(a) Interpretation: The polyatomic anion in KBrO 3 should be identified. The number of protons and electrons in the identified anion should be calculated. Concept Introduction: Charge of an ion: The group number of a maingroup element can be used to determine the charge on an ion derived from that element: For elements in groups 1A, 2A, and 3A, the group number is thecharge on the cations they make.For elements in groups 6A and 7A, the anion charge = 8 − (thegroup number). Polyatomic ions: A polyatomic ion is a cation or an anion that contains two or more atoms, which are bound through covalent bonds. Ionic compounds: Anions and cations are attracted to each other via ionic bonds and form ionic compounds. The overall charge of an ionic compounds is zero (sum of the charge of each ion involved must be zero).

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Answer 1

Question

Chapter 3, Problem 46P

Interpretation Introduction

(a)

Interpretation:

The polyatomic anion in KBrO₃ should be identified. The number of protons and electrons in the identified anion should be calculated.

Concept Introduction:

Charge of an ion:

The group number of a maingroup element can be used to determine the charge on an ion derived from that element:

For elements in groups 1A, 2A, and 3A, the group number is thecharge on the cations they make.For elements in groups 6A and 7A, the anion charge = 8 − (thegroup number).

Polyatomic ions:

A polyatomic ion is a cation or an anion that contains two or more atoms, which are bound through covalent bonds.

Ionic compounds:

Anions and cations are attracted to each other via ionic bonds and form ionic compounds. The overall charge of an ionic compounds is zero (sum of the charge of each ion involved must be zero).

Interpretation Introduction

(b)

Interpretation:

The polyatomic anion in CaHPO₃ should be identified. The number of protons and electrons in the identified anion should be calculated.

Concept Introduction:

Charge of an ion:

The group number of a maingroup element can be used to determine the charge on an ion derived from that element:

For elements in groups 1A, 2A, and 3A, the group number is thecharge on the cations they make.For elements in groups 6A and 7A, the anion charge = 8 − (thegroup number).

Polyatomic ions:

A polyatomic ion is a cation or an anion that contains two or more atoms, which are bound through covalent bonds.

Ionic compounds:

Anions and cations are attracted to each other via ionic bonds and form ionic compounds. The overall charge of an ionic compounds is zero (sum of the charge of each ion involved must be zero).

Interpretation Introduction

(b)

Interpretation:

The polyatomic anion in CaHPO₃ should be identified. The number of protons and electrons in the identified anion should be calculated.

Concept Introduction:

Charge of an ion:

The group number of a maingroup element can be used to determine the charge on an ion derived from that element:

For elements in groups 1A, 2A, and 3A, the group number is thecharge on the cations they make.For elements in groups 6A and 7A, the anion charge = 8 − (thegroup number).

Polyatomic ions:

A polyatomic ion is a cation or an anion that contains two or more atoms, which are bound through covalent bonds.

Ionic compounds:

Anions and cations are attracted to each other via ionic bonds and form ionic compounds. The overall charge of an ionic compounds is zero (sum of the charge of each ion involved must be zero).

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1. Calculate the accurate monoisotopic mass (using all 1H, 12C, 14N, 160 and 35CI) for your product using the table in your lab manual. Don't include the Cl, since you should only have [M+H]*. Compare this to the value you see on the LC-MS printout. How much different are they? 2. There are four isotopic peaks for the [M+H]* ion at m/z 240, 241, 242 and 243. For one point of extra credit, explain what each of these is and why they are present. 3. There is a fragment ion at m/z 184. For one point of extra credit, identify this fragment and confirm by calculating the accurate monoisotopic mass. 4. The UV spectrum is also at the bottom of your printout. For one point of extra credit, look up the UV spectrum of bupropion on Google Images and compare to your spectrum. Do they match? Cite your source. 5. For most of you, there will be a second chromatographic peak whose m/z is 74 (to a round number). For one point of extra credit, see if you can identify this molecule as well and confirm by…

Please draw, not just describe!

can you draw each step on a piece of a paper please this is very confusing to me

Answer 2

Question

Chapter 3, Problem 46P

Interpretation Introduction

(a)

Interpretation:

The polyatomic anion in KBrO₃ should be identified. The number of protons and electrons in the identified anion should be calculated.

