FlipIt for College Physics (Algebra Version - Six Months Access)
17th Edition
ISBN: 9781319032432
Author: Todd Ruskell
Publisher: W.H. Freeman & Co
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Chapter 3, Problem 68QAP
To determine
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dry
5. (a) When rebuilding her car's engine, a physics major must exert 300 N of force to insert a c
piston into a steel cylinder. What is the normal force between the piston and cyli=030
What force would she have to exert if the steel parts were oiled? k
F = 306N
2
=0.03 (
Include free body diagram
Include free body diagram
Chapter 3 Solutions
FlipIt for College Physics (Algebra Version - Six Months Access)
Ch. 3 - Prob. 1QAPCh. 3 - Prob. 2QAPCh. 3 - Prob. 3QAPCh. 3 - Prob. 4QAPCh. 3 - Prob. 5QAPCh. 3 - Prob. 6QAPCh. 3 - Prob. 7QAPCh. 3 - Prob. 8QAPCh. 3 - Prob. 9QAPCh. 3 - Prob. 10QAP
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- Test 2 МК 02 5. (a) When rebuilding her car's engine, a physics major must exert 300 N of force to insert a dry = 0.03 (15 pts) piston into a steel cylinder. What is the normal force between the piston and cylinder? What force would she have to exert if the steel parts were oiled? Mk Giren F = 306N MK-0.3 UK = 0.03 NF = ?arrow_forward2. A powerful motorcycle can produce an acceleration of 3.50 m/s² while traveling at 90.0 km/h. At that speed the forces resisting motion, including friction and air resistance, total 400 N. (Air resistance is analogous to air friction. It always opposes the motion of an object.) What force does the motorcycle exert backward on the ground to produce its acceleration if the mass of the motorcycle with rider is 245 ke? a = 350 m/s 2arrow_forward2. A powerful motorcycle can produce an acceleration of 3.50 m/s² while traveling at 90.0 km/h. At that speed the forces resisting motion, including friction and air resistance, total 400 N. (Air resistance is analogous to air friction. It always opposes the motion of an object.) What force does the motorcycle exert backward on the ground to produce its acceleration if the mass of the motorcycle with rider is 245 kg? (10 pts) a = 3.50 m/s 2 distance 90 km/h = 3.50m/62 M = 245garrow_forward
- Using Table 17-4, determine the approximate temperature of metal that has formed a dark blue color.arrow_forwardA positively charged disk has a uniform charge per unit area σ. dq R P x The total electric field at P is given by the following. Ek [2 - x (R² + x2) 1/2 Sketch the electric field lines in a plane perpendicular to the plane of the disk passing through its center.arrow_forwardConsider a closed triangular box resting within a horizontal electric field of magnitude E = 8.02 104 N/C as shown in the figure below. A closed right triangular box with its vertical side on the left and downward slope on the right rests within a horizontal electric field vector E that points from left to right. The box has a height of 10.0 cm and a depth of 30.0 cm. The downward slope of the box makes an angle of 60 degrees with the vertical. (a) Calculate the electric flux through the vertical rectangular surface of the box. kN · m2/C(b) Calculate the electric flux through the slanted surface of the box. kN · m2/C(c) Calculate the electric flux through the entire surface of the box. kN · m2/Carrow_forward
- The figure below shows, at left, a solid disk of radius R = 0.600 m and mass 75.0 kg. Tu Mounted directly to it and coaxial with it is a pulley with a much smaller mass and a radius of r = 0.230 m. The disk and pulley assembly are on a frictionless axle. A belt is wrapped around the pulley and connected to an electric motor as shown on the right. The turning motor gives the disk and pulley a clockwise angular acceleration of 1.67 rad/s². The tension T in the upper (taut) segment of the belt is 145 N. (a) What is the tension (in N) in the lower (slack) segment of the belt? N (b) What If? You replace the belt with a different one (one slightly longer and looser, but still tight enough that it does not sag). You again turn on the motor so that the disk accelerates clockwise. The upper segment of the belt once again has a tension of 145 N, but now the tension in the lower belt is exactly zero. What is the magnitude of the angular acceleration (in rad/s²)? rad/s²arrow_forwardA bridge truss extends x = 217 m across a river (shown in the figure below) where 0 = 40°. The structure is free to slide horizontally to permit thermal expansion. The structural components are connected by pin joints, and the masses of the bars are small compared with the mass of a 1300 kg car at the center. Calculate the force of tension or compression in each structural component (in N). B D T T T T T 22820 AB AC BC ||| || || || BD N ---Select--- N ---Select--- N ---Select--- N ---Select--- DE N ---Select--- T DC= N ---Select--- TEC N ---Select--- с ✓ Earrow_forwardno ai pleasearrow_forward
- A block of mass m₁ = 1.85 kg and a block of mass m₂ is 0.360 for both blocks. 5.90 kg are connected by a massless string over a pulley in the shape of a solid disk having a mass of M = 10.0 kg. The fixed, wedge-shaped ramp makes an angle of 0 = 30.0° as shown in the figure. The coefficient of kinetic friction m M, R m2 Ꮎ (a) Determine the acceleration of the two blocks. (Enter the magnitude of the acceleration.) m/s2 (b) Determine the tensions in the string on both sides of the pulley. left of the pulley right of the pulley N Narrow_forwardConsider as a system the Sun with Venus in a circular orbit around it. Find the magnitude of the change in the velocity of the Sun relative to the center of mass of the system during the time Venus completes half an orbit. Assume the mass of the Sun is 5.68 x 1029 kg, the mass of Venus is 4.87 × 1024 kg, its period is 1.94 × 107 s, and the radius of its orbit is 1.08 × 1011 m. Ignore the influence of other celestial objects. m/sarrow_forwardYour physics instructor loves to put on physics magic shows for elementary school children. He is working on a new trick and has asked you, his star physics student, for assistance. The figure below shows the apparatus he is designing. Cup Hinged end - Support stick A small ball rests on a support so that the center of the ball is at the same height as the upper lip of a cup of negligible mass that is attached to a uniform board of length = 1.89 m. When the support stick is snatched away, the ball will fall and the board will rotate around the hinged end. As the board hits the table, your instructor wants the ball to fall into the cup. The larger the angle 0, the more time the elementary school children will have to watch the progress of the trick. But if the angle is too large, the cup may not pull ahead of the ball. For example, in the limiting case of 90°, the board would not fall at all! (a) Your instructor wishes to know the minimum angle 0 (in degrees) at which the support would…arrow_forward
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