Chapter 3, Problem 57QP

Interpretation Introduction

Interpretation:

The number of ${\text{AsO}}_3$ molecules corresponding to the given value of ${\text{LD}}_{50}$ for a $184\text{-lb}$ man is to be calculated assuming the test animals and humans have same ${\text{LD}}_{50}$.

Concept introduction:

Stoichiometry involves calculations of number of atoms of reactants and products in a balanced chemical equation.

Number of moles of a compound is the ratio of the given mass and the molar mass.

The ${\text{LD}}_{50}$ is an abbreviation for "Lethal Dose, $50\%$" which is the amount of the substance required (usually per body weight) to kill $50\%$ of the test population.

Formula used for calculating ${\text{LD}}_{50}$ value is ${\text{LD}}_{50}\text{value}=\frac{\text{no of grams of substance}}{\text{body wt in Kg}}$.

$1\text{ kilogram (kg)}$ is equal to $2.2046\text{ pounds (lbs)}$.