Concept Introduction:

Charge of an ion:

The group number of a maingroup element can be used to determine the charge on an ion derived from that element:

For elements in groups 1A, 2A, and 3A, the group number is thecharge on the cations they make.For elements in groups 6A and 7A, the anion charge = 8 − (thegroup number).

Polyatomic ions:

A polyatomic ion is a cation or an anion that contains two or more atoms, which are bound through covalent bonds.

Ionic compounds:

Anions and cations are attracted to each other via ionic bonds and form ionic compounds. The overall charge of an ionic compounds is zero (sum of the charge of each ion involved must be zero).

Interpretation Introduction

(b)

Interpretation:

The polyatomic anion in CaHPO₃ should be identified. The number of protons and electrons in the identified anion should be calculated.

Concept Introduction:

Charge of an ion:

The group number of a maingroup element can be used to determine the charge on an ion derived from that element:

For elements in groups 1A, 2A, and 3A, the group number is thecharge on the cations they make.For elements in groups 6A and 7A, the anion charge = 8 − (thegroup number).

Polyatomic ions:

A polyatomic ion is a cation or an anion that contains two or more atoms, which are bound through covalent bonds.

Ionic compounds:

Anions and cations are attracted to each other via ionic bonds and form ionic compounds. The overall charge of an ionic compounds is zero (sum of the charge of each ion involved must be zero).

Interpretation Introduction

(b)

Interpretation:

The polyatomic anion in CaHPO₃ should be identified. The number of protons and electrons in the identified anion should be calculated.

Concept Introduction:

Charge of an ion:

The group number of a maingroup element can be used to determine the charge on an ion derived from that element:

For elements in groups 1A, 2A, and 3A, the group number is thecharge on the cations they make.For elements in groups 6A and 7A, the anion charge = 8 − (thegroup number).

Polyatomic ions:

A polyatomic ion is a cation or an anion that contains two or more atoms, which are bound through covalent bonds.

Ionic compounds:

Anions and cations are attracted to each other via ionic bonds and form ionic compounds. The overall charge of an ionic compounds is zero (sum of the charge of each ion involved must be zero).

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Students have asked these similar questions

1. Calculate the accurate monoisotopic mass (using all 1H, 12C, 14N, 160 and 35CI) for your product using the table in your lab manual. Don't include the Cl, since you should only have [M+H]*. Compare this to the value you see on the LC-MS printout. How much different are they? 2. There are four isotopic peaks for the [M+H]* ion at m/z 240, 241, 242 and 243. For one point of extra credit, explain what each of these is and why they are present. 3. There is a fragment ion at m/z 184. For one point of extra credit, identify this fragment and confirm by calculating the accurate monoisotopic mass. 4. The UV spectrum is also at the bottom of your printout. For one point of extra credit, look up the UV spectrum of bupropion on Google Images and compare to your spectrum. Do they match? Cite your source. 5. For most of you, there will be a second chromatographic peak whose m/z is 74 (to a round number). For one point of extra credit, see if you can identify this molecule as well and confirm by…

Please draw, not just describe!

can you draw each step on a piece of a paper please this is very confusing to me

Answer 3

Question

Chapter 3, Problem 46P

Interpretation Introduction

(a)

Interpretation:

The polyatomic anion in KBrO₃ should be identified. The number of protons and electrons in the identified anion should be calculated.

Concept Introduction:

Charge of an ion:

The group number of a maingroup element can be used to determine the charge on an ion derived from that element:

For elements in groups 1A, 2A, and 3A, the group number is thecharge on the cations they make.For elements in groups 6A and 7A, the anion charge = 8 − (thegroup number).

Polyatomic ions:

A polyatomic ion is a cation or an anion that contains two or more atoms, which are bound through covalent bonds.

Ionic compounds:

Anions and cations are attracted to each other via ionic bonds and form ionic compounds. The overall charge of an ionic compounds is zero (sum of the charge of each ion involved must be zero).

Interpretation Introduction

(b)

Interpretation:

The polyatomic anion in CaHPO₃ should be identified. The number of protons and electrons in the identified anion should be calculated.

