MASTERPHYS:KNIGHT'S PHYSICS ACCESS+WKB
4th Edition
ISBN: 9780135245033
Author: Knight
Publisher: PEARSON
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Chapter 3, Problem 39EAP
Tom is climbing a 3.0-m-long ladder that leans against a vertical wall, contacting the wall 2.5 m above the ground. His weight of 680 N is a vector pointing vertically downward. (Weight is measured in newtons, abbreviated N.) What are the components of Tom’s weight parallel and perpendicular to the ladder?
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Vector F1 = 625 N makes an angle of 270 degrees when rotated counterclockwise from the +x axis. Vector F2 = 875 N makes a 120 degree angle from Vector F1 when rotated counterclockwise. What is the direction of the vector needed to balance the two forces?
Two forces act on an object. The first force has a magnitude of 17.0 N17.0 N and is oriented 68.0°68.0° counterclockwise from the +?+x‑axis, whereas the second force has ?x‑ and ?y‑components (−21.0 N,12.5 N).(−21.0 N,12.5 N). Express the magnitude and direction of the net force.
magnitude:
NN
direction:
°° counterclockwise from the +?+x‑axis
Two forces of F₁ = 112
√2
N and F₂ = 388
√2
What is the resultant force in terms of the force vectors F₁ and F2?
What is the magnitude of an equal and opposite force, F3, which balances the first two forces?
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Given your observations from parts a and b, if working with vectors in 3 dimensions (i, j, k); what will the normalizing term n be for
(i- j+ k)
(i − j+ k)
the two vectors F₁ = C₁
N and F₂ = 0₂
N.
√T
| Fren |
Given the normalizing term n found in the previous part in 3 dimensions (i, j, k); what will the magnitude of the resultant vector
be in terms of the constants c₁ and ₂.
(i − j+ k)
(i- j+k)
The vectors in question are F₁:
N and F₂ = 0₂
√√T
√π
F3 =
= C1
N act on an object.
Chapter 3 Solutions
MASTERPHYS:KNIGHT'S PHYSICS ACCESS+WKB
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