In a meeting of mimes, mime 1 goes through a displacement d → 1 = (4.0 m) i ^ + (5.0 m) j ^ and mime 2 goes through a displacement d → 2 = (−3.0 m) i ^ + (4.0 m) j ^ . What are (a) d → 1 × d → 2 , (b) d → 1 d → 2 , (c) ( d → 1 + d → 2 ) · d → 2 , and (d) the component of d → 1 along the direction of d → 2 ? ( Hint: For (d), see Eq. 3-20 and Fig. 3-18.)
In a meeting of mimes, mime 1 goes through a displacement d → 1 = (4.0 m) i ^ + (5.0 m) j ^ and mime 2 goes through a displacement d → 2 = (−3.0 m) i ^ + (4.0 m) j ^ . What are (a) d → 1 × d → 2 , (b) d → 1 d → 2 , (c) ( d → 1 + d → 2 ) · d → 2 , and (d) the component of d → 1 along the direction of d → 2 ? ( Hint: For (d), see Eq. 3-20 and Fig. 3-18.)
In a meeting of mimes, mime 1 goes through a displacement
d
→
1
= (4.0 m)
i
^
+ (5.0 m)
j
^
and mime 2 goes through a displacement
d
→
2
= (−3.0 m)
i
^
+ (4.0 m)
j
^
. What are (a)
d
→
1
×
d
→
2
, (b)
d
→
1
d
→
2
, (c) (
d
→
1
+
d
→
2
) ·
d
→
2
, and (d) the component of
d
→
1
along the direction of
d
→
2
? (Hint: For (d), see Eq. 3-20 and Fig. 3-18.)
According to the text, there are two equations from which the five equations may be derived by taking the integral or antiderivative. Consider the
following equations and choose the two equations to which it is referring.
dv
A. x=
dt
dx
В. у %3
dt
dv
С. а %3
dt
D. x- x, =}(v+vo Jt
(A) A and C
(в) С and D
(c) B and C
D) A and B
The figure shows three vectors. Vector A→ has a length of 32.0, vector B→ has a length of 64.0, and vector C→ has a length of 22.0.
Find each magnitude and direction.
Ina meeting of mimes, mime 1 goes through a displacement á 1 = ( 8.69 m )ì + (8.10 m )} ar
8 d and mime 2 goes through a
d 2 =
-9.93 m )î + (8.1 m )j.What are (a) d , × d 2, (b) d
2. (c) (
1+ d 2)· d 2,and
displacement
(d) the component of á 1 along the direction of
2?
Give your answers in standard SI units.
(a) Numder
Unit
(b) Number
i
Unit
(c) Number
i
Unit
(d) Number
Unit
>
>
>
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