Physics for Scientists and Engineers with Modern Physics
10th Edition
ISBN: 9781337553292
Author: Raymond A. Serway, John W. Jewett
Publisher: Cengage Learning
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Chapter 30, Problem 21P
Within the green dashed circle show in Figure P30.21, the magnetic field changes with time according to the expression B = 2.00t3 − 4.00t2 + 0.800, where B is in teslas, t is in seconds, and R = 2.50 cm. When t = 2.00 s, calculate (a) the magnitude and (b) the direction of the force exerted on an electron located at point P, which is at a distance r = 5.00 cm from the center of the circular field region. (c) At what instant is this force equal to zero?
Figure P30.21
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Chapter 30 Solutions
Physics for Scientists and Engineers with Modern Physics
Ch. 30.1 - A circular loop of wire is held in a uniform...Ch. 30.2 - QUICK QUIZ 30.2 In Figure 30.8a, a given applied...Ch. 30.3 - Figure 30.12 (Quick Quiz 30.3) QUICK QUIZ 30.3...Ch. 30.5 - Prob. 30.4QQCh. 30 - A circular loop of wire of radius 12.0 cm is...Ch. 30 - An instrument based on induced emf has been used...Ch. 30 - Scientific work is currently under way to...Ch. 30 - A long solenoid has n = 400 turns per meter and...Ch. 30 - An aluminum ring of radius r1 = 5.00 cm and...Ch. 30 - Prob. 6P
Ch. 30 - A coil formed by wrapping 50 turns of wire in the...Ch. 30 - Prob. 8PCh. 30 - A toroid having a rectangular cross section (a =...Ch. 30 - A small airplane with a wingspan of 14.0 m is...Ch. 30 - A helicopter (Fig. P30.11) has blades of length...Ch. 30 - A 2.00-m length of wire is held in an eastwest...Ch. 30 - A metal rod of mass m slides without friction...Ch. 30 - Prob. 14PCh. 30 - Prob. 15PCh. 30 - Prob. 16PCh. 30 - You are working for a company that manufactures...Ch. 30 - You are working in a laboratory that uses motional...Ch. 30 - You are working in a factory that produces long...Ch. 30 - Prob. 20PCh. 30 - Within the green dashed circle show in Figure...Ch. 30 - Prob. 22PCh. 30 - Prob. 23PCh. 30 - Figure P30.24 (page 820) is a graph of the induced...Ch. 30 - The rotating loop in an AC generator is a square...Ch. 30 - In Figure P30.26, a semicircular conductor of...Ch. 30 - Prob. 27PCh. 30 - Prob. 28APCh. 30 - Prob. 29APCh. 30 - Prob. 30APCh. 30 - A circular coil enclosing an area of 100 cm2 is...Ch. 30 - Prob. 32APCh. 30 - A guitars steel string vibrates (see Fig. 30.5)....Ch. 30 - Prob. 34APCh. 30 - A conducting rod of length = 35.0 cm is free to...Ch. 30 - Prob. 36APCh. 30 - Prob. 37APCh. 30 - In Figure P30.38, the rolling axle, 1.50 m long,...Ch. 30 - Figure P30.39 shows a stationary conductor whose...Ch. 30 - Prob. 40APCh. 30 - Figure P30.41 shows a compact, circular coil with...Ch. 30 - Review. In Figure P30.42, a uniform magnetic field...Ch. 30 - An N-turn square coil with side and resistance R...Ch. 30 - A conducting rod of length moves with velocity v...Ch. 30 - A long, straight wire carries a current given by I...Ch. 30 - A rectangular loop of dimensions and w moves with...Ch. 30 - A thin wire = 30.0 cm long is held parallel to...Ch. 30 - Prob. 48CPCh. 30 - Prob. 49CPCh. 30 - Prob. 50CPCh. 30 - Review. The bar of mass m in Figure P30.51 is...