Concept Introduction:

Charge of an ion:

The group number of a maingroup element can be used to determine the charge on an ion derived from that element:

For elements in groups 1A, 2A, and 3A, the group number is thecharge on the cations they make.For elements in groups 6A and 7A, the anion charge = 8 − (thegroup number).

Polyatomic ions:

A polyatomic ion is a cation or an anion that contains two or more atoms, which are bound through covalent bonds.

Ionic compounds:

Anions and cations are attracted to each other via ionic bonds and form ionic compounds. The overall charge of an ionic compounds is zero (sum of the charge of each ion involved must be zero).

Interpretation Introduction

(b)

Interpretation:

The polyatomic anion in CaHPO₃ should be identified. The number of protons and electrons in the identified anion should be calculated.

Concept Introduction:

Charge of an ion:

The group number of a maingroup element can be used to determine the charge on an ion derived from that element:

For elements in groups 1A, 2A, and 3A, the group number is thecharge on the cations they make.For elements in groups 6A and 7A, the anion charge = 8 − (thegroup number).

Polyatomic ions:

A polyatomic ion is a cation or an anion that contains two or more atoms, which are bound through covalent bonds.

Ionic compounds:

Anions and cations are attracted to each other via ionic bonds and form ionic compounds. The overall charge of an ionic compounds is zero (sum of the charge of each ion involved must be zero).

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Answer 4

Question

Chapter 3, Problem 46P

Interpretation Introduction

(a)

Interpretation:

The polyatomic anion in KBrO₃ should be identified. The number of protons and electrons in the identified anion should be calculated.

Concept Introduction:

Charge of an ion:

The group number of a maingroup element can be used to determine the charge on an ion derived from that element:

For elements in groups 1A, 2A, and 3A, the group number is thecharge on the cations they make.For elements in groups 6A and 7A, the anion charge = 8 − (thegroup number).

Polyatomic ions:

A polyatomic ion is a cation or an anion that contains two or more atoms, which are bound through covalent bonds.

Ionic compounds:

Anions and cations are attracted to each other via ionic bonds and form ionic compounds. The overall charge of an ionic compounds is zero (sum of the charge of each ion involved must be zero).

Interpretation Introduction

(b)

Interpretation:

The polyatomic anion in CaHPO₃ should be identified. The number of protons and electrons in the identified anion should be calculated.

Concept Introduction:

Charge of an ion:

The group number of a maingroup element can be used to determine the charge on an ion derived from that element:

For elements in groups 1A, 2A, and 3A, the group number is thecharge on the cations they make.For elements in groups 6A and 7A, the anion charge = 8 − (thegroup number).

Polyatomic ions:

A polyatomic ion is a cation or an anion that contains two or more atoms, which are bound through covalent bonds.

Ionic compounds:

Anions and cations are attracted to each other via ionic bonds and form ionic compounds. The overall charge of an ionic compounds is zero (sum of the charge of each ion involved must be zero).

Interpretation Introduction

(b)

Interpretation:

The polyatomic anion in CaHPO₃ should be identified. The number of protons and electrons in the identified anion should be calculated.

Concept Introduction:

Charge of an ion:

The group number of a maingroup element can be used to determine the charge on an ion derived from that element:

For elements in groups 1A, 2A, and 3A, the group number is thecharge on the cations they make.For elements in groups 6A and 7A, the anion charge = 8 − (thegroup number).

Polyatomic ions:

A polyatomic ion is a cation or an anion that contains two or more atoms, which are bound through covalent bonds.

Ionic compounds:

Anions and cations are attracted to each other via ionic bonds and form ionic compounds. The overall charge of an ionic compounds is zero (sum of the charge of each ion involved must be zero).

Expert Solution & Answer

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Answer 5

Chapter 3, Problem 46P

Interpretation Introduction

(a)

Interpretation:

The polyatomic anion in KBrO₃ should be identified. The number of protons and electrons in the identified anion should be calculated.

