kg of uranium?arrow_forward
- A proton with mass m1 and initial velocity v1 makes an atomic collision with another atom with mass 3m1 and initial velocity zero. If we have: Q= 1/3 k1And the proton leaves the initial path at an angle of 45 degrees, find the final velocity of the second mass.arrow_forwardA particle of mass m, is fired at a stationary particle of mass mg, and a reaction takes place in which new particles are created out of the incident kinetic energy. Taken together, the product particles have total mass mg. The minimum kinetic energy the bombarding particle must have so as to induce the reaction is called the threshold energy. At this energy, the kinetic energy of the products is a minimum, so the fraction of the incident kinetic energy that is available to create new particles is a maximum. This condition is met when all the product particles have the same velocity and the particles have no kinetic energy of motion relative to one another. (a) By using conservation of relativistic energy and momentum and the relativistic energy-momentum relation, show that the threshold kinetic energy is [m- (m, + m,)*]c² K. min 2m, Calculate the threshold kinetic energy for each of the following reactions: (b) p + p → p + p + p + p (one of the initial protons is at rest, and…arrow_forwardElectron capture is a variant on beta-radiation. The lightest nucleus to decay by electron capture is 7Be -- beryllium-7. The daughter nucleus is 7Li -- lithium-7. The electron is transformed into a massless particle (a neutrino): e − + 7 B e + ⟶ 7 L i + ν The initial electron is bound in the atom, so the beryllium mass includes the electron. In fact, since the electron starts bound in the atom, a more-accurate statement of the nuclear reaction is probably: 7 B e ⟶ 7 L i + ν The masses are beryllium: 7.016929 u, and lithium: 7.016003 u, and refer to the neutral atom as a whole. (Use uc and uc2 as your momentum and energy units -- but carry them along in your calculation.) The initial beryllium atom is stationary. Calculate the speed of the final lithium nucleus in km/s. (all the energy released goes into the lighter particle. c = 300,000 km/s)arrow_forward
- Electron capture is a variant on beta-radiation. The lightest nucleus to decay by electron capture is 7Be -- beryllium-7. The daughter nucleus is 7Li -- lithium-7. The electron is transformed into a massless particle (a neutrino): e − + 7 B e + ⟶ 7 L i + ν The initial electron is bound in the atom, so the beryllium mass includes the electron. In fact, since the electron starts bound in the atom, a more-accurate statement of the nuclear reaction is probably: 7 B e ⟶ 7 L i + ν The masses are beryllium: 7.016929 u, and lithium: 7.016003 u, and refer to the neutral atom as a whole. (Use uc and uc2 as your momentum and energy units -- but carry them along in your calculation.) The initial beryllium atom is stationary. Calculate the speed of the final lithium nucleus in km/s. (You will make life much easier for yourself if you recognize that practically all the energy released goes into the lighter particle. c = 300,000 km/s)arrow_forwardIn a dark matter direct detection experiment, a dark matter particle is supposed to directly interact with the atoms in the detector, causing either a nucleus or an electron to recoil after the collision has occurred. The dark matter particles in our galaxy should be moving at non-relativistic speeds, so this scattering process can be described using the conservation of momentum governed by Newton's laws without the need for quantum mechanics. One of the most common target materials for these experiments is xenon. Your goal is to answer the following question. Assuming there is a dark matter particle with incident velocity v1 that will scatter from a Xe-136 nucleus (with a mass of 136 amu) that was initially at rest as shown below. What is the dark matter mass? You should solve for the answer symbolically first. Then you will substitute in the values shown below to get out an actual numerical value for the mass, in amu. Dark Matter Particle 02 01 Өз Xe nucleusarrow_forwardErnest Rutherford (the first New Zealander to be awarded the Nobel Prize in Chemistry) demonstrated that nuclei were very small and dense by scattering helium-4 nuclei from gold-197 nuclei. The energy of the incoming helium nucleus was 8.00 × 10−13 J , and the masses of the helium and gold nuclei were 6.68 × 10−27 kg and 3.29 × 10−25 kg , respectively (note that their mass ratio is 4 to 197).a. If a helium nucleus scatters to an angle of 120° during an elastic collision with a gold nucleus, calculate the helium nucleus’s final speed and the final velocity (magnitude and direction) of the gold nucleus. b. What is the final kinetic energy of the helium nucleus?arrow_forward
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