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The expression for
g
on Earth and the acceleration due to gravity on the surface of the Moon is one-sixth that of acceleration due to gravity on Earth.
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Answer to Problem 3AYK
Explanation of Solution
The expression for force of gravity on Earth according to Universal law of Gravitation is,
Here,
The expression for force of gravity or weight on Earth is,
Here,
The expression for acceleration due to gravity can be obtained by equating the two forces as both are gravitational forces acting on the object on Earth.
The expression for acceleration due to gravity or
Let
The value of
Substitute
The expression for acceleration due to gravity on moon is,
Here,
Substitute
The expression for the ratio of acceleration due to gravity on Moon and Earth is,
Substitute
Therefore, acceleration due to gravity on the surface of the Moon is
Conclusion:
Therefore, the expression for
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Chapter 3 Solutions
An Introduction to Physical Science
- Your answer is partially correct. Two small objects, A and B, are fixed in place and separated by 2.98 cm in a vacuum. Object A has a charge of +0.776 μC, and object B has a charge of -0.776 μC. How many electrons must be removed from A and put onto B to make the electrostatic force that acts on each object an attractive force whose magnitude is 12.4 N? e (mea is the es a co le E o ussian Number Tevtheel ed Media ! Units No units → answe Tr2Earrow_forward4 Problem 4) A particle is being pushed up a smooth slot by a rod. At the instant when 0 = rad, the angular speed of the arm is ė = 1 rad/sec, and the angular acceleration is = 2 rad/sec². What is the net force acting on the 1 kg particle at this instant? Express your answer as a vector in cylindrical coordinates. Hint: You can express the radial coordinate as a function of the angle by observing a right triangle. (20 pts) Ꮎ 2 m Figure 3: Particle pushed by rod along vertical path.arrow_forward4 Problem 4) A particle is being pushed up a smooth slot by a rod. At the instant when 0 = rad, the angular speed of the arm is ė = 1 rad/sec, and the angular acceleration is = 2 rad/sec². What is the net force acting on the 1 kg particle at this instant? Express your answer as a vector in cylindrical coordinates. Hint: You can express the radial coordinate as a function of the angle by observing a right triangle. (20 pts) Ꮎ 2 m Figure 3: Particle pushed by rod along vertical path.arrow_forward
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