Concept Introduction:

Charge of an ion:

The group number of a maingroup element can be used to determine the charge on an ion derived from that element:

For elements in groups 1A, 2A, and 3A, the group number is thecharge on the cations they make.For elements in groups 6A and 7A, the anion charge = 8 − (thegroup number).

Polyatomic ions:

A polyatomic ion is a cation or an anion that contains two or more atoms, which are bound through covalent bonds.

Ionic compounds:

Anions and cations are attracted to each other via ionic bonds and form ionic compounds. The overall charge of an ionic compounds is zero (sum of the charge of each ion involved must be zero).

Interpretation Introduction

(b)

Interpretation:

The polyatomic anion in CaHPO₃ should be identified. The number of protons and electrons in the identified anion should be calculated.

Concept Introduction:

Charge of an ion:

The group number of a maingroup element can be used to determine the charge on an ion derived from that element:

For elements in groups 1A, 2A, and 3A, the group number is thecharge on the cations they make.For elements in groups 6A and 7A, the anion charge = 8 − (thegroup number).

Polyatomic ions:

A polyatomic ion is a cation or an anion that contains two or more atoms, which are bound through covalent bonds.

Ionic compounds:

Anions and cations are attracted to each other via ionic bonds and form ionic compounds. The overall charge of an ionic compounds is zero (sum of the charge of each ion involved must be zero).

Interpretation Introduction

(b)

Interpretation:

The polyatomic anion in CaHPO₃ should be identified. The number of protons and electrons in the identified anion should be calculated.

Concept Introduction:

Charge of an ion:

The group number of a maingroup element can be used to determine the charge on an ion derived from that element:

For elements in groups 1A, 2A, and 3A, the group number is thecharge on the cations they make.For elements in groups 6A and 7A, the anion charge = 8 − (thegroup number).

Polyatomic ions:

A polyatomic ion is a cation or an anion that contains two or more atoms, which are bound through covalent bonds.

Ionic compounds:

Anions and cations are attracted to each other via ionic bonds and form ionic compounds. The overall charge of an ionic compounds is zero (sum of the charge of each ion involved must be zero).

Answer 6

Chapter 3, Problem 46P

Interpretation Introduction

(a)

Interpretation:

The polyatomic anion in KBrO₃ should be identified. The number of protons and electrons in the identified anion should be calculated.

Concept Introduction:

Charge of an ion:

The group number of a maingroup element can be used to determine the charge on an ion derived from that element:

For elements in groups 1A, 2A, and 3A, the group number is thecharge on the cations they make.For elements in groups 6A and 7A, the anion charge = 8 − (thegroup number).

Polyatomic ions:

A polyatomic ion is a cation or an anion that contains two or more atoms, which are bound through covalent bonds.

Ionic compounds:

Anions and cations are attracted to each other via ionic bonds and form ionic compounds. The overall charge of an ionic compounds is zero (sum of the charge of each ion involved must be zero).

Answer 7

Chapter 3, Problem 46P

Interpretation Introduction

(a)

Interpretation:

The polyatomic anion in KBrO₃ should be identified. The number of protons and electrons in the identified anion should be calculated.

Concept Introduction:

Charge of an ion:

The group number of a maingroup element can be used to determine the charge on an ion derived from that element:

For elements in groups 1A, 2A, and 3A, the group number is thecharge on the cations they make.For elements in groups 6A and 7A, the anion charge = 8 − (thegroup number).

Polyatomic ions:

A polyatomic ion is a cation or an anion that contains two or more atoms, which are bound through covalent bonds.

Ionic compounds:

Anions and cations are attracted to each other via ionic bonds and form ionic compounds. The overall charge of an ionic compounds is zero (sum of the charge of each ion involved must be zero).

Answer 8

Interpretation Introduction

(b)

Interpretation:

The polyatomic anion in CaHPO₃ should be identified. The number of protons and electrons in the identified anion should be calculated.

Concept Introduction:

Charge of an ion:

The group number of a maingroup element can be used to determine the charge on an ion derived from that element:

For elements in groups 1A, 2A, and 3A, the group number is thecharge on the cations they make.For elements in groups 6A and 7A, the anion charge = 8 − (thegroup number).

Polyatomic ions:

A polyatomic ion is a cation or an anion that contains two or more atoms, which are bound through covalent bonds.