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- A wire is bent in the form of a square loop with sides of length L (Fig. P30.24). If a steady current I flows in the loop, determine the magnitude of the magnetic field at point P in the center of the square. FIGURE P30.24arrow_forwardA circular coil 15.0 cm in radius and composed of 145 tightly wound turns carries a current of 2.50 A in the counterclockwise direction, where the plane of the coil makes an angle of 15.0 with the y axis (Fig. P30.73). The coil is free to rotate about the z axis and is placed in a region with a uniform magnetic field given by B=1.35jT. a. What is the magnitude of the magnetic torque on the coil? b. In what direction will the coil rotate? FIGURE P30.73arrow_forwardWhy is the following situation impossible? Figure P28.46 shows an experimental technique for altering the direction of travel for a charged particle. A particle of charge q = 1.00 C and mass m = 2.00 1015 kg enters the bottom of the region of uniform magnetic field at speed = 2.00 105 m/s, with a velocity vector perpendicular to the field lines. The magnetic force on the particle causes its direction of travel to change so that it leaves the region of the magnetic field at the top traveling at an angle from its original direction. The magnetic field has magnitude B = 0.400 T and is directed out of the page. The length h of the magnetic field region is 0.110 m. An experimenter performs the technique and measures the angle at which the particles exit the top of the field. She finds that the angles of deviation are exactly as predicted. Figure P28.46arrow_forward
- Two long coaxial copper tubes, each of length L, are connected to a battery of voltage V. The inner tube has inner radius o and outer radius b, and the outer tube has inner radius c and outer radius d. The tubes are then disconnected from the battery and rotated in the same direction at angular speed of radians per second about their common axis. Find the magnetic field (a) at a point inside the space enclosed by the inner tube r d. (Hint: Hunk of copper tubes as a capacitor and find the charge density based on the voltage applied, Q=VC, C=20LIn(c/b) .)arrow_forwardA toroid has a major radius R and a minor radius r and is tightly wound with N turns of wire on a hollow cardboard torus. Figure P31.6 shows half of this toroid, allowing us to see its cross section. If R r, the magnetic field in the region enclosed by the wire is essentially the same as the magnetic field of a solenoid that has been bent into a large circle of radius R. Modeling the field as the uniform field of a long solenoid, show that the inductance of such a toroid is approximately L=120N2r2R Figure P31.6arrow_forwardIn Figure P22.43, the current in the long, straight wire is I1 = 5.00 A and the wire lies in the plane of the rectangular loop, which carries a current I2 = 10.0 A. The dimensions in the figure are c = 0.100 m, a = 0.150 m, and = 0.450 m. Find the magnitude and direction of the net force exerted on the loop by the magnetic field created by the wire. Figure P22.43 Problems 43 and 44.arrow_forward
- A metal rod of mass m slides without friction along two parallel horizontal rails, separated by a distance and connected by a resistor R, as shown in Figure P30.13. A uniform vertical magnetic field of magnitude B is applied perpendicular to the plane of the paper. The applied force shown in the figure acts only for a moment, to give the rod a speed v. In terms of m, , R, B, and v, find the distance the rod will then slide as it coasts to a stop. Figure P30.13arrow_forwardOne long wire carries current 30.0 A to the left along the x axis. A second long wire carries current 50.0 A to the right along the line (y = 0.280 m, z = 0). (a) Where in the plane of the two wires is the total magnetic field equal to zero? (b) A particle with a charge of 2.00 C is moving with a velocity of 150iMm/s along the line (y = 0.100 m, z = 0). Calculate the vector magnetic force acting on the particle. (c) What If? A uniform electric field is applied to allow this particle to pass through this region undetected. Calculate the required vector electric field.arrow_forwardSketch a plot of the magnitude of the magnetic field as a function of position r for a coax (Fig. P31.27).arrow_forward
- Two frictionless conducting rails separated by l = 55.0 cm are connected through a 2.00- resistor, and the circuit is completed by a bar that is free to slide on the rails (Fig. P32.71). A uniform magnetic field of 5.00 T directed out of the page permeates the region, a. What is the magnitude of the force Fp that must be applied so that the bar moves with a constant speed of 1.25 m/s to the right? b. What is the rate at which energy is dissipated through the 2.00- resistor in the circuit?arrow_forwardFigure CQ19.7 shows a coaxial cable carrying current I in its inner conductor and a return current of the same magnitude in the opposite direction in the outer conductor. The magnetic field strength at r = r0 is Find the ratio B/B0, at (a) r = 2r0 and (b) r = 4r0. Figure CQ19.7arrow_forwardThe Hall effect finds important application in the electronics industry. It is used to find the sign and density of the carriers of electric current in semiconductor chips. The arrangement is shown in Figure P22.66. A semiconducting block of thickness t and width d carries a current I in the x direction. A uniform magnetic field B is applied in the y direction. If the charge carriers are positive, the magnetic force deflects them in the z direction. Positive charge accumulates on the top surface of the sample and negative charge on the bottom surface, creating a downward electric field. In equilibrium, the downward electric force on the charge carriers balances the upward magnetic force and the carriers move through the sample without deflection. The Hall voltage ΔVH = Vc − Va between the top and bottom surfaces is measured, and the density of the charge carriers can be calculated from it. (a) Demonstrate that if the charge carriers are negative the Hall voltage will be negative. Hence, the Hall effect reveals the sign of the charge carriers, so the sample can be classified as p-type (with positive majority charge carriers) or n-type (with negative). (b) Determine the number of charge carriers per unit volume n in terms of I, t, B, ΔVH, and the magnitude q of the carrier charge. Figure P22.66arrow_forward
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Magnets and Magnetic Fields; Author: Professor Dave explains;https://www.youtube.com/watch?v=IgtIdttfGVw;License: Standard YouTube License, CC-BY