Explanation 1) Concept: We can use formula of scalar product of two vectors and vector product of two vectors. 2) Formula: i. a → · b → = a b cos ⁡ θ ii. a → × b → = a b sin ⁡ θ 3) Given: i. The magnitude of vector a → i s a = 10 u n i t s ii. The magnitude of vector b → i s b = 6.0 u n i t s iii. The angle between a → and b → is θ = 60 ° 4) Calculations:

10th Edition

ISBN: 9781118230725

Author: David Halliday, Robert Resnick, Jearl Walker

Publisher: Wiley, John & Sons, Incorporated

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Question

Chapter 3, Problem 53P

To determine

To find:

a) The scalar product of two vectors a→·b→

b) The magnitude of the vector product a→×b→

Expert Solution & Answer

Chapter 3 Solutions

Fundamentals of Physics Extended

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Knowledge Booster

a) The scalar product of two vectors a → · b → b) The magnitude of the vector product a → × b →

Solution Summary: The author explains how to find the scalar product of two vectors and the magnitude of the vector product.

To find:

a) The scalar product of two vectors a→·b→

b) The magnitude of the vector product a→×b→

Chapter 3 Solutions

a) The scalar product of two vectors a → · b → b) The magnitude of the vector product a → × b →

Solution Summary: The author explains how to find the scalar product of two vectors and the magnitude of the vector product.

To find: a) The scalar product of two vectors a→·b→ b) The magnitude of the vector product a→×b→

Chapter 3 Solutions

To find:

a) The scalar product of two vectors a→·b→

b) The magnitude of the vector product a→×b→