Ionic compounds:

Anions and cations are attracted to each other via ionic bonds and form ionic compounds. The overall charge of an ionic compounds is zero (sum of the charge of each ion involved must be zero).

Interpretation Introduction

(b)

Interpretation:

The polyatomic anion in CaHPO₃ should be identified. The number of protons and electrons in the identified anion should be calculated.

Concept Introduction:

Charge of an ion:

The group number of a maingroup element can be used to determine the charge on an ion derived from that element:

For elements in groups 1A, 2A, and 3A, the group number is thecharge on the cations they make.For elements in groups 6A and 7A, the anion charge = 8 − (thegroup number).

Polyatomic ions:

A polyatomic ion is a cation or an anion that contains two or more atoms, which are bound through covalent bonds.

Ionic compounds:

Anions and cations are attracted to each other via ionic bonds and form ionic compounds. The overall charge of an ionic compounds is zero (sum of the charge of each ion involved must be zero).

Answer 9

Interpretation Introduction

(b)

Interpretation:

The polyatomic anion in CaHPO₃ should be identified. The number of protons and electrons in the identified anion should be calculated.

Concept Introduction:

Charge of an ion:

The group number of a maingroup element can be used to determine the charge on an ion derived from that element:

For elements in groups 1A, 2A, and 3A, the group number is thecharge on the cations they make.For elements in groups 6A and 7A, the anion charge = 8 − (thegroup number).

Polyatomic ions:

A polyatomic ion is a cation or an anion that contains two or more atoms, which are bound through covalent bonds.

Ionic compounds:

Anions and cations are attracted to each other via ionic bonds and form ionic compounds. The overall charge of an ionic compounds is zero (sum of the charge of each ion involved must be zero).

Answer 10

Interpretation Introduction

(b)

Interpretation:

The polyatomic anion in CaHPO₃ should be identified. The number of protons and electrons in the identified anion should be calculated.

Concept Introduction:

Charge of an ion:

The group number of a maingroup element can be used to determine the charge on an ion derived from that element:

For elements in groups 1A, 2A, and 3A, the group number is thecharge on the cations they make.For elements in groups 6A and 7A, the anion charge = 8 − (thegroup number).

Polyatomic ions:

A polyatomic ion is a cation or an anion that contains two or more atoms, which are bound through covalent bonds.

Ionic compounds:

Anions and cations are attracted to each other via ionic bonds and form ionic compounds. The overall charge of an ionic compounds is zero (sum of the charge of each ion involved must be zero).

Answer 11

Interpretation Introduction

(b)

Interpretation:

The polyatomic anion in CaHPO₃ should be identified. The number of protons and electrons in the identified anion should be calculated.

Concept Introduction:

Charge of an ion:

The group number of a maingroup element can be used to determine the charge on an ion derived from that element:

For elements in groups 1A, 2A, and 3A, the group number is thecharge on the cations they make.For elements in groups 6A and 7A, the anion charge = 8 − (thegroup number).

Polyatomic ions:

A polyatomic ion is a cation or an anion that contains two or more atoms, which are bound through covalent bonds.

Ionic compounds:

Anions and cations are attracted to each other via ionic bonds and form ionic compounds. The overall charge of an ionic compounds is zero (sum of the charge of each ion involved must be zero).

Answer 12

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Answer 13

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Answer 14

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Answer 15

Ch. 3.1 - Predict whether the bonds in the following species...Ch. 3.1 - (a) Classify each example of molecular art as a...Ch. 3.1 - Label each of the following as a compound,...Ch. 3.1 - Vitamin C has the chemical formula C6H8O6. Even if...Ch. 3.2 - Prob. 3.3PP Ch. 3.2 - Write the ion symbol for an atom with the given...Ch. 3.2 - How many protons and electrons are present in each...Ch. 3.2 - Prob. 3.3P Ch. 3.2 - Prob. 3.6PP Ch. 3.2 - Prob. 3.4P

Solution Summary: The author explains that the polyatomic anion in KBrO 3 should be identified and the number of protons and electrons in the identified ion calculated.

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Chapter 3 Solutions