You are working as an assistant to an air-traffic controller at the local airport, from which small airplanes take off and land. Your job is to make sure that airplanes are not closer to each other than a minimum safe separation distance of 2.00 km. You observe two small aircraft on your radar screen, out over the ocean surface. The first is at altitude 800 m above the surface, horizontal distance 19.2 km. and 25.0° south of west. The second aircraft is at altitude 1 100 m, horizontal distance 17.6 km, and 20.0° south of west. Your supervisor is concerned that the two aircraft are too close together and asks for a separatism distance for the two airplanes. (Place the x axis west, the y axis south, and the z axis vertical.)
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Chapter 3 Solutions
Physics for Scientists and Engineers
- A vector points from the origin into the second quadrant of the xy plane. What can you conclude about its components? (a) Both components are positive. (b) The x component is positive, and the y component is negative. (c) The x component is negative, and the y component is positive. (d) Both components are negative. (e) More than one answer is possible.arrow_forwardYou are working at a radar station for the Coast Guard. While everyone else is out to lunch, you hear a distress call from a sinking ship. The ship is located at a distance of 51.2km from the station, at a bearing of 36° west of north. On your radar screen you see the location of four other ships as follows: Quick! Which ship do you contact to help the sinking ship? Ship number one has a distance from station at 36.1km at a bearing of 42° west of north, at maximum speed of 30.0km/h. The ship number two has a distance of 37.3km at a bearing of 61° west of North, at maximum speed of 38.0km/h. The ship number three has a distance from station 10.0km at a bearing of 36° west of North at a maximum speed of 32.0km/h. The ship number four has a distance from station 51.2km at a bearing 79° west of North at maximum speed of 45.0km/h. Which ship will get there in the shortest time interval? Assume that each ship would accelerate quickly to its maximum speed and then maintain that constant speed…arrow_forwardYou are trying reach the microwave antenna in a middle of the night. You locator tells you that you are 122.0 meters away from the location in the direction of 58 degree east of south. You traveled 72 meters due west along walk way. How much farther and what direction must you walk to reach the antenna. Please show the complete solution and drawing. Solution must be readable. Thank you.arrow_forward
- A Freshman MSU student tours around the MSU campus. From the College of Natural Sciences and Mathematics (CNSM), he walks 300 m, 25° N of W towards the administration building, then he walks for 450 m, 67° W of S reaching the College of SPEAR. From the College of SPEAR, he walked for another 180 m, 59° S of E to be able to reach the College of Business Administration and Accountancy. In order for the student to return to his starting point (which is the CNSM), how far must he walk and in what direction?arrow_forwardGrade 11 Physics: I haven't yet learned the range formula but don't know how to adjust the angle to hit the target by using the formulas I have used. A water balloon is fired at 34.0 m/s from a water cannon, which is aimed at an angle of 18° above the ground. The centre of the cannon’s target (which has a radius of 1.0 m) is painted on the asphalt 42.0 m away from the water cannon. Will the balloon hit the target? Justify your response with calculations that indicate where the water balloon will land and make one suggestion about how to adjust the water cannon so that the water balloon will hit the target. sin??θ=opphyp sin??θ=v⃗yv⃗ v⃗y=v⃗sinθ =(34.0m/s)sin 18° =10.5m/s[up] cosθ=adjhyp cosθ=v⃗xv⃗ v⃗x=v⃗cosθ =(34.0m/s)cos 18° =32.3m/s[forward] Let [up] be positive Δd⃗=0 a⃗=-9.8m/s2[down] v⃗y1=10.5m/s[up] Δt= ? Δd⃗=v⃗y1Δt+12a⃗(Δt)2 0=(10.5m/s)Δt+12(-9.8m/s2)(Δt)2 0=(10.5m/s)Δt-4.9m/s2(Δt)2 0=Δt (10.5m/s-4.9m/s2Δt) Δt=0 or Δt=2.14s v⃗x=32.3m/s [forward] Δt=2.14s Δd⃗x= ?…arrow_forwardPart (A). You are designing the radar system to track the UFOs appearing in the city.In your setup, you have two radars R1 and R2, that are 20 miles from each other. And this happens! Oneday the radars detect a UFO somewhere between them. According to the data provided, the angle ofelevation measured by R1 is 35 degrees. The angle of elevation measured by R2 is 15 degrees. What isthe elevation of the UFO? Round your answer to the nearest thousandth mile. Part (B). Now, one of your radar stations is broken. So you have only one radar. The workingradar suddenly detects another UFO. According to the data provided, the angle of elevation of the UFOfrom some point A on the ground is 60 degrees.After flying 15 seconds horizontally, the angle of elevationchanges to 30 degrees.Also, it is detected by your working radar that the UFO is flying at a speed of 200 m/s,can you find the elevation (height) at which the UFO is flying?Round your answer to the nearest thousandth meter.arrow_forward
- A jet takes off bearing N 32° W and flies 6 miles, and then makes a right turn (90°) and flies 20 miles farther. If the control tower operator wanted to locate the plane, what bearing would he use? Round to the nearest degree.arrow_forwardDisplacement d1 is in the yz plane 59.9° from the positive direction of the y axis, has a positive z component, and has a magnitude of 3.39 m. Displacement d2 is in the xz plane 20.8° from the positive direction of the x axis, has a positive z component, and has magnitude 1.02 m. What is the angle between d1 and d2?arrow_forwardI’m confused on p 3.19.arrow_forward
- A small airplane leaves an airport on an overcast day and is later sighted 215 km away, in a direction making an angle of 22° east of due north. This means that the direction is not due north (directly toward the north) but is rotated 22° toward the east from due north. How far east and north is the airplane from the airport when sighted?arrow_forwardVector A is 3 units in length and points along the positive x-axis; vector B is 4 units in length and points along a direction 37° from the positive x-axis, and vector C is 11.5 units and points along a direction 150°. What is the direction of the resultant with respect to the positive x-axis in degrees? O 55.5° O 133.2 ° O 114.77° O 284 ° O 85.1 ° 青arrow_forwardA surveyor measures the distance across a straight river by the following method: Starting directly across from a tree on the opposite bank, he walks x = 114 m along the riverbank to establish a baseline. Then he sights across to the tree. The angle from his baseline to the tree is θ = 36.8°. How wide is the river? y= ? An overhead view of a straight, horizontal river, with a tree on the upper-left bank. A point is marked on the lower right bank. The horizontal distance to the tree from the point is labeled x, and the vertical distance from the tree across to the opposite bank is labeled y. The angle between the horizontal lower bank and a line segment connecting the point and the tree is labeled θ.arrow_forward
- Physics for Scientists and Engineers: Foundations...PhysicsISBN:9781133939146Author:Katz, Debora M.Publisher:Cengage LearningPrinciples of Physics: A Calculus-Based TextPhysicsISBN:9781133104261Author:Raymond A. Serway, John W. JewettPublisher:Cengage Learning