In Exercises 43-46, x and y are related by the given equation. Use implicit differentiation to calculate the value of d y d x for the given values of x and y . x y 2 − x 3 = 10 ; x = 2 , y = 3
In Exercises 43-46, x and y are related by the given equation. Use implicit differentiation to calculate the value of d y d x for the given values of x and y . x y 2 − x 3 = 10 ; x = 2 , y = 3
Solution Summary: The author explains how to calculate the value of dx using implicit differentiation. The product rule and power rule of differentiation are used on the left side of the equation.
In Exercises 43-46,
x
and
y
are related by the given equation. Use implicit differentiation to calculate the value of
d
y
d
x
for the given values of
x
and
y
.
x
y
2
−
x
3
=
10
;
x
=
2
,
y
=
3
With integration, one of the major concepts of calculus. Differentiation is the derivative or rate of change of a function with respect to the independent variable.
4. Use method of separation of variable to solve the following wave equation
მłu
J²u
subject to
u(0,t) =0, for t> 0,
u(л,t) = 0, for t> 0,
=
t> 0,
at²
ax²'
u(x, 0) = 0,
0.01 x,
ut(x, 0) =
Π
0.01 (π-x),
0
Solve the following heat equation by method of separation variables:
ди
=
at
subject to
u(0,t) =0, for
-16024
ძx2 •
t>0, 0 0,
ux (4,t) = 0, for
t> 0,
u(x, 0) =
(x-3,
\-1,
0 < x ≤2
2≤ x ≤ 4.
ex
5.
important aspects.
Graph f(x)=lnx. Be sure to make your graph big enough to easily read (use the space given.) Label all
6
33
Chapter 3 Solutions
Student Solutions Manual for Calculus & Its Applications and Calculus & Its Applications, Brief Version
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