Balanced form of the stated chemical equation. Concept introduction: According to the law of conservation of mass, mass can neither be created nor destroyed. The mass of reactants is equal to the mass of products formed. Therefore a chemical equation, having lesser number of moles of an element on either side of a reaction, is balanced using appropriate numerical coefficients to satisfy the law of conservation of mass.
Balanced form of the stated chemical equation. Concept introduction: According to the law of conservation of mass, mass can neither be created nor destroyed. The mass of reactants is equal to the mass of products formed. Therefore a chemical equation, having lesser number of moles of an element on either side of a reaction, is balanced using appropriate numerical coefficients to satisfy the law of conservation of mass.
Interpretation: Balanced form of the stated chemical equation.
Concept introduction: According to the law of conservation of mass, mass can neither be created nor destroyed. The mass of reactants is equal to the mass of products formed. Therefore a chemical equation, having lesser number of moles of an element on either side of a reaction, is balanced using appropriate numerical coefficients to satisfy the law of conservation of mass.
(b)
Interpretation Introduction
Interpretation: The mass of CO that can react with 0.350kg(350g) of Fe2O3 .
Concept introduction: The balanced chemical equation is:
Fe2O3(s)+3CO(g)→2Fe(s)+3CO2(g)
Here, one mole of ferric oxide reacts with three moles of carbon monoxide to form 2 moles of iron and three moles of carbon dioxide.
(c)
Interpretation Introduction
Interpretation: The mass of Fe and CO2 formed when 350g of Fe2O3 reacts with CO
Concept introduction: The balanced chemical equation is:
Fe2O3(s)+3CO(g)→2Fe(s)+3CO2(g)
Here, one mole of ferric oxide reacts with three moles of carbon monoxide to form 2 moles of iron and three moles of carbon dioxide.
(d)
Interpretation Introduction
Interpretation: The justification corresponding to the consistency of the solutions in part (b) and part (c) with the law of conservation of mass.
Concept introduction: According to the law of conservation of mass,
An essential part of the experimental design process is to select appropriate dependent and
independent variables.
True
False
10.00 g of Compound X with molecular formula C₂Hg are burned in a constant-pressure calorimeter containing 40.00 kg of water at 25 °C. The temperature of
the water is observed to rise by 2.604 °C. (You may assume all the heat released by the reaction is absorbed by the water, and none by the calorimeter itself.)
Calculate the standard heat of formation of Compound X at 25 °C.
Be sure your answer has a unit symbol, if necessary, and round it to the correct number of significant digits.
need help not sure what am doing wrong step by step please answer is 971A
During the lecture, we calculated the Debye length at physiological salt concentrations and temperature, i.e. at an ionic strength of 150 mM (i.e. 0.150 mol/l) and a temperature of T=310 K. We predicted that electrostatic interactions are effectively screened beyond distances of 8.1 Å in solutions with a physiological salt concentration.
What is the Debye length in a sample of distilled water with an ionic strength of 10.0 µM (i.e. 1.00 * 10-5 mol/l)? Assume room temperature, i.e. T= 298 K, and provide your answer as a numerical expression with 3 significant figures in Å (1 Å = 10-10 m).
Chapter 3 Solutions
Pearson eText Chemistry: The Central Science -- Access Card
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