Systems Architecture
Systems Architecture
7th Edition
ISBN: 9781305080195
Author: Stephen D. Burd
Publisher: Cengage Learning
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Chapter 3, Problem 4RQ

Explanation of Solution

Range of a 16 bit twos complement value:

  • A numeric range of twos complement is “(2n1)” to “(2n1)1” where “n” is the number of bits.
  • Substitute the value “16” for “n” to find the range of 16 bit twos complement value.

(2n1)=(2161)=(

Explanation of Solution

Range of a 16 bit excess notation:

  • A numeric range of excess notation is “(2n1)” to “2(n1)1” where “n” is the number of bits.
  • Substitute the value “16” for “n” to find the range of 16 bit twos complement value.

(2n1)=(2161)=(

Explanation of Solution

Range of a 16 bit unsigned integer value:

  • A numeric range of unsigned integer is “0” to “2n1” where “n” is the number of bits.
  • Substitute the value “16” for “n” to find the range of 16 bit unsigned value

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